Program Explanation Given information: The function is F ( s ) = 5 − 2 s s 2 + 7 s + 10 . Explanation: The given function is F ( s ) = 5 − 2 s s 2 + 7 s + 10 . Apply inverse Laplace transform to the function F ( s ) = 5 − 2 s s 2 + 7 s + 10 . L − 1 { F ( s ) } = L − 1 { 5 − 2 s s 2 + 7 s + 10 } = L − 1 { 5 − 2 s s 2 + 5 s + 2 s + 10 } = L − 1 { 5 − 2 s s ( s + 5 ) + 2 ( s + 5 ) } = L − 1 { 5 − 2 s ( s + 5 ) ( s + 2 ) } Apply partial fraction method to solve the above expression, 5 − 2 s ( s + 5 ) ( s + 2 ) = A s + 2 + B s + 5 ........... (1) Multiply the equation by denominator as, ( 5 − 2 s ) ( s + 5 ) ( s + 2 ) ( s + 5 ) ( s + 2 ) = A ( s + 5 ) ( s + 2 ) s + 2 + B ( s + 5 ) ( s + 2 ) s + 5 5 − 2 s = A ( s + 5 ) + B ( s

5th Edition

ISBN: 9780135904206

Author: Edwards

Publisher: PEARSON

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Problems on Growing Functions

For a given set of functions f and g, the growth of functions states that the function g grows as fast as the function f. The growth rate of algorithms helps determine the algorithm's efficiency and compare its performance to other algorithms.

Question

Chapter 7.3, Problem 13P

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Program Description: Purpose of problem is to obtain the inverse Laplace transformation of the functions F(s)=5−2ss2+7s+10 by using partial fraction.

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Chapter 7.3, Problem 12P

Chapter 7.3, Problem 14P

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Chapter 7 Solutions

DIFFERENTIAL EQUATIONS+..-MYLAB ACCESS

Ch. 7.1 - Apply the definition in (1) to find directly tile...Ch. 7.1 - Prob. 2P Ch. 7.1 - Prob. 3P Ch. 7.1 - Prob. 4P Ch. 7.1 - Prob. 5P Ch. 7.1 - Prob. 6P Ch. 7.1 - Prob. 7P Ch. 7.1 - Prob. 8P Ch. 7.1 - Prob. 9P Ch. 7.1 - Prob. 10P

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Program Description: Purpose of problem is to obtain the inverse Laplace transformation of the functions F ( s ) = 5 − 2 s s 2 + 7 s + 10 by using partial fraction.

Solution Summary: The author explains how to obtain the inverse Laplace transformation of the functions by using partial tion.

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Program Description: Purpose of problem is to obtain the inverse Laplace transformation of the functions F(s)=5−2ss2+7s+10 by using partial fraction.

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Chapter 7 Solutions