(a) Interpretation: The number of molecules in 0 .150 g of carbon monoxide is to be calculated. Concept introduction: One mole of every gas occupies the same volume at STP. This value is equal to 22 .4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022 × 10 23 and this value is known as the Avogadro’s number .

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Answer 1

Question

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³

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34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Answer 2

Question

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

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Answer 3

Question

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

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Answer 4

Question

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

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Answer 5

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Answer 6

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Answer 7

Chapter 8, Problem 31E

Interpretation Introduction

(a)

Interpretation:

The number of molecules in 0.150 g of carbon monoxide is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The number of molecules in 100.0 mL of hydrogen is to be calculated.

Concept introduction:

One mole of every gas occupies the same volume at STP. This value is equal to 22.4 L and is known as the molar volume of the gas. The number of particles present in 1 mol of any gas is equal to 6.022×1023 and this value is known as the Avogadro’s number.

Answer 10

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Answer 12

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Answer 13

Ch. 8 - Prob. 1CE Ch. 8 - Prob. 2CE Ch. 8 - Prob. 3CE Ch. 8 - Prob. 4CE Ch. 8 - Prob. 5CE Ch. 8 - Prob. 6CE Ch. 8 - Prob. 7CE Ch. 8 - Prob. 8CE Ch. 8 - Prob. 9CE Ch. 8 - Prob. 10CE

Solution Summary: The author explains how the molar mass of carbon monoxide is calculated by the formula given below.

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