The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below: Age of householder ( years ) Number ( thousands ) 15 − 24 3395 25 − 34 13347 35 − 44 17546 45 − 54 18119 55 − 64 13462 65 + 12978

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Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Microsoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADO

The spread of an infectious disease is often modeled using the following autonomous differential equation: dI - - BI(N − I) − MI, dt where I is the number of infected people, N is the total size of the population being modeled, ẞ is a constant determining the rate of transmission, and μ is the rate at which people recover from infection. Close a) (5 points) Suppose ẞ = 0.01, N = 1000, and µ = 2. Find all equilibria. b) (5 points) For the equilbria in part a), determine whether each is stable or unstable. c) (3 points) Suppose ƒ(I) = d. Draw a phase plot of f against I. (You can use Wolfram Alpha or Desmos to plot the function, or draw the dt function by hand.) Identify the equilibria as stable or unstable in the graph. d) (2 points) Explain the biological meaning of these equilibria being stable or unstable.

Find the indefinite integral. Check Answer: 7x 4 + 1x dx

Answer 2

Question

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Answer 3

Question

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Answer 4

Question

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Answer 5

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

Answer 6

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

Answer 7

Chapter 8, Problem 13T

To determine

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

Answer 8

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Answer 9

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Ch. 8.1 - Determine whether the following experiments...Ch. 8.1 - Prob. 2CP Ch. 8.1 - Determine whether the following experiments...Ch. 8.1 - Prob. 4CP Ch. 8.1 - 1. Suppose a fair die is rolled 18 times. (a) What...Ch. 8.1 - 2. Suppose a fair coin is tossed 12 times. (a)...Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E

Solution Summary: The author calculates the mean and standard deviation of the ages of householders and the number in thousands.

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To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Chapter 8 Solutions

Solution Summary: The author calculates the mean and standard deviation of the ages of householders and the number in thousands.

Concept explainers

Videos

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below: Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978

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Chapter 8 Solutions

To calculate: The mean and standard deviation of the ages of the householders. The data for the class marks of ages of the householders and the number in thousands is tabulated below:

Age of householder(years)Number(thousands)15−24339525−341334735−441754645−541811955−641346265+12978