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Essentials of Statistics for Business and Economics, Loose-leaf Version
8th Edition
ISBN: 9781337114196
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: South-Western College Pub
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Textbook Question
Chapter 7.5, Problem 28E
The state of California has a mean annual rainfall of 22 inches, whereas the state of New York has a mean annual rainfall of 42 inches (Current Results website, October 27, 2012). Assume that the standard deviation for both states is 4 inches. A sample of 30 years of rainfall for California and a sample of 45 years of rainfall for New York has been taken.
- a. Show the
probability distribution of the sample mean annual rainfall for California. - b. What is the probability that the sample mean is within 1 inch of the population mean for California?
- c. What is the probability that the sample mean is within 1 inch of the population mean for New York?
- d. In which case, part (b) or part (c), is the probability of obtaining a sample mean within 1 inch of the population mean greater? Why?
Expert Solution & Answer
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Students have asked these similar questions
Question 2
Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples
of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2.
Table 2: Strength Data for Question 2
Sample Number
x1
x2
23
x4
x5
R
1
83.0
2
88.6 78.3 78.8
3
85.7
75.8
84.3
81.2 78.7 75.7 77.0
71.0 84.2
81.0
79.1
7.3
80.2 17.6
75.2
80.4
10.4
4
80.8
74.4
82.5
74.1 75.7 77.5
8.4
5
83.4
78.4
82.6 78.2
78.9
80.3
5.2
File Preview
6
75.3
79.9
87.3 89.7
81.8
82.8
14.5
7
74.5
78.0 80.8
73.4
79.7
77.3
7.4
8
79.2
84.4 81.5 86.0
74.5
81.1
11.4
9
80.5
86.2
76.2 64.1
80.2
81.4
9.9
10
75.7
75.2
71.1 82.1
74.3
75.7
10.9
11
80.0 81.5
78.4 73.8
78.1
78.4
7.7
12
80.6
81.8
79.3
73.8
81.7 79.4
8.0
13
82.7
81.3
79.1
82.0 79.5 80.9
3.6
14
79.2
74.9
78.6 77.7
75.3
77.1
4.3
15
85.5 82.1
82.8 73.4
71.7
79.1
13.8
16
78.8 79.6
80.2 79.1
80.8 79.7
2.0
17
82.1
78.2
18
84.5
76.9
75.5
83.5 81.2
19
79.0 77.8
20
84.5
73.1
78.2 82.1
79.2 81.1 7.6
81.2 84.4 81.6 80.8…
Name:
Lab Time:
Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26
Contingency Analysis (Ch. 9)
In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to
evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop)
were more likely to suffer a fall in the next six months. I have tabulated the data below.
Answer the questions below. Please show your calculations on this or a separate sheet.
Did not stop walking to talk
Stopped walking to talk Totals
Suffered a fall
Did not suffer a fall
Totals
12
11
23
2
35
37
14
14
46
60
Quiz 7:
1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those
who did not stop walking vs. those who did stop walking. Interpret your result verbally.
Solve please and thank you!
Chapter 7 Solutions
Essentials of Statistics for Business and Economics, Loose-leaf Version
Ch. 7.2 - Consider a finite population with five elements...Ch. 7.2 - Assume a finite population has 350 elements. Using...Ch. 7.2 - Industrial Stock Performance. Fortune publishes...Ch. 7.2 - The 10 most active stocks on the New York Stock...Ch. 7.2 - A student government organization is interested in...Ch. 7.2 - 6. The County and City Data Book, published by the...Ch. 7.2 - 7. Assume that we want to identify a simple random...Ch. 7.2 - 8. The following stocks make up the Dow Jones...Ch. 7.2 - 9. The Wall Street Journal provides the net asset...Ch. 7.2 - 10. Indicate which of the following situations...
Ch. 7.3 - The following data are from a simple random...Ch. 7.3 - Prob. 12ECh. 7.3 - 13. A sample of 5 months of sales data provided...Ch. 7.3 - 14. Morningstar publishes ratings data on 1208...Ch. 7.3 - The National Football League (NFL) polls fans to...Ch. 7.3 - 16. A sample of 426 U.S. adults age 50 and older...Ch. 7.3 - 17. One of the questions in the Pew Internet &...Ch. 7.5 - 18. A population has a mean of 200 and a standard...Ch. 7.5 - A population has a mean of 200 and a standard...Ch. 7.5 - 20. Assume the population standard deviation is σ...Ch. 7.5 - 21. Suppose a random sample of size 50 is selected...Ch. 7.5 - Sampling Distribution for Electronic Associates,...Ch. 7.5 - Finding Probabilities for Electronic Associates,...Ch. 7.5 - Barrons reported that the average number of weeks...Ch. 7.5 - Prob. 25ECh. 7.5 - Prob. 26ECh. 7.5 - The Economic Policy Institute periodically issues...Ch. 7.5 - 28. The state of California has a mean annual...Ch. 7.5 - 29. The mean preparation fee H&R Block charged...Ch. 7.5 - To estimate the mean age for a population of 4000...Ch. 7.6 - A sample of size 100 is selected from a population...Ch. 7.6 - 32. A population proportion is .40. A sample of...Ch. 7.6 - Prob. 33ECh. 7.6 - 34. The population proportion is .30. What is the...Ch. 7.6 - Orders from First-Time Customers. The president of...Ch. 7.6 - The Wall Street Journal reported that the age at...Ch. 7.6 - Prob. 37ECh. 7.6 - Unnecessary Medical Care. According to Readers...Ch. 7.6 - Prob. 39ECh. 7.6 - 40. The Grocery Manufacturers of America reported...Ch. 7.6 - 41. The Food Marketing Institute shows that 17% of...Ch. 7 - Shadow Stocks. Jack Lawler, a financial analyst,...Ch. 7 - The latest available data showed health...Ch. 7 - 44. Foot Locker uses sales per square foot as a...Ch. 7 - Allegiant Airlines charges a mean base fare of 89....Ch. 7 - After deducting grants based on need, the average...Ch. 7 - Prob. 47SECh. 7 - Survey Research Results. A researcher reports...Ch. 7 - Production Quality Control. A production process...Ch. 7 - Australians and Smoking. Reuters reports that 15...Ch. 7 - 51. A market research firm conducts telephone...Ch. 7 - Advertisers contract with Internet service...Ch. 7 - The proportion of individuals insured by the...Ch. 7 - Lori Jeffrey is a successful sales representative...Ch. 7 - Managerial Report Prepare a managerial report that...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- 7. In a 2011 article, M. Radelet and G. Pierce reported a logistic prediction equation for the death penalty verdicts in North Carolina. Let Y denote whether a subject convicted of murder received the death penalty (1=yes), for the defendant's race h (h1, black; h = 2, white), victim's race i (i = 1, black; i = 2, white), and number of additional factors j (j = 0, 1, 2). For the model logit[P(Y = 1)] = a + ß₁₂ + By + B²², they reported = -5.26, D â BD = 0, BD = 0.17, BY = 0, BY = 0.91, B = 0, B = 2.02, B = 3.98. (a) Estimate the probability of receiving the death penalty for the group most likely to receive it. [4 pts] (b) If, instead, parameters used constraints 3D = BY = 35 = 0, report the esti- mates. [3 pts] h (c) If, instead, parameters used constraints Σ₁ = Σ₁ BY = Σ; B = 0, report the estimates. [3 pts] Hint the probabilities, odds and odds ratios do not change with constraints.arrow_forwardSolve please and thank you!arrow_forwardSolve please and thank you!arrow_forward
- Question 1:We want to evaluate the impact on the monetary economy for a company of two types of strategy (competitive strategy, cooperative strategy) adopted by buyers.Competitive strategy: strategy characterized by firm behavior aimed at obtaining concessions from the buyer.Cooperative strategy: a strategy based on a problem-solving negotiating attitude, with a high level of trust and cooperation.A random sample of 17 buyers took part in a negotiation experiment in which 9 buyers adopted the competitive strategy, and the other 8 the cooperative strategy. The savings obtained for each group of buyers are presented in the pdf that i sent: For this problem, we assume that the samples are random and come from two normal populations of unknown but equal variances.According to the theory, the average saving of buyers adopting a competitive strategy will be lower than that of buyers adopting a cooperative strategy.a) Specify the population identifications and the hypotheses H0 and H1…arrow_forwardYou assume that the annual incomes for certain workers are normal with a mean of $28,500 and a standard deviation of $2,400. What’s the chance that a randomly selected employee makes more than $30,000?What’s the chance that 36 randomly selected employees make more than $30,000, on average?arrow_forwardWhat’s the chance that a fair coin comes up heads more than 60 times when you toss it 100 times?arrow_forward
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