ELECTRICITY FOR TRADES (LOOSELEAF)
ELECTRICITY FOR TRADES (LOOSELEAF)
3rd Edition
ISBN: 9781260437454
Author: Petruzella
Publisher: MCG
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Chapter 7.2, Problem 5RQ

A resistor has a resistance of 220 Ω. The current flow through the resistor is measured and found to be 30 mA. What is the value of the voltage across the resistor?

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I need a detailed solution to a problem. The far-zone electric field intensity (array factor) of an end-fire two-element array antenna, placed along the z-axis and radiating into free-space, is given by E=cos (cos - 1) Find the directivity using (a) Kraus' approximate formula (b) the DIRECTIVITY computer program at the end of this chapter Repeat Problem 2.19 when E = cos -jkr 0505π $[ (cos + 1) (a). Elmax = Cost (case-1)] | max" = 1 at 8-0°. 0.707 Emax = 0.707.(1) = cos [(cose,-1)] (cose-1) = ± 0,= {Cos' (2) = does not exist (105(0)= 90° = rad. Bir Do≈ 4T ar=2() = = Bar 4-1-273 = 1.049 dB T₂ a. Elmax = cos((cose +1)), 0.707 = cos (Close,+1)) = 1 at 6 = π Imax (Cose+1)=== G₁ = cos(-2) does not exist. Girar=2()=π. 4T \cos (0) + 90° + rad Do≈ = +=1.273=1.049dB IT 2
I need an expert mathematical solution. The E-field pattern of an antenna. independent of , varies as follows: 0° ≤ 0≤ 45° E = 0 45° {1 90° 90° < 0 ≤ 180° (a) What is the directivity of this antenna? (b) What is the radiation resistance of the antenna at 200 m from it if the field is equal to 10 V/m (rms) for Ø = 0° at that distance and the terminal current is 5 A (rms)?
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