Explanation Given info : The force of gravity acting on the lower leg is 30.0 N , the force of gravity acting on the foot is 12.5 N , the angle of extended leg with the vertical is 40.0 ° , and the angle of tension with tibia is 25.0 ° . Explanation : The following figure shows the tension in the tendon. Assume a coordinate system in which, the x axis of the coordinate is parallel to the tibia and the y axis of the coordinate is perpendicular to it. The sum of torques acting on it is ∑ τ = 0 = − ( d / 2 ) w y − d F y + ( d / 5 ) T y and this expression is written as − ( d / 2 ) w sin θ − d ( F sin θ ) + ( d / 5 ) T sin θ ' = 0 . The formula for the tension in the tendon is, T = 5 ( w 2 + F ) sin θ sin θ ' w is the force of gravity on the lower leg

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Chapter 8, Problem 29P

To determine

The tension in the tendon when it is at an angle of 25.0° with tibia.

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The tension in the tendon when it is at an angle of 25.0 ° with tibia.

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The tension in the tendon when it is at an angle of 25.0° with tibia.

Chapter 8 Solutions