To verify: The given vector , x ( c ) = c 1 ( 1 2 ) t − 1 + c 2 ( 2 1 ) t 2 is the general solution of the homogeneous system of t x ′ = ( 3 − 2 2 − 2 ) x + ( − 2 t t 4 − 1 ) and hence solve the non-homogeneous system ( t > 0 ) .

Question

Want to see the full answer?

Answer 1

Question

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

12:25 AM Sun Dec 22 uestion 6- Week 8: QuX Assume that a company X + → C ezto.mheducation.com Week 8: Quiz i Saved 6 4 points Help Save & Exit Submit Assume that a company is considering purchasing a machine for $50,000 that will have a five-year useful life and a $5,000 salvage value. The machine will lower operating costs by $17,000 per year. The company's required rate of return is 15%. The net present value of this investment is closest to: Click here to view Exhibit 12B-1 and Exhibit 12B-2, to determine the appropriate discount factor(s) using the tables provided. 00:33:45 Multiple Choice О $6,984. $11,859. $22,919. ○ $9,469, Mc Graw Hill 2 100-

No chatgpt pls will upvote

7. [10 marks] Let G = (V,E) be a 3-connected graph. We prove that for every x, y, z Є V, there is a cycle in G on which x, y, and z all lie. (a) First prove that there are two internally disjoint xy-paths Po and P₁. (b) If z is on either Po or P₁, then combining Po and P₁ produces a cycle on which x, y, and z all lie. So assume that z is not on Po and not on P₁. Now prove that there are three paths Qo, Q1, and Q2 such that: ⚫each Qi starts at z; • each Qi ends at a vertex w; that is on Po or on P₁, where wo, w₁, and w₂ are distinct; the paths Qo, Q1, Q2 are disjoint from each other (except at the start vertex 2) and are disjoint from the paths Po and P₁ (except at the end vertices wo, W1, and w₂). (c) Use paths Po, P₁, Qo, Q1, and Q2 to prove that there is a cycle on which x, y, and z all lie. (To do this, notice that two of the w; must be on the same Pj.)

Answer 2

Question

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Answer 6

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Answer 7

Chapter 7.9, Problem 15P

To determine

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 7.1 - In each of Problems 1 through 4, transform the...Ch. 7.1 - Prob. 2P Ch. 7.1 - Prob. 3P Ch. 7.1 - In each of Problems 1 through 4, transform the...Ch. 7.1 - Prob. 5P Ch. 7.1 - In each of Problems 5 and 6, transform the given...Ch. 7.1 - Systems of first order equations can sometimes be...Ch. 7.1 - Prob. 8P Ch. 7.1 - Prob. 9P Ch. 7.1 - In each of Problems 8 through 12, proceed as in...

To verify: The given vector , x ( c ) = c 1 ( 1 2 ) t − 1 + c 2 ( 2 1 ) t 2 is the general solution of the homogeneous system of t x ′ = ( 3 − 2 2 − 2 ) x + ( − 2 t t 4 − 1 ) and hence solve the non-homogeneous system ( t > 0 ) .

Videos

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Want to see the full answer?

Chapter 7 Solutions

To verify: The given vector , x ( c ) = c 1 ( 1 2 ) t − 1 + c 2 ( 2 1 ) t 2 is the general solution of the homogeneous system of t x ′ = ( 3 − 2 2 − 2 ) x + ( − 2 t t 4 − 1 ) and hence solve the non-homogeneous system ( t &gt; 0 ) .

Videos

To verify: The given vector, x(c)=c1(12)t−1+c2(21)t2 is the general solution of the homogeneous system of tx′=(3−22−2)x+(−2tt4−1) and hence solve the non-homogeneous system (t>0).

Want to see the full answer?

Chapter 7 Solutions

To verify: The given vector , x ( c ) = c 1 ( 1 2 ) t − 1 + c 2 ( 2 1 ) t 2 is the general solution of the homogeneous system of t x ′ = ( 3 − 2 2 − 2 ) x + ( − 2 t t 4 − 1 ) and hence solve the non-homogeneous system ( t > 0 ) .