Kick Back, Inc., is producing a new hammock. For the first year, the fixed costs for setting up production are $44,000. The variable costs for producing each hammock are $25. The revenue from each hammock is $80. Find the following. a. The total cost C ( x ) of producing x hammocks b. The total revenue R ( x ) from the sale of x hammocks c. The total profit P ( x ) from the production and sale of x hammocks d. The profit or loss from the production and sale of 300 hammocks; of 900 hammocks e. The break-even point
Kick Back, Inc., is producing a new hammock. For the first year, the fixed costs for setting up production are $44,000. The variable costs for producing each hammock are $25. The revenue from each hammock is $80. Find the following. a. The total cost C ( x ) of producing x hammocks b. The total revenue R ( x ) from the sale of x hammocks c. The total profit P ( x ) from the production and sale of x hammocks d. The profit or loss from the production and sale of 300 hammocks; of 900 hammocks e. The break-even point
Solution Summary: The author calculates the cost function C(x) for the production of x hammock.
Kick Back, Inc., is producing a new hammock. For the first year, the fixed costs for setting up production are $44,000. The variable costs for producing each hammock are $25. The revenue from each hammock is $80. Find the following.
a. The total cost
C
(
x
)
of producing x hammocks
b. The total revenue
R
(
x
)
from the sale of x hammocks
c. The total profit
P
(
x
)
from the production and sale of x hammocks
d. The profit or loss from the production and sale of 300 hammocks; of 900 hammocks
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
Chapter 8 Solutions
Pearson eText Elementary and Intermediate Algebra: Concepts and Applications -- Instant Access (Pearson+)
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