Chapter 7.6, Problem 28P

Solve each equation.

$3\cdot 2^x-16=80$

To determine

To solve an equation ${3.2}^x-16=80$

Answer to Problem 28P

The value $\text{of}x=5$ .

Explanation of Solution

Given information :

Given equation ${3.2}^x-16=80$

As we have ${3.2}^x-16=80$

  $\begin{array}{l}\Rightarrow {3.2}^x=80+16\\ \Rightarrow 2^x=\frac{96}{3}\\ \Rightarrow 2^x=32\\ \Rightarrow 2^x=2^5\\ \therefore x=5\end{array}$

Hence, the value $\text{of}x=5$ .