
a)
The mass flow rate of the steam.
a)

Explanation of Solution
Given:
The initial pressure of the steam
The initial temperature of the steam
The initial velocity
The final pressure of the steam
The final velocity
The power output of the turbine
The isentropic efficiency
Conclusion:
Refer the Table A-6, “superheated water table”, obtain the following properties at a pressure of
The initial enthalpy
The initial entropy
The entropy remains constant since the process is isentropic
Refer the Table A-6, “superheated water table”, obtain the following properties at a pressure of
The enthalpy at final state in isentropic process
Calculate the power output for the isentropic process.
Write the expression for the energy balance equation for closed system.
Here, rate of net energy transfer in to the control volume is
The rate of change in internal energy of the system is zero at steady state.
Substitute
Thus, the mass flow rate of the steam is
b)
The exit temperature of the steam.
b)

Explanation of Solution
Write the expression to calculate the mass flow rate of the steam.
Refer the Table A-6, “superheated water table”, obtain final entropy at pressure of
Refer the Table A-6, “Superheated water”, obtain the value of exit temperature
Show exit temperature and enthalpy values from the Table A-6.
Temperature | Enthalpy |
2675 | 100 |
2683.5 | ? |
2776.6 | 150 |
Write the formula of interpolation method of two variables.
Here, the variables denoted by x and y are exit temperature and enthalpy.
Substitute
The value of exit temperature
Thus, the exit temperature of the steam is
c)
The entropy generation in the turbine.
c)

Explanation of Solution
Calculate the entropy generation in the turbine
Thus, the entropy generation in the turbine is
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Chapter 8 Solutions
Fundamentals of Thermal-Fluid Sciences
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