Bundle: Enhanced Discovering Computers 2017, Loose-leaf Version + Illustrated Microsoft Office 365 & Office 2016: Introductory, Loose-leaf Version + ... 1 term (6 months) Printed Access Card
Bundle: Enhanced Discovering Computers 2017, Loose-leaf Version + Illustrated Microsoft Office 365 & Office 2016: Introductory, Loose-leaf Version + ... 1 term (6 months) Printed Access Card
1st Edition
ISBN: 9781337379960
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher: Cengage Learning
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Chapter 8, Problem 10PS

Explanation of Solution

 Reasons for the above problem:

 Some of the reasons for the above problem are as follows:

  • Too large files: If there are too many files in the uploaded folder then it will take more to upload which results in synchronization problem...

Explanation of Solution

 Steps taken to resolve the above problem:

 Steps taken to resolve the above issues are as follows:

  • Too large files: In this case, the user should wait until all the files get uploaded on the cloud...

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(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester!  Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!
(OnlineGDB) 1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}   What is the output of the program? Please explain why.

Chapter 8 Solutions

Bundle: Enhanced Discovering Computers 2017, Loose-leaf Version + Illustrated Microsoft Office 365 & Office 2016: Introductory, Loose-leaf Version + ... 1 term (6 months) Printed Access Card

Ch. 8 - Prob. 11SGCh. 8 - Prob. 12SGCh. 8 - Prob. 13SGCh. 8 - Prob. 14SGCh. 8 - Prob. 15SGCh. 8 - Prob. 16SGCh. 8 - Prob. 17SGCh. 8 - Prob. 18SGCh. 8 - Prob. 19SGCh. 8 - Prob. 20SGCh. 8 - Prob. 21SGCh. 8 - Prob. 22SGCh. 8 - Prob. 23SGCh. 8 - Prob. 24SGCh. 8 - Prob. 25SGCh. 8 - Prob. 26SGCh. 8 - Prob. 27SGCh. 8 - Prob. 28SGCh. 8 - Prob. 29SGCh. 8 - Prob. 30SGCh. 8 - Prob. 31SGCh. 8 - Prob. 32SGCh. 8 - Prob. 33SGCh. 8 - Prob. 34SGCh. 8 - Prob. 35SGCh. 8 - Prob. 36SGCh. 8 - Prob. 37SGCh. 8 - Prob. 38SGCh. 8 - Prob. 39SGCh. 8 - Prob. 40SGCh. 8 - Prob. 41SGCh. 8 - Prob. 42SGCh. 8 - Prob. 43SGCh. 8 - Prob. 44SGCh. 8 - Prob. 45SGCh. 8 - Prob. 46SGCh. 8 - Prob. 47SGCh. 8 - Prob. 1TFCh. 8 - Prob. 2TFCh. 8 - Prob. 3TFCh. 8 - Prob. 4TFCh. 8 - Prob. 5TFCh. 8 - Prob. 6TFCh. 8 - Prob. 7TFCh. 8 - Prob. 8TFCh. 8 - Prob. 9TFCh. 8 - Prob. 10TFCh. 8 - Prob. 11TFCh. 8 - Prob. 12TFCh. 8 - Prob. 1MCCh. 8 - Prob. 2MCCh. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MCCh. 8 - Prob. 6MCCh. 8 - Prob. 7MCCh. 8 - Prob. 8MCCh. 8 - Prob. 1MCh. 8 - Prob. 2MCh. 8 - Prob. 3MCh. 8 - Prob. 4MCh. 8 - Prob. 5MCh. 8 - Prob. 6MCh. 8 - Prob. 7MCh. 8 - Prob. 8MCh. 8 - Prob. 9MCh. 8 - Prob. 10MCh. 8 - Prob. 2CTCh. 8 - Prob. 3CTCh. 8 - Prob. 4CTCh. 8 - Prob. 5CTCh. 8 - Prob. 6CTCh. 8 - Prob. 7CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Prob. 10CTCh. 8 - Prob. 11CTCh. 8 - Prob. 12CTCh. 8 - Prob. 13CTCh. 8 - Prob. 14CTCh. 8 - Prob. 15CTCh. 8 - Prob. 16CTCh. 8 - Prob. 17CTCh. 8 - Prob. 18CTCh. 8 - Prob. 19CTCh. 8 - Prob. 20CTCh. 8 - Prob. 21CTCh. 8 - Prob. 22CTCh. 8 - Prob. 23CTCh. 8 - Prob. 24CTCh. 8 - Prob. 25CTCh. 8 - Prob. 26CTCh. 8 - Prob. 27CTCh. 8 - Prob. 1PSCh. 8 - Prob. 2PSCh. 8 - Prob. 3PSCh. 8 - Prob. 4PSCh. 8 - Prob. 5PSCh. 8 - Prob. 8PSCh. 8 - Prob. 9PSCh. 8 - Prob. 10PSCh. 8 - Prob. 11PSCh. 8 - Prob. 1.1ECh. 8 - Prob. 1.2ECh. 8 - Prob. 1.3ECh. 8 - Prob. 2.1ECh. 8 - Prob. 2.2ECh. 8 - Prob. 2.3ECh. 8 - Prob. 3.1ECh. 8 - Prob. 3.2ECh. 8 - Prob. 3.3ECh. 8 - Prob. 4.1ECh. 8 - Prob. 4.2ECh. 8 - Prob. 4.3ECh. 8 - Prob. 2IRCh. 8 - Prob. 3IR
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