MATERIALS SCIENCE+ENGINEERING:WILEY PLUS
10th Edition
ISBN: 9781119815242
Author: Callister
Publisher: WILEY
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Chapter 8, Problem 18QAP
To determine
The minimum allowable bar diameter to ensure that fatigue failure will not occur.
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Design a self-biased JFET circuit (Fig. 6) assuming VGS(0) = -1.3 and ipss=
20 mA. We require a VGS = -0.7. Assume a supply voltage of 15 volts. Draw the
load line for this circuit using Fig. 4b once you have selected the appropriate values
for the components. Does the load line intersect the VGS = -0.7 volt line at the
computed in point?
RD.
RG
Rs
12
20nA
GS = -1.3
VGS
10nA
Fig. 6. Circuit for Examples 2 &3.
50
100
150
200
□ ID(J1)
UDS
Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of
0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3,
respectively.
Introduction: Orifice and Free Flow Jet in Applied Fluid Mechanics' I need to introduction only for answer
Chapter 8 Solutions
MATERIALS SCIENCE+ENGINEERING:WILEY PLUS
Ch. 8 - Prob. 1QAPCh. 8 - Prob. 2QAPCh. 8 - Prob. 3QAPCh. 8 - Prob. 4QAPCh. 8 - Prob. 5QAPCh. 8 - Prob. 6QAPCh. 8 - Prob. 7QAPCh. 8 - Prob. 8QAPCh. 8 - Prob. 9QAPCh. 8 - Prob. 10QAP
Ch. 8 - Prob. 11QAPCh. 8 - Prob. 12QAPCh. 8 - Prob. 13QAPCh. 8 - Prob. 14QAPCh. 8 - Prob. 15QAPCh. 8 - Prob. 16QAPCh. 8 - Prob. 17QAPCh. 8 - Prob. 18QAPCh. 8 - Prob. 19QAPCh. 8 - Prob. 20QAPCh. 8 - Prob. 21QAPCh. 8 - Prob. 22QAPCh. 8 - Prob. 23QAPCh. 8 - Prob. 24QAPCh. 8 - Prob. 25QAPCh. 8 - Prob. 26QAPCh. 8 - Prob. 27QAPCh. 8 - Prob. 28QAPCh. 8 - Prob. 29QAPCh. 8 - Prob. 30QAPCh. 8 - Prob. 31QAPCh. 8 - Prob. 32QAPCh. 8 - Prob. 33QAPCh. 8 - Prob. 34QAPCh. 8 - Prob. 35QAPCh. 8 - Prob. 36QAPCh. 8 - Prob. 37QAPCh. 8 - Prob. 38QAPCh. 8 - Prob. 40QAPCh. 8 - Prob. 41QAPCh. 8 - Prob. 42QAPCh. 8 - Prob. 43QAPCh. 8 - Prob. 44QAPCh. 8 - Prob. 1DPCh. 8 - Prob. 2DPCh. 8 - Prob. 3DPCh. 8 - Prob. 4DPCh. 8 - Prob. 5DPCh. 8 - Prob. 6DPCh. 8 - Prob. 7DPCh. 8 - Prob. 8DPCh. 8 - Prob. 1SSPCh. 8 - Prob. 2SSPCh. 8 - Prob. 1FEQPCh. 8 - Prob. 2FEQPCh. 8 - Prob. 3FEQPCh. 8 - Prob. 4FEQP
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- Find the operating point and the load line of a voltage-divider JFET biasing circuit using the following parameters: VGS(0) = -1.3 and Vcc = 15 volts. Assume ipss = 20 mA, RG₁ = RG2 = 10 kn, RD = 300, and Rs = 1 kn. Use Fig. 4b for the IV characteristic of the JFET. 20nA GS=-1.3 GS 10nA- 50 100 150 200 ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardDesign the JFET circuit for the largest in swing. Use the self-bias circuit shown in Fig. 6. Assume that VGS (0) = -1.3 and Vcc = 15 volts. Furthermore, assume that ipss = 20 mA. Using Fig. 4b, draw the load line and identify the Q point. Explain why this will allow the largest swing. Use ip = ipss (1- VGS VGS(0) to show what happens to i, and vps when you have a swing of 0.2 volts in vcs form its operating point (that is, change vas by ±0.2 volts and compute the corresponding iD and VDs). RD RG Rs 0 20nA GS=-1.3 VGS 12 10nA -0- Fig. 6. Circuit for Examples 2 &3. BA-C 50 100 150 200 □ ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardplease do the correct VI chrastaristics curve on excel. I am not sure if mine is correctarrow_forward
- please do the correct VI chrastaristics curve on excel. I am not sure if mine is correct. Note the two curves in the picture are for both but its two tries and i dont know which is correct, and probebly both are wrong SCR (Forward Bias Condition) NO VAA VG= 0V, IG=0 mA VG= 5V, IG=4.07mA VG= 10V, IG=9.05mA VAK (V) IAK(mA) VAK (V) IAK(mA) VAK (V) IAK(mA) 1 0 0 0 0 0 0 0 2 5 0.576 4.42 mA 0.576 4.42 mA 0.576 4.43 3 10 7.99 2 0.598 9.4 0.598 9.4 4 15 14.99 0.003 0.612 14.4 0.612 14.4 5 20 19.994 0.004 0.622 19.4 0.622 19.4 6 25 0.63 24.4 0.63 24.4 0.63 24.4 4 30 0.637 29.4 0.637 29.4 0.637 29.4 8 40 0.65 39.4 0.65 39.4 0.65 39.4 9 50 0.66 49.3 0.66 49.3 0.66 49.3 10 60 0.67 59.3 0.67 59.3 0.67 59.3 11 70 0.679 69.3 0.679 69.3 SCR (Reversed Bias…arrow_forwardI tried this problem and don't know what I did wrong or how else I could approach it can you please help me out?arrow_forwardI need to make a parallel version of this sequential code.arrow_forward
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