
Concept explainers
Interpretation:
The mechanism for each step in the pathway given for bio synthesizing epi-Aristolochene is to be shown using curved arrows. Further the steps that involve electrophilic addition(s) to the
Concept introduction:
While drawing curved arrows the head of the curved arrow starts from the nucleophilic source (either negatively charged or neutral) and ends in an electrophilic sink (either positively charged or neutral). The formation of a new bond should lead to the breaking of a bond that already exists as the octet rule cannot be violated.
In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of another reactant to yield a carbocation. One of the carbon in C=C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation formed can rearrange to give another more stable carbocation either by a hydride shift (shift of hydrogen atom with its electron pair) or by an alkyl shift (shift of an alkyl group with its electron pair) between neighboring carbons. In the last step the carbocation produced reacts with a negatively charged ion or eliminates a proton to give the product.
To show:
The mechanism for each step in the pathway given for bio synthesizing epi-aristolochene using curved arrows. Further to identify the steps that involve electrophilicaddition(s) to the alkene and that involve carbocation rearrangement(s).

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Chapter 7 Solutions
Organic Chemistry - With Access (Custom)
- Q5: Label each chiral carbon in the following molecules as R or S. Make sure the stereocenter to which each of your R/S assignments belong is perfectly clear to the grader. (8pts) R OCH 3 CI H S 2pts for each R/S HO R H !!! I OH CI HN CI R Harrow_forwardCalculate the proton and carbon chemical shifts for this structurearrow_forwardA. B. b. Now consider the two bicyclic molecules A. and B. Note that A. is a dianion and B. is a neutral molecule. One of these molecules is a highly reactive compound first characterized in frozen noble gas matrices, that self-reacts rapidly at temperatures above liquid nitrogen temperature. The other compound was isolated at room temperature in the early 1960s, and is a stable ligand used in organometallic chemistry. Which molecule is the more stable molecule, and why?arrow_forward
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- EBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT

