Chapter 7.2, Problem B7.2P

(a)

Interpretation Introduction

Interpretation:

The frequency and colour of the light associated with the element $\text{Li}$ of wavelength $\lambda =671\text{ nm}$ is to be determined.

Concept introduction:

The equation that relates to the frequency and wavelength of electromagnetic radiation is as follows:

$\nu =\frac{c}{\lambda }$        (1)

Here,

$c$ is the speed of light.

$\lambda$ is the wavelength.

The conversion factor to convert wavelength from $\text{nm}$ to $\text{m}$ is,

$1\text{nm}=1\times {10}^{-9}\text{ m}$

(b)

Interpretation Introduction

Interpretation:

The frequency and colour of the light associated with the ion ${\text{Cs}}^{+}$ of wavelength $\lambda =453\text{ nm}$ is to be determined.

Concept introduction:

The equation that relates to the frequency and wavelength of electromagnetic radiation is as follows:

$\nu =\frac{c}{\lambda }$        (1)

Here,

$c$ is the speed of light.

$\lambda$ is the wavelength.

The conversion factor to convert wavelength from $\text{nm}$ to $\text{m}$ is,

$1\text{nm}=1\times {10}^{-9}\text{ m}$

(c)

Interpretation Introduction

Interpretation:

The frequency and colour of the light associated with the element $\text{Na}$ of wavelength $\lambda =589\text{ nm}$ is to be determined.

Concept introduction:

The equation that relates to the frequency and wavelength of electromagnetic radiation is as follows:

$\nu =\frac{c}{\lambda }$        (1)

Here,

$c$ is the speed of light.

$\lambda$ is the wavelength.

The conversion factor to convert wavelength from $\text{nm}$ to $\text{m}$ is,

$1\text{nm}=1\times {10}^{-9}\text{ m}$