To determine The character of the roots of the equation 3.6 t 2 + 2.1 = 7.7 t . Explanation Procedure used: “ Character of the Roots of a Quadratic Equation : 1. If b 2 − 4 a c is a positive and a perfect square, the roots are real, rational, and unequal. 2. If b 2 − 4 a c is a positive but not a perfect square, the roots are real, irrational, and unequal. 3. If b 2 − 4 a c = 0 , the roots are real, rational, and equal. 4. If b 2 − 4 a c < 0 , the roots contain imaginary numbers and are unequal. Therefore, there are no real roots.” Calculation: The given equation is 3.6 t 2 + 2.1 = 7.7 t . Rewrite the given equation into the general form of quadratic equation as 3.6 t 2 − 7.7 t + 2.1 = 0 . Compare the equation 3.6 t 2 − 7.7 t + 2.1 = 0 into the general second degree quadratic equation a t 2 + b t + c = 0 and obtain the value of a , b and c as follows: Thus, a = 3

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

11th Edition

ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 7.3, Problem 37E

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The character of the roots of the equation 3.6t2+2.1=7.7t.

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Chapter 7.3, Problem 36E

Chapter 7.3, Problem 38E

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Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 7.1 - Solve for x: x2 + 4x − 21 = 0 Ch. 7.1 - Prob. 2PE Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E

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