a. Answer The vertex of graph of function is ( − 4 , 25 ) . Explanation Given information: The given function is f ( x ) = 9 − 8 x − x 2 . Calculation: The given function can be written as, y = 9 − 8 x − x 2 .... ( Replace f ( x ) = y ) or, y − 9 = − ( x 2 + 8 x ) y − 9 + ( − 16 ) = − ( x 2 + 2 ( x ) ( 4 ) + ( 4 ) 2 ) .... ( Complete square ) y − 25 = − ( x + 4 ) 2 .... ( 1 ) Since (1) represents a parabola of the form y − k = a ( x − h ) 2 . Therefore the graph for the function has vertex ( − 4 , 25 ) . b. To determine The domain of the function f ( x ) = 9 − 8 x − x 2 . Answer The domain of the function is all real numbers. Explanation Given information: The given function is f ( x ) = 9 − 8 x − x 2 . Calculation: From (1), the parabola obtained represents a parabola opening downwards because of negative coefficient of ( x + 4 ) 2 . Therefore the domain of the function has no restrictions at all. Hence the domain of the function is all real numbers. c. To determine The range of the function f ( x ) = 9 − 8 x − x 2 . Answer The range of the function is { y | y ≤ 25 } . Explanation Given information: The given function is f ( x ) = 9 − 8 x − x 2 . Calculation: From (1), the parabola obtained represents a parabola opening downwards because of negative coefficient of ( x + 4 ) 2 . Also the parabola has the vertex ( − 4 , 25 ) which means the upper limit for range is 25 . Since, the parabola (1) is upper bound. So its maximum range will be ( y ) coordinate of its vertex. Hence the range of the function is all real numbers less than or equal to 25 . Mathematically, the range of function is { y | y ≤ 25 } . d. To determine The zeros of the function f ( x ) = 9 − 8 x − x 2 . Answer The zeros of the function are − 9 , 1 . Explanation Given information: The given function is f ( x ) = 9 − 8 x − x 2 . Calculation: The zeros of the function can be obtained by equating the given function equal to zero. Therefore f ( x ) = 0 gives, 9 − 8 x − x 2 = 0 or, x 2 + 8 x − 9 = 0 ( x + 9 ) ( x − 1 ) = 0 x = − 9 or x = 1 Hence the zeros of the function are − 9 , 1 .

Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

See similar textbooks

Videos

Question

Chapter 7.6, Problem 28WE

To determine

The vertex of the graph of the function f(x)=9−8x−x2 .

Expert Solution

Answer to Problem 28WE

The vertex of graph of function is (−4,25) .

Explanation of Solution

Given information: The given function is f(x)=9−8x−x2 .

Calculation: The given function can be written as,

y=9−8x−x2.... (Replace f(x)=y)or, y−9=−(x2+8x)y−9+(−16)=−(x2+2(x)(4)+(4)2)....(Complete square)y−25=−(x+4)2 ....(1)

Since (1) represents a parabola of the form y−k=a(x−h)2 . Therefore the graph for the function has vertex (−4,25) .

To determine

The domain of the function f(x)=9−8x−x2 .

Expert Solution

Answer to Problem 28WE

The domain of the function is all real numbers.

Explanation of Solution

Given information: The given function is f(x)=9−8x−x2 .

Calculation: From (1), the parabola obtained represents a parabola opening downwards because of negative coefficient of (x+4)2 . Therefore the domain of the function has no restrictions at all.

Hence the domain of the function is all real numbers.

To determine

The range of the function f(x)=9−8x−x2 .

Expert Solution

Answer to Problem 28WE

The range of the function is {y|y≤25} .

Explanation of Solution

Given information: The given function is f(x)=9−8x−x2 .

Calculation: From (1), the parabola obtained represents a parabola opening downwards because of negative coefficient of (x+4)2 . Also the parabola has the vertex (−4,25) which means the upper limit for range is 25 . Since, the parabola (1) is upper bound. So its maximum range will be (y) coordinate of its vertex.

Hence the range of the function is all real numbers less than or equal to 25 . Mathematically, the range of function is {y|y≤25} .

To determine

The zeros of the function f(x)=9−8x−x2 .

Expert Solution

Answer to Problem 28WE

The zeros of the function are −9,1 .

Explanation of Solution

Given information: The given function is f(x)=9−8x−x2 .

Calculation: The zeros of the function can be obtained by equating the given function equal to zero. Therefore f(x)=0 gives,

9−8x−x2=0or, x2+8x−9=0(x+9)(x−1)=0x=−9 or x=1

Hence the zeros of the function are −9,1 .

Chapter 7.6, Problem 27WE

Chapter 7.6, Problem 29WE

Chapter 7 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 7.1 - Prob. 1OE Ch. 7.1 - Prob. 2OE Ch. 7.1 - Prob. 3OE Ch. 7.1 - Prob. 4OE Ch. 7.1 - Prob. 5OE Ch. 7.1 - Prob. 6OE Ch. 7.1 - Prob. 7OE Ch. 7.1 - Prob. 8OE Ch. 7.1 - Prob. 9OE Ch. 7.1 - Prob. 10OE

Ch. 7.1 - Prob. 11OE Ch. 7.1 - Prob. 12OE Ch. 7.1 - Prob. 13OE Ch. 7.1 - Prob. 14OE Ch. 7.1 - Prob. 15OE Ch. 7.1 - Prob. 16OE Ch. 7.1 - Prob. 17OE Ch. 7.1 - Prob. 18OE Ch. 7.1 - Prob. 19OE Ch. 7.1 - Prob. 20OE Ch. 7.1 - Prob. 1WE Ch. 7.1 - Prob. 2WE Ch. 7.1 - Prob. 3WE Ch. 7.1 - Prob. 4WE Ch. 7.1 - Prob. 5WE Ch. 7.1 - Prob. 6WE Ch. 7.1 - Prob. 7WE Ch. 7.1 - Prob. 8WE Ch. 7.1 - Prob. 9WE Ch. 7.1 - Prob. 10WE Ch. 7.1 - Prob. 11WE Ch. 7.1 - Prob. 12WE Ch. 7.1 - Prob. 13WE Ch. 7.1 - Prob. 14WE Ch. 7.1 - Prob. 15WE Ch. 7.1 - Prob. 16WE Ch. 7.1 - Prob. 17WE Ch. 7.1 - Prob. 18WE Ch. 7.1 - Prob. 19WE Ch. 7.1 - Prob. 20WE Ch. 7.1 - Prob. 21WE Ch. 7.1 - Prob. 22WE Ch. 7.1 - Prob. 23WE Ch. 7.1 - Prob. 24WE Ch. 7.1 - Prob. 25WE Ch. 7.1 - Prob. 26WE Ch. 7.1 - Prob. 27WE Ch. 7.1 - Prob. 28WE Ch. 7.1 - Prob. 29WE Ch. 7.1 - Prob. 30WE Ch. 7.1 - Prob. 31WE Ch. 7.1 - Prob. 32WE Ch. 7.1 - Prob. 33WE Ch. 7.1 - Prob. 34WE Ch. 7.1 - Prob. 35WE Ch. 7.1 - Prob. 36WE Ch. 7.1 - Prob. 37WE Ch. 7.1 - Prob. 38WE Ch. 7.1 - Prob. 39WE Ch. 7.1 - Prob. 40WE Ch. 7.1 - Prob. 41WE Ch. 7.1 - Prob. 42WE Ch. 7.1 - Prob. 1MRE Ch. 7.1 - Prob. 2MRE Ch. 7.1 - Prob. 3MRE Ch. 7.1 - Prob. 4MRE Ch. 7.1 - Prob. 5MRE Ch. 7.1 - Prob. 6MRE Ch. 7.1 - Prob. 7MRE Ch. 7.1 - Prob. 8MRE Ch. 7.1 - Prob. 9MRE Ch. 7.2 - Prob. 1OE Ch. 7.2 - Prob. 2OE Ch. 7.2 - Prob. 3OE Ch. 7.2 - Prob. 4OE Ch. 7.2 - Prob. 5OE Ch. 7.2 - Prob. 6OE Ch. 7.2 - Prob. 1WE Ch. 7.2 - Prob. 2WE Ch. 7.2 - Prob. 3WE Ch. 7.2 - Prob. 4WE Ch. 7.2 - Prob. 5WE Ch. 7.2 - Prob. 6WE Ch. 7.2 - Prob. 7WE Ch. 7.2 - Prob. 8WE Ch. 7.2 - Prob. 9WE Ch. 7.2 - Prob. 10WE Ch. 7.2 - Prob. 11WE Ch. 7.2 - Prob. 12WE Ch. 7.2 - Prob. 13WE Ch. 7.2 - Prob. 14WE Ch. 7.2 - Prob. 15WE Ch. 7.2 - Prob. 16WE Ch. 7.2 - Prob. 17WE Ch. 7.2 - Prob. 18WE Ch. 7.2 - Prob. 19WE Ch. 7.2 - Prob. 20WE Ch. 7.2 - Prob. 21WE Ch. 7.2 - Prob. 22WE Ch. 7.2 - Prob. 23WE Ch. 7.2 - Prob. 24WE Ch. 7.2 - Prob. 25WE Ch. 7.2 - Prob. 26WE Ch. 7.2 - Prob. 27WE Ch. 7.2 - Prob. 28WE Ch. 7.2 - Prob. 29WE Ch. 7.2 - Prob. 30WE Ch. 7.2 - Prob. 31WE Ch. 7.2 - Prob. 32WE Ch. 7.2 - Prob. 33WE Ch. 7.2 - Prob. 34WE Ch. 7.2 - Prob. 35WE Ch. 7.2 - Prob. 36WE Ch. 7.2 - Prob. 37WE Ch. 7.2 - Prob. 38WE Ch. 7.2 - Prob. 39WE Ch. 7.2 - Prob. 40WE Ch. 7.2 - Prob. 41WE Ch. 7.2 - Prob. 42WE Ch. 7.2 - Prob. 1P Ch. 7.2 - Prob. 2P Ch. 7.2 - Prob. 3P Ch. 7.2 - Prob. 4P Ch. 7.2 - Prob. 5P Ch. 7.2 - Prob. 6P Ch. 7.2 - Prob. 7P Ch. 7.2 - Prob. 8P Ch. 7.2 - Prob. 9P Ch. 7.2 - Prob. 10P Ch. 7.2 - Prob. 11P Ch. 7.2 - Prob. 12P Ch. 7.2 - Prob. 13P Ch. 7.2 - Prob. 14P Ch. 7.2 - Prob. 15P Ch. 7.2 - Prob. 1ST Ch. 7.2 - Prob. 2ST Ch. 7.2 - Prob. 3ST Ch. 7.2 - Prob. 4ST Ch. 7.2 - Prob. 5ST Ch. 7.2 - Prob. 6ST Ch. 7.3 - Prob. 1OE Ch. 7.3 - Prob. 2OE Ch. 7.3 - Prob. 3OE Ch. 7.3 - Prob. 4OE Ch. 7.3 - Prob. 5OE Ch. 7.3 - Prob. 6OE Ch. 7.3 - Prob. 7OE Ch. 7.3 - Prob. 8OE Ch. 7.3 - Prob. 9OE Ch. 7.3 - Prob. 10OE Ch. 7.3 - Prob. 1WE Ch. 7.3 - Prob. 2WE Ch. 7.3 - Prob. 3WE Ch. 7.3 - Prob. 4WE Ch. 7.3 - Prob. 5WE Ch. 7.3 - Prob. 6WE Ch. 7.3 - Prob. 7WE Ch. 7.3 - Prob. 8WE Ch. 7.3 - Prob. 9WE Ch. 7.3 - Prob. 10WE Ch. 7.3 - Prob. 11WE Ch. 7.3 - Prob. 12WE Ch. 7.3 - Prob. 13WE Ch. 7.3 - Prob. 14WE Ch. 7.3 - Prob. 15WE Ch. 7.3 - Prob. 16WE Ch. 7.3 - Prob. 17WE Ch. 7.3 - Prob. 18WE Ch. 7.3 - Prob. 19WE Ch. 7.3 - Prob. 20WE Ch. 7.3 - Prob. 21WE Ch. 7.3 - Prob. 22WE Ch. 7.3 - Prob. 23WE Ch. 7.3 - Prob. 24WE Ch. 7.3 - Prob. 25WE Ch. 7.3 - Prob. 26WE Ch. 7.3 - Prob. 27WE Ch. 7.3 - Prob. 28WE Ch. 7.3 - Prob. 29WE Ch. 7.3 - Prob. 30WE Ch. 7.3 - Prob. 31WE Ch. 7.3 - Prob. 32WE Ch. 7.3 - Prob. 33WE Ch. 7.3 - Prob. 34WE Ch. 7.3 - Prob. 35WE Ch. 7.3 - Prob. 36WE Ch. 7.3 - Prob. 37WE Ch. 7.3 - Prob. 38WE Ch. 7.3 - Prob. 39WE Ch. 7.3 - Prob. 40WE Ch. 7.3 - Prob. 41WE Ch. 7.3 - Prob. 42WE Ch. 7.3 - Prob. 43WE Ch. 7.3 - Prob. 1MRE Ch. 7.3 - Prob. 2MRE Ch. 7.3 - Prob. 3MRE Ch. 7.3 - Prob. 4MRE Ch. 7.3 - Prob. 5MRE Ch. 7.3 - Prob. 6MRE Ch. 7.3 - Prob. 7MRE Ch. 7.3 - Prob. 8MRE Ch. 7.3 - Prob. 9MRE Ch. 7.3 - Prob. 10MRE Ch. 7.3 - Prob. 11MRE Ch. 7.3 - Prob. 12MRE Ch. 7.3 - Prob. 13MRE Ch. 7.3 - Prob. 14MRE Ch. 7.3 - Prob. 1CE Ch. 7.3 - Prob. 2CE Ch. 7.3 - Prob. 3CE Ch. 7.3 - Prob. 4CE Ch. 7.3 - Prob. 5CE Ch. 7.3 - Prob. 6CE Ch. 7.4 - Prob. 1OE Ch. 7.4 - Prob. 2OE Ch. 7.4 - Prob. 3OE Ch. 7.4 - Prob. 4OE Ch. 7.4 - Prob. 5OE Ch. 7.4 - Prob. 6OE Ch. 7.4 - Prob. 7OE Ch. 7.4 - Prob. 8OE Ch. 7.4 - Prob. 9OE Ch. 7.4 - Prob. 10OE Ch. 7.4 - Prob. 11OE Ch. 7.4 - Prob. 12OE Ch. 7.4 - Prob. 1WE Ch. 7.4 - Prob. 2WE Ch. 7.4 - Prob. 3WE Ch. 7.4 - Prob. 4WE Ch. 7.4 - Prob. 5WE Ch. 7.4 - Prob. 6WE Ch. 7.4 - Prob. 7WE Ch. 7.4 - Prob. 8WE Ch. 7.4 - Prob. 9WE Ch. 7.4 - Prob. 10WE Ch. 7.4 - Prob. 11WE Ch. 7.4 - Prob. 12WE Ch. 7.4 - Prob. 13WE Ch. 7.4 - Prob. 14WE Ch. 7.4 - Prob. 15WE Ch. 7.4 - Prob. 16WE Ch. 7.4 - Prob. 17WE Ch. 7.4 - Prob. 18WE Ch. 7.4 - Prob. 19WE Ch. 7.4 - Prob. 20WE Ch. 7.4 - Prob. 21WE Ch. 7.4 - Prob. 22WE Ch. 7.4 - Prob. 23WE Ch. 7.4 - Prob. 24WE Ch. 7.4 - Prob. 25WE Ch. 7.4 - Prob. 26WE Ch. 7.4 - Prob. 27WE Ch. 7.4 - Prob. 28WE Ch. 7.4 - Prob. 29WE Ch. 7.4 - Prob. 30WE Ch. 7.4 - Prob. 31WE Ch. 7.4 - Prob. 32WE Ch. 7.4 - Prob. 1ST Ch. 7.4 - Prob. 2ST Ch. 7.4 - Prob. 3ST Ch. 7.4 - Prob. 4ST Ch. 7.4 - Prob. 5ST Ch. 7.4 - Prob. 6ST Ch. 7.4 - Prob. 7ST Ch. 7.4 - Prob. 8ST Ch. 7.4 - Prob. 9ST Ch. 7.4 - Prob. 10ST Ch. 7.5 - Prob. 1OE Ch. 7.5 - Prob. 2OE Ch. 7.5 - Prob. 3OE Ch. 7.5 - Prob. 4OE Ch. 7.5 - Prob. 5OE Ch. 7.5 - Prob. 6OE Ch. 7.5 - Prob. 7OE Ch. 7.5 - Prob. 8OE Ch. 7.5 - Prob. 9OE Ch. 7.5 - Prob. 10OE Ch. 7.5 - Prob. 11OE Ch. 7.5 - Prob. 12OE Ch. 7.5 - Prob. 13OE Ch. 7.5 - Prob. 14OE Ch. 7.5 - Prob. 15OE Ch. 7.5 - Prob. 16OE Ch. 7.5 - Prob. 17OE Ch. 7.5 - Prob. 1WE Ch. 7.5 - Prob. 2WE Ch. 7.5 - Prob. 3WE Ch. 7.5 - Prob. 4WE Ch. 7.5 - Prob. 5WE Ch. 7.5 - Prob. 6WE Ch. 7.5 - Prob. 7WE Ch. 7.5 - Prob. 8WE Ch. 7.5 - Prob. 9WE Ch. 7.5 - Prob. 10WE Ch. 7.5 - Prob. 11WE Ch. 7.5 - Prob. 12WE Ch. 7.5 - Prob. 13WE Ch. 7.5 - Prob. 14WE Ch. 7.5 - Prob. 15WE Ch. 7.5 - Prob. 16WE Ch. 7.5 - Prob. 17WE Ch. 7.5 - Prob. 18WE Ch. 7.5 - Prob. 19WE Ch. 7.5 - Prob. 20WE Ch. 7.5 - Prob. 21WE Ch. 7.5 - Prob. 22WE Ch. 7.5 - Prob. 23WE Ch. 7.5 - Prob. 24WE Ch. 7.5 - Prob. 25WE Ch. 7.5 - Prob. 26WE Ch. 7.5 - Prob. 27WE Ch. 7.5 - Prob. 28WE Ch. 7.5 - Prob. 29WE Ch. 7.5 - Prob. 30WE Ch. 7.5 - Prob. 31WE Ch. 7.5 - Prob. 32WE Ch. 7.5 - Prob. 33WE Ch. 7.5 - Prob. 34WE Ch. 7.5 - Prob. 35WE Ch. 7.5 - Prob. 36WE Ch. 7.5 - Prob. 37WE Ch. 7.5 - Prob. 38WE Ch. 7.5 - Prob. 39WE Ch. 7.5 - Prob. 1MRE Ch. 7.5 - Prob. 2MRE Ch. 7.5 - Prob. 3MRE Ch. 7.5 - Prob. 4MRE Ch. 7.5 - Prob. 5MRE Ch. 7.5 - Prob. 6MRE Ch. 7.6 - Prob. 1OE Ch. 7.6 - Prob. 2OE Ch. 7.6 - Prob. 3OE Ch. 7.6 - Prob. 4OE Ch. 7.6 - Prob. 5OE Ch. 7.6 - Prob. 6OE Ch. 7.6 - Prob. 7OE Ch. 7.6 - Prob. 1WE Ch. 7.6 - Prob. 2WE Ch. 7.6 - Prob. 3WE Ch. 7.6 - Prob. 4WE Ch. 7.6 - Prob. 5WE Ch. 7.6 - Prob. 6WE Ch. 7.6 - Prob. 7WE Ch. 7.6 - Prob. 8WE Ch. 7.6 - Prob. 9WE Ch. 7.6 - Prob. 10WE Ch. 7.6 - Prob. 11WE Ch. 7.6 - Prob. 12WE Ch. 7.6 - Prob. 13WE Ch. 7.6 - Prob. 14WE Ch. 7.6 - Prob. 15WE Ch. 7.6 - Prob. 16WE Ch. 7.6 - Prob. 17WE Ch. 7.6 - Prob. 18WE Ch. 7.6 - Prob. 19WE Ch. 7.6 - Prob. 20WE Ch. 7.6 - Prob. 21WE Ch. 7.6 - Prob. 22WE Ch. 7.6 - Prob. 23WE Ch. 7.6 - Prob. 24WE Ch. 7.6 - Prob. 25WE Ch. 7.6 - Prob. 26WE Ch. 7.6 - Prob. 27WE Ch. 7.6 - Prob. 28WE Ch. 7.6 - Prob. 29WE Ch. 7.6 - Prob. 30WE Ch. 7.6 - Prob. 31WE Ch. 7.6 - Prob. 32WE Ch. 7.6 - Prob. 33WE Ch. 7.6 - Prob. 34WE Ch. 7.6 - Prob. 35WE Ch. 7.6 - Prob. 36WE Ch. 7.6 - Prob. 37WE Ch. 7.6 - Prob. 38WE Ch. 7.6 - Prob. 39WE Ch. 7.6 - Prob. 40WE Ch. 7.6 - Prob. 41WE Ch. 7.6 - Prob. 42WE Ch. 7.6 - Prob. 43WE Ch. 7.6 - Prob. 44WE Ch. 7.7 - Prob. 1OE Ch. 7.7 - Prob. 2OE Ch. 7.7 - Prob. 3OE Ch. 7.7 - Prob. 4OE Ch. 7.7 - Prob. 5OE Ch. 7.7 - Prob. 6OE Ch. 7.7 - Prob. 7OE Ch. 7.7 - Prob. 8OE Ch. 7.7 - Prob. 9OE Ch. 7.7 - Prob. 10OE Ch. 7.7 - Prob. 11OE Ch. 7.7 - Prob. 12OE Ch. 7.7 - Prob. 13OE Ch. 7.7 - Prob. 14OE Ch. 7.7 - Prob. 15OE Ch. 7.7 - Prob. 1WE Ch. 7.7 - Prob. 2WE Ch. 7.7 - Prob. 3WE Ch. 7.7 - Prob. 4WE Ch. 7.7 - Prob. 5WE Ch. 7.7 - Prob. 6WE Ch. 7.7 - Prob. 7WE Ch. 7.7 - Prob. 8WE Ch. 7.7 - Prob. 9WE Ch. 7.7 - Prob. 10WE Ch. 7.7 - Prob. 11WE Ch. 7.7 - Prob. 12WE Ch. 7.7 - Prob. 13WE Ch. 7.7 - Prob. 14WE Ch. 7.7 - Prob. 15WE Ch. 7.7 - Prob. 16WE Ch. 7.7 - Prob. 17WE Ch. 7.7 - Prob. 18WE Ch. 7.7 - Prob. 19WE Ch. 7.7 - Prob. 20WE Ch. 7.7 - Prob. 21WE Ch. 7.7 - Prob. 22WE Ch. 7.7 - Prob. 23WE Ch. 7.7 - Prob. 24WE Ch. 7.7 - Prob. 25WE Ch. 7.7 - Prob. 26WE Ch. 7.7 - Prob. 27WE Ch. 7.7 - Prob. 28WE Ch. 7.7 - Prob. 29WE Ch. 7.7 - Prob. 30WE Ch. 7.7 - Prob. 31WE Ch. 7.7 - Prob. 32WE Ch. 7.7 - Prob. 33WE Ch. 7.7 - Prob. 34WE Ch. 7.7 - Prob. 35WE Ch. 7.7 - Prob. 36WE Ch. 7.7 - Prob. 37WE Ch. 7.7 - Prob. 38WE Ch. 7.7 - Prob. 39WE Ch. 7.7 - Prob. 40WE Ch. 7.7 - Prob. 1P Ch. 7.7 - Prob. 2P Ch. 7.7 - Prob. 3P Ch. 7.7 - Prob. 4P Ch. 7.7 - Prob. 5P Ch. 7.7 - Prob. 6P Ch. 7.7 - Prob. 7P Ch. 7.7 - Prob. 8P Ch. 7.7 - Prob. 9P Ch. 7.7 - Prob. 10P Ch. 7.7 - Prob. 11P Ch. 7.7 - Prob. 12P Ch. 7.7 - Prob. 13P Ch. 7.7 - Prob. 14P Ch. 7.7 - Prob. 15P Ch. 7.7 - Prob. 16P Ch. 7.7 - Prob. 1MRE Ch. 7.7 - Prob. 2MRE Ch. 7.7 - Prob. 3MRE Ch. 7.7 - Prob. 4MRE Ch. 7.7 - Prob. 5MRE Ch. 7.7 - Prob. 6MRE Ch. 7.7 - Prob. 7MRE Ch. 7.7 - Prob. 8MRE Ch. 7.7 - Prob. 9MRE Ch. 7.7 - Prob. 10MRE Ch. 7.7 - Prob. 11MRE Ch. 7.7 - Prob. 12MRE Ch. 7.7 - Prob. 1ST Ch. 7.7 - Prob. 2ST Ch. 7.7 - Prob. 3ST Ch. 7.7 - Prob. 4ST Ch. 7.7 - Prob. 5ST Ch. 7.7 - Prob. 6ST Ch. 7.7 - Prob. 7ST Ch. 7 - Prob. 1CR Ch. 7 - Prob. 2CR Ch. 7 - Prob. 3CR Ch. 7 - Prob. 4CR Ch. 7 - Prob. 5CR Ch. 7 - Prob. 6CR Ch. 7 - Prob. 7CR Ch. 7 - Prob. 8CR Ch. 7 - Prob. 9CR Ch. 7 - Prob. 10CR Ch. 7 - Prob. 11CR Ch. 7 - Prob. 12CR Ch. 7 - Prob. 13CR Ch. 7 - Prob. 14CR Ch. 7 - Prob. 15CR Ch. 7 - Prob. 1CT Ch. 7 - Prob. 2CT Ch. 7 - Prob. 3CT Ch. 7 - Prob. 4CT Ch. 7 - Prob. 5CT Ch. 7 - Prob. 6CT Ch. 7 - Prob. 7CT Ch. 7 - Prob. 8CT Ch. 7 - Prob. 9CT Ch. 7 - Prob. 10CT Ch. 7 - Prob. 11CT Ch. 7 - Prob. 12CT Ch. 7 - Prob. 13CT Ch. 7 - Prob. 14CT Ch. 7 - Prob. 1CLR Ch. 7 - Prob. 2CLR Ch. 7 - Prob. 3CLR Ch. 7 - Prob. 4CLR Ch. 7 - Prob. 5CLR Ch. 7 - Prob. 6CLR Ch. 7 - Prob. 7CLR Ch. 7 - Prob. 8CLR Ch. 7 - Prob. 9CLR Ch. 7 - Prob. 10CLR Ch. 7 - Prob. 11CLR Ch. 7 - Prob. 12CLR Ch. 7 - Prob. 13CLR Ch. 7 - Prob. 14CLR Ch. 7 - Prob. 15CLR Ch. 7 - Prob. 16CLR Ch. 7 - Prob. 17CLR Ch. 7 - Prob. 18CLR Ch. 7 - Prob. 19CLR Ch. 7 - Prob. 20CLR Ch. 7 - Prob. 21CLR Ch. 7 - Prob. 22CLR Ch. 7 - Prob. 23CLR Ch. 7 - Prob. 24CLR Ch. 7 - Prob. 25CLR Ch. 7 - Prob. 26CLR Ch. 7 - Prob. 27CLR Ch. 7 - Prob. 28CLR Ch. 7 - Prob. 29CLR Ch. 7 - Prob. 30CLR Ch. 7 - Prob. 31CLR Ch. 7 - Prob. 32CLR Ch. 7 - Prob. 33CLR Ch. 7 - Prob. 34CLR Ch. 7 - Prob. 35CLR Ch. 7 - Prob. 36CLR Ch. 7 - Prob. 37CLR

Additional Math Textbook Solutions

Find more solutions based on key concepts

Determine whether the following vectors are linearly independent in 2 : (21),(32) (23),(46) (21),(13),(24) (12)...

Linear Algebra with Applications (9th Edition) (Featured Titles for Linear Algebra (Introductory))

Diagonalize the matrices in Exercises 720, if possible. The eigenvalues for Exercises 1116 are as follows: (11)...

Linear Algebra and Its Applications (5th Edition)

Fill in each blank so that the resulting statement is true. An equation that expresses a relationship between t...

Algebra and Trigonometry

In the following exercises, evaluate each expression. hwwhen h=12,w=3

PREALGEBRA

Exercises 1-44: Checking Symbolic Skills Solve the quadratic equation. Check your answers for Exercises 1-28. ...

College Algebra with Modeling & Visualization (6th Edition)

Fill in each blanks so that the resulting statement is true. Any set of ordered pairs is called a/an _______. T...

College Algebra (7th Edition)

Knowledge Booster

$Algebra$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.

Recommended textbooks for you

Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education

Algebra and Trigonometry (6th Edition)

Algebra

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:PEARSON

Contemporary Abstract Algebra

Algebra

ISBN:9781305657960

Author:Joseph Gallian

Publisher:Cengage Learning

Linear Algebra: A Modern Introduction

Algebra

ISBN:9781285463247

Author:David Poole

Publisher:Cengage Learning

Algebra And Trigonometry (11th Edition)

Algebra

ISBN:9780135163078

Author:Michael Sullivan

Publisher:PEARSON

Introduction to Linear Algebra, Fifth Edition

Algebra

ISBN:9780980232776

Author:Gilbert Strang

Publisher:Wellesley-Cambridge Press

College Algebra (Collegiate Math)

Algebra

ISBN:9780077836344

Author:Julie Miller, Donna Gerken

Publisher:McGraw-Hill Education

SEE MORE TEXTBOOKS

Interpreting Graphs of Quadratic Equations (GMAT/GRE/CAT/Bank PO/SSC CGL) | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=BHgewRcuoRM;License: Standard YouTube License, CC-BY

Solve a Trig Equation in Quadratic Form Using the Quadratic Formula (Cosine, 4 Solutions); Author: Mathispower4u;https://www.youtube.com/watch?v=N6jw_i74AVQ;License: Standard YouTube License, CC-BY

The vertex of the graph of the function f ( x ) = 9 − 8 x − x 2 .

Videos

The vertex of the graph of the function f(x)=9−8x−x2 .

Answer to Problem 28WE

Explanation of Solution

The domain of the function f(x)=9−8x−x2 .

Answer to Problem 28WE

Explanation of Solution

The range of the function f(x)=9−8x−x2 .

Answer to Problem 28WE

Explanation of Solution

The zeros of the function f(x)=9−8x−x2 .

Answer to Problem 28WE

Explanation of Solution

Chapter 7 Solutions

Additional Math Textbook Solutions