EBK BIOLOGY:SCIENCE F/LIFE
6th Edition
ISBN: 9780134819167
Author: BELK
Publisher: PEARSON
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Chapter 8, Problem 10LTB
Summary Introduction
Introduction:
Sex-linked recessive disorders pass down in a family from X and Y sex chromosomes. In such disorders, if only one gene is abnormal, then the disease will not occur. The person carrying on one abnormal gene is the carrier of the disease. Mostly such disorders are X-linked traits.
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The chart below is showing 4 generations of a family that is affected by a hereditary disease.
a. Is the disorder being tracked dominant or recessive? How do you know?
b. There is only one possible genotype for person C. True or False?
c. What are the possible genotypes for person A?
d. What are the possible genotypes for person B?,
e. If two people with the same genotypes as person C's spouse and person A's
spouse had a child, what is the probability that the child will be affected by this genetic disorder?
(draw a Punnett square using the correct genotypes to help you).
% chance offspring will be affected
% chance offspring will not be affected
Which of the following must be true about the inheritance the trait depicted in the pedigree diagram below.
A. it is recessive
B. It is dominant
C. It is on the X chromosome
D. There is not enough information to determine the mechanism of inheritance
15. The following pedigree shows inheritance of Huntington's disease, a fatal genetic
disorder that causes neurodegeneration. Since signs and symptoms usually do not
appear until adulthood, many who are carriers may not realize their risk of passing on
the disease-causing allele. The following pedigree represents a family in which some
people are affected by Huntington's disease.
Reeessive Trit
er btmnt be
Mec
yplicalty
Hinhetee
Chapter 8 Solutions
EBK BIOLOGY:SCIENCE F/LIFE
Ch. 8 - What is the relationship between genotype and...Ch. 8 - Add labels to the figure that follows, which...Ch. 8 - Prob. 3LTBCh. 8 - Prob. 4LTBCh. 8 - Prob. 5LTBCh. 8 - Scientists have recently developed a process by...Ch. 8 - What is the physical basis for the independent...Ch. 8 - Prob. 8LTBCh. 8 - Prob. 9LTBCh. 8 - Prob. 10LTB
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A heterozygous individual is crossed with a homozygous recessive individual. a. Draw a Punnett square to represent this cross. b. What is the probability that an offspring will have a homozygous genotype? c. What is the probability that an offspring will have a dominant phenotype? d. What is the probability that three offspring will be produced that all carry the recessive allele but do not express the recessive phenotype?arrow_forwardTay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forwardColorblindness is inherited as an X-linked recessive trait while pattern baldness is controlled by an autosomal gene that is dominant in males but recessive in females. A colorblind man who is also homozygous for baldness has children with a woman who carries normal genes for both traits. What is the probability that any of their child will be: a. Colorblind, bald male b. Colorblind, normal-haired male c. Female with normal sight and baldarrow_forward
- a. Determine if the pedigree below can be for a trait that is X-linked traits. Write the genotype of each individual next to the symbol. b. Is it possible that this pedigree is for an X-linked recessive trait? c. What can you conclude about the children if both parents are affected with an X-linked recessive trait?arrow_forwardWhich of the following cannot be true about the inheritance the trait depicted in the pedigree diagram below? A. It is recessive B. It is dominant C. It is on the X chromosome D. There is not enough information to determine the mechanism of inheritancearrow_forwardWhat are the genotypes of the mother and father in the pedigree below? The pedigree shows albinism (an autosomal recessive trait). The shaded shapes represent albino individuals. a. mother - homozygous dominant; father - homozygous dominant b. mother - heterozygous; father - homozygous recessive c. mother - homozygous recessive; father - heterozygous d. mother - heterozygous; father - heterozygous e. mother - homozygous dominant; father - homozygous recessivearrow_forward
- A woman with a rare autosomal recessive disorder was told that it was unlikely that her children would have the disorderas her husband did not have it. However, her first child has the disorder. a. What is the most likely explanation? b. Diagram the cross between the woman and her husband using a Punnett square, give the genotypic ratio (GR) and phenotypic ratio (PR) from the Punnett square. c. Based on the Punnett square results, what is the chance that her next child will have the disorder?arrow_forwardIn humans, the genes for coloblindedness and hemophilia re both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles. a. If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this. b. If the man dies and the woman remarries to a colorblind man, draw a Punnet Square showing the type of children could be expected from hre second marriage. How many/what percentages of each could ne expectedarrow_forwardWebbed fingers is inherited as an X-linked disease An unaffected male marries an affected female. a. Draw a Punnett square of the possible offspring. b. List the phenotypes of the possible children c. Draw a pedigree that displays the inheritance in you Punnett squarearrow_forward
- Hemophilia is a disease inherited as a X-linked recessive trait while pattern baldness is controlled by an autosomal gene that is dominant in males and recessive in females. A hemophilic man who is also homozygous for baldness has children with a woman who carries normal genes for both traits. What is the probability that any of their child will be: a. Hemophilic, normal-haired male b. Hemophilic, bald male c Female with normal blood clotting and bald Note: Show how you derived your answers.arrow_forwardConsider a cross between a Brown furred dog and a Yellow furred dog. All the puppies born from these parents are yellow furred. Crossing the F1 yellow furred sons and F1 yellow furred daughters produces a 3:1 ratio of yellow furred dogs (3) to brown-furred dogs (1) in the F2 generation. True or False: this tells you that brown fur color in this dog species is inherited in an autosomal recessive manner. is it true or false?arrow_forwardA type of baldness is sex –limited such that the allele that causes it is dominant in men and recessive in women. Thus baldness is much more common in men than women even though the locus is on an autosome. How is the pattern of inheritance in this example different from X-linked inheritance of a recessive allele? Group of answer choices A. the trait can be passed from fathers to sons B. the trait can be passed from fathers to daughters C. the trait can be passed from mothers to sons D. the trait can be passed from mothers to daughtersarrow_forward
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