Given points P r 1 , θ 1 and Q r 2 , θ 2 represented in polar coordinates with θ 1 ≠ θ 2 and r 1 > 1 and r 2 > 0 , use the law of cosines to show that the distance d between P and Q is given by d = r 1 2 + r 2 2 − 2 r 1 r 2 cos θ 2 − θ 1 .
Given points P r 1 , θ 1 and Q r 2 , θ 2 represented in polar coordinates with θ 1 ≠ θ 2 and r 1 > 1 and r 2 > 0 , use the law of cosines to show that the distance d between P and Q is given by d = r 1 2 + r 2 2 − 2 r 1 r 2 cos θ 2 − θ 1 .
Solution Summary: The author analyzes the distance d between PandQ, using the law of cosine.
Given points
P
r
1
,
θ
1
and
Q
r
2
,
θ
2
represented in polar coordinates with
θ
1
≠
θ
2
and
r
1
>
1
and
r
2
>
0
, use the law of cosines to show that the distance d between P and Q is given by
d
=
r
1
2
+
r
2
2
−
2
r
1
r
2
cos
θ
2
−
θ
1
.
Given lim x-4 f (x) = 1,limx-49 (x) = 10, and lim→-4 h (x) = -7 use the limit properties
to find lim→-4
1
[2h (x) — h(x) + 7 f(x)] :
-
h(x)+7f(x)
3
O DNE
17. Suppose we know that the graph below is the graph of a solution to dy/dt = f(t).
(a) How much of the slope field can
you sketch from this information?
[Hint: Note that the differential
equation depends only on t.]
(b) What can you say about the solu-
tion with y(0) = 2? (For example,
can you sketch the graph of this so-
lution?)
y(0) = 1
y
AN
(b) Find the (instantaneous) rate of change of y at x = 5.
In the previous part, we found the average rate of change for several intervals of decreasing size starting at x = 5. The instantaneous rate of
change of fat x = 5 is the limit of the average rate of change over the interval [x, x + h] as h approaches 0. This is given by the derivative in the
following limit.
lim
h→0
-
f(x + h) − f(x)
h
The first step to find this limit is to compute f(x + h). Recall that this means replacing the input variable x with the expression x + h in the rule
defining f.
f(x + h) = (x + h)² - 5(x+ h)
=
2xh+h2_
x² + 2xh + h² 5✔
-
5
)x - 5h
Step 4
-
The second step for finding the derivative of fat x is to find the difference f(x + h) − f(x).
-
f(x + h) f(x) =
= (x²
x² + 2xh + h² -
])-
=
2x
+ h² - 5h
])x-5h) - (x² - 5x)
=
]) (2x + h - 5)
Macbook Pro
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Polar Coordinates Basic Introduction, Conversion to Rectangular, How to Plot Points, Negative R Valu; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=aSdaT62ndYE;License: Standard YouTube License, CC-BY