Dihydrogen monosulfide reacts with sulfur dioxide according to the balanced equation: 2 H 2 S ( g ) + SO 2 ( g ) → 3 S ( s ) + 2 H 2 O ( g ) If the first figure represents the amount of SO 2 available to react, which figure best represents the amount of H 2 S required to completely react with all of the SO 2 ?
Dihydrogen monosulfide reacts with sulfur dioxide according to the balanced equation: 2 H 2 S ( g ) + SO 2 ( g ) → 3 S ( s ) + 2 H 2 O ( g ) If the first figure represents the amount of SO 2 available to react, which figure best represents the amount of H 2 S required to completely react with all of the SO 2 ?
Solution Summary: The author explains the stoichiometric mole-mole relationships between the reactants.
It is not unexpected that the methoxyl substituent on a cyclohexane ring
prefers to adopt the equatorial conformation.
OMe
H
A G₂ = +0.6 kcal/mol
OMe
What is unexpected is that the closely related 2-methoxytetrahydropyran
prefers the axial conformation:
H
H
OMe
OMe
A Gp=-0.6 kcal/mol
Methoxy: CH3O group
Please be specific and clearly write the reason why this is observed. This effect that provides
stabilization of the axial OCH 3 group in this molecule is called the anomeric effect. [Recall in the way of
example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO
interacting with anti-bonding MO...]
206 Pb
82
Express your answers as integers. Enter your answers separated by a comma.
▸ View Available Hint(s)
VAΣ
ΜΕ ΑΣΦ
Np, N₁ = 82,126
Submit
Previous Answers
?
protons, neutrons
Please draw the inverted chair forms of the products for the two equilibrium reactions
shown below. Circle the equilibrium reaction that would have a AG = 0, i.e., the relative energy of
the reactant (to the left of the equilibrium arrows) equals the relative energy of the product? [No
requirement to show or do calculations.]
CH3
CH3
HH
CH3
1
-CH3
Chapter 8 Solutions
Introductory Chemistry Plus MasteringChemistry with eText - Access Card Package (5th Edition) (New Chemistry Titles from Niva Tro)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell