Understandable Statistics: Concepts and Methods
Understandable Statistics: Concepts and Methods
12th Edition
ISBN: 9781337119917
Author: Charles Henry Brase, Corrinne Pellillo Brase
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 7.3, Problem 13P

(a)

To determine

Find the point estimate for p.

(a)

Expert Solution
Check Mark

Answer to Problem 13P

The point estimate for p is 0.3100.

Explanation of Solution

Calculation:

Point estimate:

The point estimate for p is,

p^=rn

In the formula n is the number of trails, and r is the number of success.

Let p represent the proportion of all permanent dwellings on the entire NavajoReservation that are traditional hogans.

A random sample of 5,222 permanentdwellingsis considered in which1,619 were traditional Navajo hogans. Thatis n=5,222, r=1,619.

Substitute 1,619 as r, and 5,222 as n in the point estimate formula.

p^=1,6195,222=0.3100

Hence, the point estimate for p is 0.3100.

(b)

To determine

Find the 99% confidence interval for p.

Interpret the confidence interval.

(b)

Expert Solution
Check Mark

Answer to Problem 13P

The 99% confidence interval for p is 0.2935<p<0.3265.

Explanation of Solution

Calculation:

Confidence interval:

The confidence interval formula is,

p^E<p<p^+E

In the formula E=zcp^q^n, p^ is probability of success, q^ is probability of failure, n is the sample size, c is confidence level, and zc is critical value for confidence level c based on the standard normal distribution.

The confidence level is 99%.

Critical value:

Use the Appendix II: Tables, Table 5 (b): Confidence interval, Critical Values zc.

  • In the level of confidence c column, locate the value of 0.99, or 99%.
  • The correspondingCritical value zc is2.58.

The error is,

E=2.58(0.3100)(10.3100)5,222=2.58×0.0064=0.0165

Confidence interval:

Substitute p^ as 0.3100, E as 0.0165 in the confidence interval formula

0.31000.0165<p<0.3100+0.01650.2935<p<0.3265

Hence, the 99% confidence interval for p is 0.2935<p<0.3265.

The confidence interval can be interpreted as; there is 99% confidence that the population proportion of all permanent dwellings on the entire NavajoReservation that are traditional hogans lies within the interval 0.2935 to 0.3265.

(c)

To determine

Identify whether the conditions np^>5 and nq^>5 are satisfied or not.

Describe why satisfying conditions would be an important consideration.

(c)

Expert Solution
Check Mark

Explanation of Solution

Checking conditions:

np^=5,222(0.3100)=1,619>5

nq^=n(1p^)=5,222(10.3100)=5,222(0.6900)=3,603>5

It can be observed that two of the conditions np^>5, nq^>5 are satisfied.

Conditions for normal approximation to p^ distribution:

For a binomial experiment with n number of trails, r number of success, probability of success for each trail p^ and probability of failure q^=1p^, the p^=rn is approximated to a normal distribution if,

  • np^>5
  • nq^>5

The probability of success for each trail p^ is normally distributed with μ=p and σ=pqn when the conditions are satisfied. This shows that, it is necessary that the conditions np^>5 and nq^>5 must be satisfied to use approximation.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 7 Solutions

Understandable Statistics: Concepts and Methods

Ch. 7.1 - Basic Computation: Confidence Interval Suppose x...Ch. 7.1 - Basic Computation: Confidence Interval Suppose x...Ch. 7.1 - Basic Computation: Sample Size Suppose x has a...Ch. 7.1 - Basic Computation: Sample Size Suppose x has a...Ch. 7.1 - Zoology: Hummingbirds Allens hummingbird...Ch. 7.1 - Diagnostic Tests: Uric Acid Overproduction of uric...Ch. 7.1 - Diagnostic Tests: Plasma Volume Total plasma...Ch. 7.1 - Agriculture: Watermelon What price do farmers get...Ch. 7.1 - Prob. 19PCh. 7.1 - Confidence Intervals: Values of A random sample...Ch. 7.1 - Confidence Intervals: Sample Size A random sample...Ch. 7.1 - Ecology: Sand Dunes At wind speeds above 1000...Ch. 7.1 - Prob. 23PCh. 7.1 - Prob. 24PCh. 7.1 - Prob. 25PCh. 7.2 - Use Table 6 of Appendix II to find tc for a 0.95...Ch. 7.2 - Prob. 2PCh. 7.2 - Prob. 3PCh. 7.2 - Prob. 4PCh. 7.2 - Prob. 5PCh. 7.2 - Prob. 6PCh. 7.2 - Prob. 7PCh. 7.2 - Prob. 8PCh. 7.2 - Prob. 9PCh. 7.2 - Prob. 10PCh. 7.2 - Basic Computation: Confidence Interval Suppose x...Ch. 7.2 - Basic Computation: Confidence Interval A random...Ch. 7.2 - In Problems 1319, assume that the population of x...Ch. 7.2 - In Problems 1319, assume that the population of x...Ch. 7.2 - In Problems 1319, assume that the population of x...Ch. 7.2 - In Problems 1319, assume that the population of x...Ch. 7.2 - In Problems 1319, assume that the population of x...Ch. 7.2 - Prob. 18PCh. 7.2 - Prob. 19PCh. 7.2 - Prob. 20PCh. 7.2 - Prob. 21PCh. 7.2 - Prob. 22PCh. 7.2 - Prob. 23PCh. 7.3 - For all these problems, carry at least four digits...Ch. 7.3 - Prob. 2PCh. 7.3 - Prob. 3PCh. 7.3 - Prob. 4PCh. 7.3 - For all these problems, carry at least four digits...Ch. 7.3 - Prob. 6PCh. 7.3 - Prob. 7PCh. 7.3 - Prob. 8PCh. 7.3 - Prob. 9PCh. 7.3 - For all these problems, carry at least four digits...Ch. 7.3 - Prob. 11PCh. 7.3 - Prob. 12PCh. 7.3 - Prob. 13PCh. 7.3 - For all these problems, carry at least four digits...Ch. 7.3 - Prob. 15PCh. 7.3 - Prob. 16PCh. 7.3 - Prob. 17PCh. 7.3 - Prob. 18PCh. 7.3 - Prob. 19PCh. 7.3 - Prob. 20PCh. 7.3 - Prob. 21PCh. 7.3 - Prob. 22PCh. 7.3 - Prob. 23PCh. 7.3 - Prob. 24PCh. 7.3 - Prob. 25PCh. 7.3 - Prob. 26PCh. 7.3 - Prob. 27PCh. 7.3 - Prob. 28PCh. 7.4 - Prob. 1PCh. 7.4 - Prob. 2PCh. 7.4 - Prob. 3PCh. 7.4 - Prob. 4PCh. 7.4 - Prob. 5PCh. 7.4 - Prob. 6PCh. 7.4 - Prob. 7PCh. 7.4 - Prob. 8PCh. 7.4 - Prob. 9PCh. 7.4 - Prob. 10PCh. 7.4 - Prob. 11PCh. 7.4 - Prob. 12PCh. 7.4 - Prob. 13PCh. 7.4 - Prob. 14PCh. 7.4 - Prob. 15PCh. 7.4 - Prob. 16PCh. 7.4 - Answers may vary slightly due to rounding....Ch. 7.4 - Prob. 18PCh. 7.4 - Prob. 19PCh. 7.4 - Prob. 20PCh. 7.4 - Prob. 21PCh. 7.4 - Prob. 22PCh. 7.4 - Prob. 23PCh. 7.4 - Prob. 24PCh. 7.4 - Prob. 25PCh. 7.4 - Prob. 26PCh. 7.4 - Prob. 27PCh. 7.4 - Prob. 28PCh. 7.4 - Prob. 29PCh. 7.4 - Prob. 30PCh. 7.4 - Prob. 31PCh. 7 - Prob. 1CRPCh. 7 - Critical Thinking Suppose you are told that a 95%...Ch. 7 - Prob. 3CRPCh. 7 - Prob. 4CRPCh. 7 - Prob. 5CRPCh. 7 - For Problems 419, categorize each problem...Ch. 7 - Prob. 7CRPCh. 7 - For Problems 419, categorize each problem...Ch. 7 - Prob. 9CRPCh. 7 - For Problems 419, categorize each problem...Ch. 7 - For Problems 419, categorize each problem...Ch. 7 - For Problems 419, categorize each problem...Ch. 7 - Prob. 13CRPCh. 7 - Prob. 14CRPCh. 7 - Prob. 15CRPCh. 7 - For Problems 419, categorize each problem...Ch. 7 - Prob. 17CRPCh. 7 - Prob. 18CRPCh. 7 - Prob. 19CRPCh. 7 - Prob. 1DHCh. 7 - Prob. 2DHCh. 7 - Prob. 3DHCh. 7 - Prob. 1LCCh. 7 - Prob. 2LCCh. 7 - Prob. 3LCCh. 7 - Prob. 1UT
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Text book image
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Text book image
Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
Continuous Probability Distributions - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=QxqxdQ_g2uw;License: Standard YouTube License, CC-BY
Probability Density Function (p.d.f.) Finding k (Part 1) | ExamSolutions; Author: ExamSolutions;https://www.youtube.com/watch?v=RsuS2ehsTDM;License: Standard YouTube License, CC-BY
Find the value of k so that the Function is a Probability Density Function; Author: The Math Sorcerer;https://www.youtube.com/watch?v=QqoCZWrVnbA;License: Standard Youtube License