EBK ENHANCED DISCOVERING COMPUTERS & MI
1st Edition
ISBN: 9780100606920
Author: Vermaat
Publisher: YUZU
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Question
Chapter 8, Problem 3.2E
Program Plan Intro
Cloud storage:
- The term cloud can be defined as the process that led the computers resources to be accessed anytime anywhere over the internet.
- Users can store their data into the cloud.
- Examples of cloud storage are Dropbox, Xdrive, and so on.
Explanation of Solution
Free and paid online services:
All the mentioned cloud services provide free online storage space. If the user requires extra space to store data, then the user can upgrade the cloud account to get additional storage space.
- OneDrive – It is a free online storage. Here, the user can upgrade the account to get additional storage space. The user should pay 123 rupees every month for 50 GB...
Explanation of Solution
Storage space provided by online services:
- OneDrive – The personal storage space offered by this service is 5GB...
Explanation of Solution
Obtaining more storage space:
- OneDrive – The user can upgrade the account to get additional storage space. The user should pay 123 rupees every month for 50 GB...
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 8 Solutions
EBK ENHANCED DISCOVERING COMPUTERS & MI
Ch. 8 - Prob. 1SGCh. 8 - Prob. 2SGCh. 8 - Prob. 3SGCh. 8 - Prob. 4SGCh. 8 - Prob. 5SGCh. 8 - Prob. 6SGCh. 8 - Prob. 7SGCh. 8 - Prob. 8SGCh. 8 - Prob. 9SGCh. 8 - Prob. 10SG
Ch. 8 - Prob. 11SGCh. 8 - Prob. 12SGCh. 8 - Prob. 13SGCh. 8 - Prob. 14SGCh. 8 - Prob. 15SGCh. 8 - Prob. 16SGCh. 8 - Prob. 17SGCh. 8 - Prob. 18SGCh. 8 - Prob. 19SGCh. 8 - Prob. 20SGCh. 8 - Prob. 21SGCh. 8 - Prob. 22SGCh. 8 - Prob. 23SGCh. 8 - Prob. 24SGCh. 8 - Prob. 25SGCh. 8 - Prob. 26SGCh. 8 - Prob. 27SGCh. 8 - Prob. 28SGCh. 8 - Prob. 29SGCh. 8 - Prob. 30SGCh. 8 - Prob. 31SGCh. 8 - Prob. 32SGCh. 8 - Prob. 33SGCh. 8 - Prob. 34SGCh. 8 - Prob. 35SGCh. 8 - Prob. 36SGCh. 8 - Prob. 37SGCh. 8 - Prob. 38SGCh. 8 - Prob. 39SGCh. 8 - Prob. 40SGCh. 8 - Prob. 41SGCh. 8 - Prob. 42SGCh. 8 - Prob. 43SGCh. 8 - Prob. 44SGCh. 8 - Prob. 45SGCh. 8 - Prob. 46SGCh. 8 - Prob. 47SGCh. 8 - Prob. 1TFCh. 8 - Prob. 2TFCh. 8 - Prob. 3TFCh. 8 - Prob. 4TFCh. 8 - Prob. 5TFCh. 8 - Prob. 6TFCh. 8 - Prob. 7TFCh. 8 - Prob. 8TFCh. 8 - Prob. 9TFCh. 8 - Prob. 10TFCh. 8 - Prob. 11TFCh. 8 - Prob. 12TFCh. 8 - Prob. 1MCCh. 8 - Prob. 2MCCh. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MCCh. 8 - Prob. 6MCCh. 8 - Prob. 7MCCh. 8 - Prob. 8MCCh. 8 - Prob. 1MCh. 8 - Prob. 2MCh. 8 - Prob. 3MCh. 8 - Prob. 4MCh. 8 - Prob. 5MCh. 8 - Prob. 6MCh. 8 - Prob. 7MCh. 8 - Prob. 8MCh. 8 - Prob. 9MCh. 8 - Prob. 10MCh. 8 - Prob. 2CTCh. 8 - Prob. 3CTCh. 8 - Prob. 4CTCh. 8 - Prob. 5CTCh. 8 - Prob. 6CTCh. 8 - Prob. 7CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Prob. 10CTCh. 8 - Prob. 11CTCh. 8 - Prob. 12CTCh. 8 - Prob. 13CTCh. 8 - Prob. 14CTCh. 8 - Prob. 15CTCh. 8 - Prob. 16CTCh. 8 - Prob. 17CTCh. 8 - Prob. 18CTCh. 8 - Prob. 19CTCh. 8 - Prob. 20CTCh. 8 - Prob. 21CTCh. 8 - Prob. 22CTCh. 8 - Prob. 23CTCh. 8 - Prob. 24CTCh. 8 - Prob. 25CTCh. 8 - Prob. 26CTCh. 8 - Prob. 27CTCh. 8 - Prob. 1PSCh. 8 - Prob. 2PSCh. 8 - Prob. 3PSCh. 8 - Prob. 4PSCh. 8 - Prob. 5PSCh. 8 - Prob. 8PSCh. 8 - Prob. 9PSCh. 8 - Prob. 10PSCh. 8 - Prob. 11PSCh. 8 - Prob. 1.1ECh. 8 - Prob. 1.2ECh. 8 - Prob. 1.3ECh. 8 - Prob. 2.1ECh. 8 - Prob. 2.2ECh. 8 - Prob. 2.3ECh. 8 - Prob. 3.1ECh. 8 - Prob. 3.2ECh. 8 - Prob. 3.3ECh. 8 - Prob. 4.1ECh. 8 - Prob. 4.2ECh. 8 - Prob. 4.3ECh. 8 - Prob. 2IRCh. 8 - Prob. 3IR
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