Bundle: Modern Business Statistics with Microsoft Office Excel, Loose-Leaf Version, 6th + MindTap Business Statistics, 2 terms (12 months) Printed Access Card
6th Edition
ISBN: 9781337589383
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 7.6, Problem 31E
a.
To determine
Find the sampling distribution of
b.
To determine
Find the probability that the sample proportion
c.
To determine
Find the probability that the sample proportion would be between 0.25 and 0.35.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Find the regression equation.
Find the equation of the regression line for the given data. Then construct a scatter plot of the data and draw the regression line. (The pair of variables have a significant correlation.) Then use the
regression equation to predict the value of y for each of the given x-values, if meaningful. The number of hours 6 students spent for a test and their scores on that test are shown below.
Hours spent studying, x
Test score, y
0
2
2
4
5
6
39
45
51
49
63
68
(a) x = 2 hours
(c) x = 12 hours
(b) x = 2.5 hours
(d) x 3.5 hours
y = x + (D
☐ x + (☐
(Round the slope to three decimal places as needed. Round the y-intercept to two decimal places as needed.)
Choose the correct graph below.
A.
B.
Test score
0
80-
0
Π
8
Test score
80-
0-
0
Hours studying
Hours studying
(a) Predict the value of y for x = 2. Choose the correct answer below.
A. 47.2
B. 49.5
C. 54.0
D. not meaningful
(b) Predict the value of y for x = 2.5. Choose the correct answer below.
A. 54.0
B. 49.5
C.…
In a survey of 2727 adults, 1463 say they have started paying bills online in the last year.
Construct a 99% confidence interval for the population proportion. Interpret the results.
A 99% confidence interval for the population proportion is
(Round to three decimal places as needed.)
Interpret your results. Choose the correct answer below.
(D).
A. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence
interval.
B. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence
interval.
○ C. The endpoints of the given confidence interval show that adults pay bills online 99% of the time.
A research center claims that at least 28% of adults in a certain country think that their taxes will be audited. In a random sample of 600 adults in that country in a recent year, 25% say they are
concerned that their taxes will be audited. At a = 0.10, is there enough evidence to reject the center's claim? Complete parts (a) through (d) below.
...
(a) Identify the claim and state Ho and Ha.
Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice.
(Type an integer or a decimal. Do not round.)
A. At least
B. Less than
% of adults in the country think that their taxes will be audited.
% of adults in the country think that their taxes will be audited.
C. The percentage of adults in the country who think that their taxes will be audited is not %.
D.
% of adults in the country think that their taxes will be audited.
Let p be the population proportion of successes, where a success is an adult in the country who thinks that…
Chapter 7 Solutions
Bundle: Modern Business Statistics with Microsoft Office Excel, Loose-Leaf Version, 6th + MindTap Business Statistics, 2 terms (12 months) Printed Access Card
Ch. 7.2 - Consider a finite population with five elements...Ch. 7.2 - Assume a finite population has 10 elements. Number...Ch. 7.2 - The 2012 American League consists of 14 baseball...Ch. 7.2 - The U.S. Golf Association has instituted a ban on...Ch. 7.2 - In this section we used a two-step procedure to...Ch. 7.2 - 10. Indicate which of the following situations...Ch. 7.3 - 11. The following data are from a simple random...Ch. 7.3 - Prob. 8ECh. 7.3 - Prob. 9ECh. 7.3 - 14. Morningstar publishes ratings data on 1208...
Ch. 7.3 - 15. The National Football League (NFL) polls fans...Ch. 7.3 - AARP Survey. In a sample of 426 U.S. adults age 50...Ch. 7.3 - 17. One of the questions in the Pew Internet &...Ch. 7.3 - In this section we showed how a simple random...Ch. 7.5 - 19. A population has a mean of 200 and a standard...Ch. 7.5 - Prob. 16ECh. 7.5 - 21. Suppose a random sample of size 50 is selected...Ch. 7.5 - Refer to the EAI sampling problem. Suppose a...Ch. 7.5 - In the EAI sampling problem (see Figure 7.8), we...Ch. 7.5 - 24. Barron’s reported that the average number of...Ch. 7.5 - The average full-sized front-loading Energy Star...Ch. 7.5 - Federal Income Tax Returns. The Wall Street...Ch. 7.5 - 27. The Economic Policy Institute periodically...Ch. 7.5 - State Rainfalls. The state of California has a...Ch. 7.5 - The mean preparation fee H&R Block charged retail...Ch. 7.5 - 30. To estimate the mean age for a population of...Ch. 7.6 - 31. A sample of size 100 is selected from a...Ch. 7.6 - 32. A population proportion is .40. A sample of...Ch. 7.6 - Prob. 29ECh. 7.6 - 34. The population proportion is .30. What is the...Ch. 7.6 - Prob. 31ECh. 7.6 - 36. The Wall Street Journal reported that the age...Ch. 7.6 - Seventy two percent of American adults have read a...Ch. 7.6 - Unnecessary Medical Care. According to Reader’s...Ch. 7.6 - Thirty-six percent of all Americans drink bottled...Ch. 7.6 - Prob. 36ECh. 7.6 - 41. The Food Marketing Institute shows that 17% of...Ch. 7.8 - Martina Levitt, director of marketing for the...Ch. 7.8 - Consider the Spontanversation sampling problem for...Ch. 7.8 - The Wall Street Journal reported that 37% of all...Ch. 7.8 - The vice president of sales for Blasterman...Ch. 7 - Shadow Stocks. Jack Lawler, a financial analyst,...Ch. 7 - 43. The latest available data showed health...Ch. 7 - 44. Foot Locker uses sales per square foot as a...Ch. 7 - 45. Allegiant Airlines charges a mean base fare of...Ch. 7 - 46. After deducting grants based on need, the...Ch. 7 - Prob. 47SECh. 7 - Prob. 48SECh. 7 - Production Quality Control. A production process...Ch. 7 - Prob. 50SECh. 7 - Prob. 51SECh. 7 - Prob. 52SECh. 7 - Prob. 53SECh. 7 - 54. Lori Jeffrey is a successful sales...Ch. 7 - Managerial Report
Prepare a managerial report that...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- The table shows the total square footage (in billions) of retailing space at shopping centers and their sales (in billions of dollars) for 10 years. Construct a 90% prediction interval for sales when the total square footage is 5.7 billion. The equation of the regression line is y = 567.939x - 1985.560. Total 4.9 5.2 5.3 5.4 5.5 5.6 5.9 5.9 5.9 6.1 Square Footage, x Sales, y 880.1 935.5 989.5 1056.9 1100.7 1201.9 1283.4 1346.3 1434.8 1549.5 Click the icon to view a table of critical values for the t-distribution. Construct a 90% prediction interval for the sales when the total square footage is 5.7 billion. Choose the correct prediction interval below, rounded to the nearest million dollars.arrow_forwardThe maximum weights (in kilograms) for which one repetition of a half squat can be performed and the times (in seconds) to run a 10-meter sprint for 12 international soccer players are shown in the attached data table with a sample correlation coefficient r of -0.941. A 13th data point was added to the end of the data set for an international soccer player who can perform the half squat with a maximum of 205 kilograms and can sprint 10 meters in 2.01 seconds. Describe how this affects the correlation coefficient r. Use technology. Click the icon to view the data set. The new correlation coefficient r (Round to three decimal places a going from 0.941 to - gets stronger, gets weaker, stays the same,arrow_forwardYou receive a brochure from a large university. The brochure indicates that the mean class size for full-time faculty is fewer than 31 students. You want to test this claim. You randomly select 18 classes taught by full-time faculty and determine the class size of each. The results are shown in the table below. At α = 0.05, can you support the university's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 36 28 25 27 29 35 32 39 31 28 380 22 26 29 24 27 24 30吋 24 (a) Write the claim mathematically and identify Ho and Ha. Which of the following correctly states Ho and H₂? ○ A. Ho: μ31 Нa: μ≤31 E. Ho: "=31 Ha: μ 31 OF. Ho: μ=31 Нa: μ31arrow_forwardTest the claim about the population mean μ at the level of significance α. Assume the population is normally distributed. μ Claim: <4715; α = 0.05 Sample statistics: x = 4917, s = 5501, n = 54 What are the null and alternative hypotheses? Ho: Ha (Type integers or decimals. Do not round.) Find the standardized test statistic t. t = ☐ (Round to two decimal places as needed.) Find the P-value. P = (Round to three decimal places as needed.) Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below. Ho. There enough evidence at the ☐ % level of significance to Fail to reject Reject .... the claim.arrow_forwardA politician claims that the mean salary for managers in his state is more than the national mean, $85,000. Assume the the population is normally distributed and the population standard deviation is $8700. The salaries (in dollars) for a random sample of 30 managers in the state are listed. At α = 0.01, is there enough evidence to support the claim? Use technology. 92,421 81,412 85,143 97,220 99,317 71,884 97,762 86,108 98,385 73,869 81,391 95,997 98,828 86,476 77,893 74,995 90,472 81,330 92,183 94,649 77,880 91,821 90,907 84,640 78,479 81,703 89,573 89,948 70,938 81,300 (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: " =85,000 Нa: μ85,000 D. Hoi u >85,000 Нa: μ≤85,000 (b) Identify the standardized test statistic. Z= B. Hoμ≥85,000 Haμ85,000 Haμ≤85,000 (Round the final answer to two places as needed. Round all intermediate values to three places as needed.) (c) Find the P-value. Use technology. (Round to three decimal places as needed.) (d) Decide whether to reject…arrow_forwardI would like to get help to know how to make a report of the multiple regression analysis I performed about 30 employees salaries. it should include a description of the predictice model, pre-analysis, regression analysis, interpretation of the relevant findings and a conclusion with recommendations. thank youarrow_forwardTHE QUESTION: Set up a free RStudio account at posit.cloud. At the start of your R session, you should enter the following commands. set.seed(1) e<-rnorm(n = 100,mean = 0,sd = 80) x<-seq(1,100,1) y<-10+15*x + e Follow the examples in the Panopto Videos to use R to obtain the values requested below. (As always, if you round your answers, make sure you do so correctly and keep at least three decimal places.) (a) The smallest value of y = (b) The largest value of y = (c) The standard deviation of y = (d) The mean of y = (e) The median of y = (f) The correlation between x and y = (g) Using the variable e as data, the p-value for a test of Ho = 0 vs. Hд μ0 is ANSWERS I HAVE TRIED THAT ARE NOT CORRECT ↓ Answer Preview (BESIDES F, F IS CORRECT) (A) -104.123 (B) 1545.84 (C) 448.543 (D) 752.347 (E) 775.533 (F) (G) 0.987 0.497 PLEASSSEEE DO NOT GIVE ME BACK THE SAME ANSWERS THAT I HAVE SAID ARE WRONG Result incorrect incorrect incorrect incorrect incorrect correct incorrectarrow_forward3:23 Search 1 of 2 UMCISI mville.brightspace.com onomic Statistics our grade, can be done as a 2 people's group) - Due date Sunday, 12/08/202 through Brightspace portal. College students' physical, emotional, and mental health are at the forefront of many national discussions and statistical studies. Many factors can influence students' overall health, including diet, sleep, exercise, social media usage, etc. In this project, you will look at real data gathered from 30 college students and determine related descriptive and inferential statistics. Please use MS Excel (see attached file) to collect your data and complete the assignment. The students surveyed were asked the following questions: On a typical weekday, Are you an on-campus student or a commuter? How many hours of sleep do you get? How many hours do you study? How many calories do you intake? How many hours do you exercise? How many hours do you spend on social media? How many hours do you spend with your friends and family…arrow_forwardIs the area to the right of the left-tail critical value Chi-squared(1-alpha) of the chi-squared distribution always (1-alpha), and is the area to the left of this critical value always alpha? Does this apply to all chi-squared distributions?Please see image attachedarrow_forwardSet up a free RStudio account at posit.cloud. At the start of your R session, you should enter the following commands. set.seed(1) e<-rnorm(n = 100,mean = 0,sd = 80) x<-seq(1,100,1) y<-10+15*x + e Follow the examples in the Panopto Videos to use R to obtain the values requested below. (As always, if you round your answers, make sure you do so correctly and keep at least three decimal places.) (a) The smallest value of y = (b) The largest value of y = (c) The standard deviation of y = (d) The mean of y = (e) The median of y = (f) The correlation between x and y = : (g) Using the variable e as data, the p-value for a test of Hoμ = 0 vs. HA μ0 isarrow_forwardDoes Chi-squared(alpha) always represent the right tail of the the chi-square distribution and does Chi-squared(1-alpha) always represent the left tail of the the chi-square distribution. Also, for a standard normal distribution would Z(1-alpha) be equivalent to -Zalpha in represneting the left tail of the standard normal distribution curve because they both have the same z-score. Furthermore, is my understanding correct in the sense that if we have a critical value,say Zalpha, would the area to the right of it will be alpha and to the left of it would be 1-alphaarrow_forwardOne bulb manufacturer claims an average bulb life of 1,600 hours. It is suspected that the actual average is significantly lower. To verify this, a sample of 49 bulbs is selected and the life of each bulb is measured. A sample mean of 1,500 hours and a standard deviation of 120 hours were obtained from them. Can you be sure, at 5% significance, that the mean life is less than what the manufacturer claims?arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALCollege Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Bayes' Theorem 1: Introduction and conditional probability; Author: Dr Nic's Maths and Stats;https://www.youtube.com/watch?v=lQVkXfJ-rpU;License: Standard YouTube License, CC-BY
What is Conditional Probability | Bayes Theorem | Conditional Probability Examples & Problems; Author: ACADGILD;https://www.youtube.com/watch?v=MxOny_1y2Q4;License: Standard YouTube License, CC-BY
Bayes' Theorem of Probability With Tree Diagrams & Venn Diagrams; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=OByl4RJxnKA;License: Standard YouTube License, CC-BY
Bayes' Theorem - The Simplest Case; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=XQoLVl31ZfQ;License: Standard Youtube License