
Interpretation:
The carbocation intermediate has to be drawn and resonance structure has to be drawn for the carbocation.
Concept Introduction:
Unimolecular nucleophilic substitution reaction
- Loss of leaving group, where the loss of leaving group from the substrate gives a carbocation intermediate.
- Nucleophilic attack: A nucleophile attacks the carbocation intermediate to afford the product.
Leaving group: It is a fragment that leaves substrate with a pair of electrons via heterolytic bond cleavage.
Nucleophile: Donates pair of electrons to positively charged substrate resulting in the formation of
Resonance is an electron displacement effect for stabilizing a molecule through delocalization of bonding electrons in the pi orbital.
Delocalized electrons stabilize a compound. The extra stability gains from having delocalized electrons are called resonance stabilization or resonance energy.

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Chapter 7 Solutions
ORGANIC CHEMISTRY-PRINT COMPANION (LL)
- Indicate the reagent needed to go from cyclopentane-CH2-CHO to cyclopentane-CH2-CH=CH-C6H5.arrow_forwardesc Write the systematic name of each organic molecule: structure CH3 CH3-C=CH2 CH3-CH2-C-CH2-CH3 CH-CH3 CH3 ☐ ☐ ☐ CI-CH-CH=CH2 Explanation Check F1 F2 name 80 F3 F4 F5 F6 A 7 ! 2 # 3 4 % 5 6 & 7 Q W E R Y FT 2025 Mcarrow_forwardTwo reactants X and Z are required to convert the compound CH3-CH2-CH2Br to the compound CH3-CH2-CH=P(C6H5)3. State reactants X and Z.arrow_forward
- 2. Write a reasonable mechanism that converts the reactants into the products. Avoid issues A-U from the previous page. You can use any number of steps (it does not have to be a one-step mechanism). Do not use any other chemicals (solvents, acids, bases, etc.) in your mechanism. 2 2 H ΗΘarrow_forwardFor the following reaction, the partial pressures were determined for the reaction components as shownbelow. Is the reaction at equilibrium? If not, in which direction will it proceed?I2 (g) + Cl2 (g) ⇋ 2 ICl (g) Kp = 81.9 partial pressures: I2 = 0.114 atm; Cl2 = 0.102 atm; ICl = 0.355 atmarrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. H3O+ + Oarrow_forward
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- == Functional Groups Identifying and drawing hemiacetals and acetals In the drawing area below, create an acetal with 1 isopropoxy group, 1 hydroxyl group, and a total of 10 carbon atoms. Explanation Click and drag to start drawing a structure. Check G +arrow_forwardState the products (formulas) of the reaction of acetophenone with iodine and NaOH.arrow_forwardExplanation Check Draw the skeletal ("line") structure of 5-hydroxy-4-methyl-2-pentanone. Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cer ☐ : Carrow_forward
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