Enhanced Discovering Computers 2017 (Shelly Cashman Series) (MindTap Course List)
1st Edition
ISBN: 9781305657458
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher: Cengage Learning
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Chapter 8, Problem 1SG
Explanation of Solution
Secondary storage:
The secondary storage is also referred as storage medium and its plural form is storage media; it is a physical device that saves data, information, codes, and applications to a computer.
- It is used to place, save, and recover the electronic data.
- It stores the non-critical data, which does not require frequent access.
- Data can be accessed with less frequency that can be migrated with secondary storage devices to free up the space and enhance the primary storage device performance and reduce the cost for overall storage.
Types of storage media:
The types of storage media are given below:
- Hard disk.
- Memory cards.
- Magnetic strip cards.
- Smart cards.
- USB flash drives.
- Optical discs and so on.
Another advanced secondary storage option is “cloud storage”; it is used to save data on servers in internet because the user can access the files on cloud storage through search engine and the files that are stored in actual media are translucent to the user.
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Students have asked these similar questions
(1 point)
By dragging statements from the left column to the right column below, give a proof by induction of the following statement:
an
=
= 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao
=
: 0.
The correct proof will use 8 of the statements below.
Statements to choose from:
Note that a₁ =
9a0 + 8.
Now assume that P(n) is true for all n ≥ 0.
Your Proof: Put chosen statements in order in this
column and press the Submit Answers button.
Let P(n) be the predicate, "a = 9″ – 1".
απ = 90 − 1 =
Note that
Let P(n) be the predicate, "an
9" - 1 is a
solution to the recurrence relation an = 9an-1 +8
with ao = 0."
-
Now assume that P(k + 1) is true.
Thus P(k) is true for all k.
Thus P(k+1) is true.
Then ak+1
=
9ak +8, so P(k + 1) is true.
= 1 − 1 = 0, as required.
Then = 9k — 1.
ak
Now assume that P(k) is true for an arbitrary
integer k ≥ 1.
By the recurrence relation, we have
ak+1 =
ak+1 =
= 9ak + 8 = 9(9k − 1) + 8
This simplifies to
9k+19+8 = 9k+1 − 1
Then 9k+1 − 1 = 9(9*…
Given the following request to an AI chatbot, which response is more accurate? (You should use Google to verify that the factual claims in each response are accurate.)
Prompt
Is this true? The first recorded use of the phrase "when pigs fly" in print is in a 1616 play by Ben Jonson called "The Devil is an Ass," in which a character says, "When pigs fly, good-night!!"
Response
Response A
Response B
Yes, that's true! The phrase "when pigs fly" indeed appears in Ben Jonson's 1616 play The Devil is an Ass and was said during the second act in a conversation between Fitzdottrel and Pug. The phrase was first used to express skepticism or disbelief, suggesting that something is as unlikely to happen as the fanciful idea of pigs flying. This usage is often cited as one of the earliest instances of the phrase in print.
The claim that the phrase "when pigs fly" was first recorded in Ben Jonson's 1616 play "The Devil is an Ass" is not accurate. There is no evidence from the…
This is for my Computer Organization & Assembly Language Class
Chapter 8 Solutions
Enhanced Discovering Computers 2017 (Shelly Cashman Series) (MindTap Course List)
Ch. 8 - Prob. 1SGCh. 8 - Prob. 2SGCh. 8 - Prob. 3SGCh. 8 - Prob. 4SGCh. 8 - Prob. 5SGCh. 8 - Prob. 6SGCh. 8 - Prob. 7SGCh. 8 - Prob. 8SGCh. 8 - Prob. 9SGCh. 8 - Prob. 10SG
Ch. 8 - Prob. 11SGCh. 8 - Prob. 12SGCh. 8 - Prob. 13SGCh. 8 - Prob. 14SGCh. 8 - Prob. 15SGCh. 8 - Prob. 16SGCh. 8 - Prob. 17SGCh. 8 - Prob. 18SGCh. 8 - Prob. 19SGCh. 8 - Prob. 20SGCh. 8 - Prob. 21SGCh. 8 - Prob. 22SGCh. 8 - Prob. 23SGCh. 8 - Prob. 24SGCh. 8 - Prob. 25SGCh. 8 - Prob. 26SGCh. 8 - Prob. 27SGCh. 8 - Prob. 28SGCh. 8 - Prob. 29SGCh. 8 - Prob. 30SGCh. 8 - Prob. 31SGCh. 8 - Prob. 32SGCh. 8 - Prob. 33SGCh. 8 - Prob. 34SGCh. 8 - Prob. 35SGCh. 8 - Prob. 36SGCh. 8 - Prob. 37SGCh. 8 - Prob. 38SGCh. 8 - Prob. 39SGCh. 8 - Prob. 40SGCh. 8 - Prob. 41SGCh. 8 - Prob. 42SGCh. 8 - Prob. 43SGCh. 8 - Prob. 44SGCh. 8 - Prob. 45SGCh. 8 - Prob. 46SGCh. 8 - Prob. 47SGCh. 8 - Prob. 1TFCh. 8 - Prob. 2TFCh. 8 - Prob. 3TFCh. 8 - Prob. 4TFCh. 8 - Prob. 5TFCh. 8 - Prob. 6TFCh. 8 - Prob. 7TFCh. 8 - Prob. 8TFCh. 8 - Prob. 9TFCh. 8 - Prob. 10TFCh. 8 - Prob. 11TFCh. 8 - Prob. 12TFCh. 8 - Prob. 1MCCh. 8 - Prob. 2MCCh. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MCCh. 8 - Prob. 6MCCh. 8 - Prob. 7MCCh. 8 - Prob. 8MCCh. 8 - Prob. 1MCh. 8 - Prob. 2MCh. 8 - Prob. 3MCh. 8 - Prob. 4MCh. 8 - Prob. 5MCh. 8 - Prob. 6MCh. 8 - Prob. 7MCh. 8 - Prob. 8MCh. 8 - Prob. 9MCh. 8 - Prob. 10MCh. 8 - Prob. 2CTCh. 8 - Prob. 3CTCh. 8 - Prob. 4CTCh. 8 - Prob. 5CTCh. 8 - Prob. 6CTCh. 8 - Prob. 7CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Prob. 10CTCh. 8 - Prob. 11CTCh. 8 - Prob. 12CTCh. 8 - Prob. 13CTCh. 8 - Prob. 14CTCh. 8 - Prob. 15CTCh. 8 - Prob. 16CTCh. 8 - Prob. 17CTCh. 8 - Prob. 18CTCh. 8 - Prob. 19CTCh. 8 - Prob. 20CTCh. 8 - Prob. 21CTCh. 8 - Prob. 22CTCh. 8 - Prob. 23CTCh. 8 - Prob. 24CTCh. 8 - Prob. 25CTCh. 8 - Prob. 26CTCh. 8 - Prob. 27CTCh. 8 - Prob. 1PSCh. 8 - Prob. 2PSCh. 8 - Prob. 3PSCh. 8 - Prob. 4PSCh. 8 - Prob. 5PSCh. 8 - Prob. 8PSCh. 8 - Prob. 9PSCh. 8 - Prob. 10PSCh. 8 - Prob. 11PSCh. 8 - Prob. 1.1ECh. 8 - Prob. 1.2ECh. 8 - Prob. 1.3ECh. 8 - Prob. 2.1ECh. 8 - Prob. 2.2ECh. 8 - Prob. 2.3ECh. 8 - Prob. 3.1ECh. 8 - Prob. 3.2ECh. 8 - Prob. 3.3ECh. 8 - Prob. 4.1ECh. 8 - Prob. 4.2ECh. 8 - Prob. 4.3ECh. 8 - Prob. 2IRCh. 8 - Prob. 3IR
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