Explanation Result used: The vertex and the y -intercept of the quadratic function y = a x 2 + b x + c is ( − b 2 a , f ( − b 2 a ) ) and ( 0 , c ) . Description: Compare the equation y = x 2 − 4 with the general quadratic equation . y = a ↓ x 2 + b ↓ x + c ↓ y = 1 x 2 + 0 x − 4 From the above, the value of a , b and c are observed to be 1, 0 and −4, respectively. Compute the vertex as follows. Obtain the value of x -coordinate in ( − b 2 a , f ( − b 2 a ) ) . Substitute a = 1 and b = 0 in − b 2 a . − b 2 a = 0 2 ( 1 ) = 0 Thus, the x -coordinate of the vertex is 0 . Substitute x = 0 in y = x 2 − 4 and obtain the value of y -coordinate. y = 0 2 − 4 = − 4 Thus, the y -coordinate of the vertex is − 4 . So, the vertex is ( 0 , − 4 )

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 7.4, Problem 9E

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To sketch: The graph of the function y=x2−4 using the vertex, y-intercept and the x-intercept.

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Chapter 7.4, Problem 8E

Chapter 7.4, Problem 10E

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Ch. 7.1 - Solve for x: x2 + 4x − 21 = 0 Ch. 7.1 - Prob. 2PE Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E

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The graph of the function y = x 2 − 4 using the vertex, y -intercept and the x -intercept.

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Chapter 7 Solutions