Fundamentals Of Chemical Engineering Thermodynamics
Fundamentals Of Chemical Engineering Thermodynamics
1st Edition
ISBN: 9781111580711
Author: Kevin D. Dahm, Donald P. Visco, Jr.
Publisher: CENGAGE L
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Chapter 7.7, Problem 20P
Interpretation Introduction

Interpretation:

The Coefficient of performance

Concept Introduction:

Write the expression for the difference in entropy using residuals.

S_2S_1=(S_2S_2ig)+(S_2igS_1ig)(S_1S_1ig)

Here, molar entropy at state 1 (liquid) and 2 (vapor) are S_1 and S_2, molar entropy at state 1 and 2 at inert gas are S_1ig and S_2ig respectively.

Write the ideal gas entropy change.

S_2igS_1ig=CP*ln(T2T1)Rln(P2P1)

Here, temperature and pressure at state 1 and 2 is T1,T2,P1,andP2, gas constant is R, and heat capacity at constant pressure for an ideal gas is CP*.

Write the van der Waals EOS.

P2=RT2V_2baV_22

Here, van der Waals parameter are a and b, molar volume at state 2 is V_2, and gas constant is R.

Write the expression for the residual entropy obtained from the van der Waals EOS.

S_2S_2ig=Rln(Z)+Rln(V_2bV_2)=Rln(P2V_2RT2)+Rln(V_2bV_2)

Here, compressibility factor is Z.

Write the residual molar enthalpy according to the van der Waals EOS.

H_R=RT(Z1)+T=T,V_=T=T,V_=V_[T(PT)V_P]dV_

Here, change in pressure with respect to change in temperature at constant molar volume is (PT)V_.

Write the change in molar enthalpy using residual properties across the compressor.

W˙S,revn˙=(H_2H_2ig)+(H_2igH_1ig)(H_1H_1ig)

Here, molar enthalpy at state 1 (liquid) and 2 (vapor) is H_1 and H_2, molar enthalpy at state 1 and 2 at inert gas is H_1ig and H_2ig respectively

Write the efficiency of the compressor.

η=W˙S,revn˙W˙S,actn˙W˙S,actn˙=W˙S,revn˙η   

Here, actual rate of work done on the shaft is W˙S,act, molar flow rate is n˙, and efficiency is η.

Write the energy balance on the entire refrigeration cycle.

0=Q˙Hn˙+Q˙Cn˙+W˙S,actn˙

Write the coefficient of performance.

COP=Q˙Cn˙W˙S,actn˙

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Chemical Engineering Use the psychrometric chart and demonstrate the linear interpolation method to obtain -0.52 KJ/KgDA.  This is the enthalpy deviation.   The exercise is uploaded below.
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