Explanation Given: Circle passing through point ( − 3 , − 4 ) and center is ( 0 , 0 ) . Formula Used: Standard form of circle equation ( x − h ) 2 + ( y − k ) 2 = r 2 . Distance between two points ( x 1 , y 1 ) and ( x 2 , y 2 ) is ( x 1 − x 2 ) 2 + ( y 1 − y 2 ) 2 . Calculation: Equation of circle with Center ( h , k ) and radius r is ( x − h ) 2 + ( y − k ) 2 = r 2

College Algebra Plus New Mymathlab With Pearson Etext Access Card

6th Edition

ISBN: 9780321919748

Author: Mark Dugopolski

Publisher: PEARSON

See similar textbooks

Question

Chapter 7.2, Problem 46E

To determine

To calculate: The equation of circle for center (0,0) and passing through point (−3,−4).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 7.2, Problem 45E

Chapter 7.2, Problem 47E

Students have asked these similar questions

1.2.19. Let and s be natural numbers. Let G be the simple graph with vertex set Vo... V„−1 such that v; ↔ v; if and only if |ji| Є (r,s). Prove that S has exactly k components, where k is the greatest common divisor of {n, r,s}.

Question 3 over a field K. In this question, MË(K) denotes the set of n × n matrices (a) Suppose that A Є Mn(K) is an invertible matrix. Is it always true that A is equivalent to A-¹? Justify your answer. (b) Let B be given by 8 B = 0 7 7 0 -7 7 Working over the field F2 with 2 elements, compute the rank of B as an element of M2(F2). (c) Let 1 C -1 1 [4] [6] and consider C as an element of M3(Q). Determine the minimal polynomial mc(x) and hence, or otherwise, show that C can not be diagonalised. [7] (d) Show that C in (c) considered as an element of M3(R) can be diagonalised. Write down all the eigenvalues. Show your working. [8]

R denotes the field of real numbers, Q denotes the field of rationals, and Fp denotes the field of p elements given by integers modulo p. You may refer to general results from lectures. Question 1 For each non-negative integer m, let R[x]m denote the vector space consisting of the polynomials in x with coefficients in R and of degree ≤ m. x²+2, V3 = 5. Prove that (V1, V2, V3) is a linearly independent (a) Let vi = x, V2 = list in R[x] 3. (b) Let V1, V2, V3 be as defined in (a). Find a vector v € R[×]3 such that (V1, V2, V3, V4) is a basis of R[x] 3. [8] [6] (c) Prove that the map ƒ from R[x] 2 to R[x]3 given by f(p(x)) = xp(x) — xp(0) is a linear map. [6] (d) Write down the matrix for the map ƒ defined in (c) with respect to the basis (2,2x + 1, x²) of R[x] 2 and the basis (1, x, x², x³) of R[x] 3. [5]

Chapter 7 Solutions

College Algebra Plus New Mymathlab With Pearson Etext Access Card

Ch. 7.1 - True or False? Explain. A parabola with focus (0,...Ch. 7.1 - Prob. 2FT Ch. 7.1 - Prob. 3FT Ch. 7.1 - Prob. 4FT Ch. 7.1 - Prob. 5FT Ch. 7.1 - Prob. 6FT Ch. 7.1 - Prob. 7FT Ch. 7.1 - Prob. 8FT Ch. 7.1 - Prob. 9FT Ch. 7.1 - Prob. 10FT

Knowledge Booster

The equation of circle for center ( 0 , 0 ) and passing through point ( − 3 , − 4 ) .

Solution Summary: The author calculates the equation of circle for center (0,0) and passing through point (-3,-4)

To calculate: The equation of circle for center (0,0) and passing through point (−3,−4).

Want to see the full answer?

Chapter 7 Solutions