Starting Out with C++ from Control Structures to Objects, Student Value Edition (9th Edition)
9th Edition
ISBN: 9780134443829
Author: Tony Gaddis
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 8, Problem 1RQE
Explanation of Solution
Linear search:
- Linear search or sequential search is the process of searching for a particular element that is present in the array one by one till the last element in the search element is found.
- The search uses a loop that iterates from the beginning till the last element to find the search element.
- The search continues for all the elements present in the array until the last element.
- The search of the target element is made after comparing it with each and every element that is present in the array.
- The search process continues until the target value or search value is found.
- If the search element is not found, the search gets returned unsuccessfully.
Number of comparisons in linear search:
To search the target element that is present in the array, the search element is compared with the number of elements present in the array. Even if the array contains 500 elements, the search process continues 500 times if the search element is present at the end of the array.
Maximum number of comparison = N
Average number of the comparison = N/2
Therefore, linear search is called sequential search because the search element is found by comparing each element present in the array using a loop one after the other, until the search element is found.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Why is Linux popular? What would make someone choose a Linux OS over others? What makes a server? How is a server different from a workstation? What considerations do you have to keep in mind when choosing between physical, hybrid, or virtual server and what are the reasons to choose a virtual installation over the other options?
Objective you will:
1. Implement a Binary Search Tree (BST) from scratch, including the Big Five (Rule of Five)
2. Implement the TreeSort algorithm using a in-order traversal to store sorted elements in a vector.
3. Compare the performance of TreeSort with C++'s std::sort on large datasets.
Part 1: Understanding TreeSort How TreeSort Works TreeSort is a comparison-based sorting algorithm that leverages a Binary Search Tree (BST):
1. Insert all elements into a BST (logically sorting them).
2. Traverse the BST in-order to extract elements in sorted order.
3. Store the sorted elements in a vector.
Time Complexity
Operation Average Case Worst Case (Unbalanced Tree)Insertion 0(1log n) 0 (n)Traversal (Pre-order) 0(n) 0 (n)Overall Complexity 0(n log n) 0(n^2) (degenerated tree)
Note: To improve performance, you could use a…
I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
Chapter 8 Solutions
Starting Out with C++ from Control Structures to Objects, Student Value Edition (9th Edition)
Ch. 8.2 - Prob. 8.1CPCh. 8.2 - Prob. 8.2CPCh. 8.2 - Prob. 8.3CPCh. 8.2 - Prob. 8.4CPCh. 8 - Prob. 1RQECh. 8 - If a linear search function is searching for a...Ch. 8 - Prob. 3RQECh. 8 - A binary search function is searching for a value...Ch. 8 - What is the maximum number of comparisons that a...Ch. 8 - Prob. 6RQE
Ch. 8 - Why is the selection sort more efficient than the...Ch. 8 - Prob. 8RQECh. 8 - The __________ search algorithm repeatedly divides...Ch. 8 - Prob. 10RQECh. 8 - The ____________ search algorithm requires that...Ch. 8 - If an array is sorted in ______________ order, the...Ch. 8 - If an array is sorted in _____________ order, the...Ch. 8 - Prob. 14RQECh. 8 - Prob. 15RQECh. 8 - Prob. 16RQECh. 8 - T F The maximum number of comparisons performed by...Ch. 8 - Prob. 18RQECh. 8 - Charge Account Validation Write a program that...Ch. 8 - Lottery Winners A lottery ticket buyer purchases...Ch. 8 - Lottery Winners Modification Modify the program...Ch. 8 - Charge Account Validation Modification Modify the...Ch. 8 - Rainfall Statistics Modification Modify the...Ch. 8 - String Selection Sort Modify the selectionSort...Ch. 8 - Binary String Search Modify the binarySearch...Ch. 8 - Search Benchmarks Write a program that has an...Ch. 8 - Sorting Benchmarks Write a program that uses two...Ch. 8 - Sorting Orders Write a program that uses two...Ch. 8 - Using FilesString Selection Sort Modification...
Knowledge Booster
Similar questions
- My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardI would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).arrow_forwardmap the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forward
- What is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardTask 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forward
- Can you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forwardCHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forward
- HELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forwardusing r languagearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
New Perspectives on HTML5, CSS3, and JavaScriptComputer ScienceISBN:9781305503922Author:Patrick M. CareyPublisher:Cengage Learning
EBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT
C++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning
Programming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:Cengage
Systems ArchitectureComputer ScienceISBN:9781305080195Author:Stephen D. BurdPublisher:Cengage Learning
C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr
New Perspectives on HTML5, CSS3, and JavaScript
Computer Science
ISBN:9781305503922
Author:Patrick M. Carey
Publisher:Cengage Learning
EBK JAVA PROGRAMMING
Computer Science
ISBN:9781337671385
Author:FARRELL
Publisher:CENGAGE LEARNING - CONSIGNMENT
C++ Programming: From Problem Analysis to Program...
Computer Science
ISBN:9781337102087
Author:D. S. Malik
Publisher:Cengage Learning
Programming Logic & Design Comprehensive
Computer Science
ISBN:9781337669405
Author:FARRELL
Publisher:Cengage
Systems Architecture
Computer Science
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Cengage Learning
C++ for Engineers and Scientists
Computer Science
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Course Technology Ptr