Explanation The cooling constant is obtained at two different times by equating the equations y ( t 1 ) and y ( t 2 ) Given: k = 1 t 1 − t 2 ln ( y ( t 2 ) − T 0 y ( t 1 ) − T 0 ) Calculation: We know that y ( t 1 ) = T 0 + C e − k t 1 and y ( t 2 ) = T 0 + C e − k t 2 ...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Differential Equations

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Question

Chapter 7.6, Problem 22E

To determine

To show that the cooling constant of an object can be determined from two temperature readings $y (t_{1})$ and $y (t_{2})$ at times $t_{1} \neq t_{2}$ by the given formula

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Chapter 7.6, Problem 21E

Chapter 7.6, Problem 23E

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Chapter 7 Solutions

Calculus - Standalone book

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To show that the cooling constant of an object can be determined from two temperature readings y ( t 1 ) and y ( t 2 ) at times t 1 ≠ t 2 by the given formula

Solution Summary: The author explains that the cooling constant of an object can be determined from two temperature readings y (t 1 ) and t 2 by the given formula.

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To show that the cooling constant of an object can be determined from two temperature readings $y (t_{1})$ and $y (t_{2})$ at times $t_{1} \neq t_{2}$ by the given formula

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Chapter 7 Solutions

To show that the cooling constant of an object can be determined from two temperature readings y ( t 1 ) and y ( t 2 ) at times t 1 ≠ t 2 by the given formula

Solution Summary: The author explains that the cooling constant of an object can be determined from two temperature readings y (t 1 ) and t 2 by the given formula.

Concept explainers

Videos

To show that the cooling constant of an object can be determined from two temperature readings y(t1) and y(t2) at times t1≠t2 by the given formula

Want to see the full answer?

Chapter 7 Solutions

To show that the cooling constant of an object can be determined from two temperature readings $y (t_{1})$ and $y (t_{2})$ at times $t_{1} \neq t_{2}$ by the given formula