Among CH 3 3 CBr and CD 3 3 CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted. Concept Introduction : When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C − H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

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Answer 1

Question

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

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esc Write the systematic name of each organic molecule: structure CH3 CH3-C=CH2 CH3-CH2-C-CH2-CH3 CH-CH3 CH3 ☐ ☐ ☐ CI-CH-CH=CH2 Explanation Check F1 F2 name 80 F3 F4 F5 F6 A 7 ! 2 # 3 4 % 5 6 & 7 Q W E R Y FT 2025 Mc

Two reactants X and Z are required to convert the compound CH3-CH2-CH2Br to the compound CH3-CH2-CH=P(C6H5)3. State reactants X and Z.

2. Write a reasonable mechanism that converts the reactants into the products. Avoid issues A-U from the previous page. You can use any number of steps (it does not have to be a one-step mechanism). Do not use any other chemicals (solvents, acids, bases, etc.) in your mechanism. 2 2 H ΗΘ

Answer 2

Question

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

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Answer 3

Question

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

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Answer 4

Question

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

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Answer 5

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 6

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 7

Chapter 7.12, Problem 45CC

(a)

Interpretation Introduction

Interpretation:

Among CH33CBr and CD33CBr , the compound which will undergo a more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Among CH32CDBr and CD32CHBr which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 11

(c)

Interpretation Introduction

Interpretation:

Among CH3CD2Cl and CD3CH2Cl which will undergo more rapid elimination reaction in presence of strong base is to be interpreted.

Concept Introduction :

When bond breaking is directly associated with isotopes used in the rate-determining phase, the principal isotope effect is seen. The C-D bond is stronger than a C−H bond. Tertiary alkyl halide undergoes E2 reaction in presence of strong base.

Answer 12

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Answer 14

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Answer 15

Ch. 7.2 - Prob. 1CC Ch. 7.3 - Prob. 2CC Ch. 7.3 - Prob. 1LTS Ch. 7.3 - Prob. 3PTS Ch. 7.3 - Prob. 4ATS Ch. 7.3 - Prob. 2LTS Ch. 7.3 - Prob. 5PTS Ch. 7.3 - Prob. 6ATS Ch. 7.3 - Prob. 7CC Ch. 7.4 - Prob. 8CC

Solution Summary: The author analyzes how bond breaking is directly associated with isotopes used in the rate-determining phase.

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