Chapter 7.6, Problem 105ES

(a)

To determine

To calculate: The time period of a pendulum whose length is $8$ feet using the formula $T=2\pi \sqrt{\frac{l}{32}}$ where $T$ is the time period in seconds, $l$ is its length in feet and the acceleration of gravity is $32\text{ ft}/{\text{sec}}^2$.

(b)

To determine

To calculate: The effect on time period of the pendulum if the length of the pendulum is doubled using the formula $T=2\pi \sqrt{\frac{l}{32}}$ where $T$ is the time period in seconds, $l$ is its length in feet and the acceleration of gravity is $32\text{ ft}/{\text{sec}}^2$.

(c)

To determine

To calculate: The time period of a pendulum on moon if gravity on moon is $\frac{1}{6}$ that on Earth and a pendulum has a time period of $2$ seconds on Earth using the formula, $T=2\pi \sqrt{\frac{l}{g}}$ where $T$ is the time period in seconds, $l$ is its length in feet, $g$ is the acceleration of gravity and its value is $32\text{ ft}/{\text{sec}}^2$.