For Exercises 43–56, write the standard form of an equation of an ellipse subject to the given conditions. (See Example 5)
Vertices:
Foci:
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COLLEGE ALGEBRA - ALEKS 360
- For Exercises 27–34, an equation of a parabola x = 4py or y = 4px is given. a. Identify the vertex, value of p, focus, and focal diameter of the parabola. b. Identify the endpoints of the latus rectum. c. Graph the parabola. d. Write equations for the directrix and axis of symmetry. (See Examples 2-3) 27. x -4y 28. x -20y 29. 10y = 80x 30. 3y = 12x 31. 4x 40y 32. 2x 14y 33. y = 34. y = -2x = -X %3Darrow_forwardWhich are the foci for the hyperbola modeled by the equation (X-32 (x-1)²-1? 36 13 O (1. 10) and (1,-4) O (3.8) and (3, -8) O (1.9) and (1, -3) O (-6, 0) and (6, 0)arrow_forward3) Explain how changing the a, h, and k variables affect the shape of the parabola in the vertex form y = a(x - h)² + k. [3 Communication Marks] Page 1arrow_forward
- 2. Suppose that the last three digits of your student number are like. abc . It is not important whether it is a 4 digit number or a 5 digit number, take the last three :+(-1) ; (b+1)3 digits as abc. Consider the conic (-1)ª following. Major semiaxis Minor semiaxis (-1)ab. Find the %3D (a+1)a i. ii. iii. Vertices iv. Foci Eccentricity Directrices Asymptotes (if it is a hyperbola) and the graph (geogebra or nice handmade) V. vi. vii. Now, consider the Quadratic Surface (-1)ª. (a+1)a +(-1) + (-1)° (b+1) =(-1)abe. (c+1)2 Find the following. Name of the surface viii. ix. Traces of the surface Nice Graph (in GeoGebra or handmade) х. For example, your professor's ID number is 0000005121. So, he will study the conic (-1) + (-1) =(-1)*2 which gives (-) + (-1)', (1+1) = (-1)12 which gives (-) + = 1. Also he will (2+1)3 4 study the quadratic surface (-1)' (1+1)2 + (-1)² - (2+1)a + (-1)'; :(-1)121 (1+1) which gives. (-) + + (-÷) = 1.arrow_forwardIn Exercises 51-60, convert each equation to standard form by completing the square on x and y. Then graph the ellipse and give the location of its foci. 51. 9x? + 25y? – 36x + 50y – 164 = 0 52. 4x + 9y? - 32x + 36y + 64 = 0 53. 9x? + 16y? - 18x + 64y - 71 = 0 54. x + 4y? + 10x 8y + 13 = 0 55. 4x2 + y? + 16x – 6y – 39 = 0 56. 4x + 25y? – 24x + 100y + 36 = 0 57. 25x + 4y - 150x + 32y + 189 = 0 %3D 58. 49x? + 16y² + 98x – 64y - 671 = 0 59. 36x? + 9y2 - 216x = 0 %3! 60. 16x? + 25y² – 300y + 500 = 0 %3Darrow_forwardIn Exercises 17-30, find the standard form of the equation of each parabola satisfying the given conditions. 17. Focus: (7,0); Directrix: x = -7 18. Focus: (9,0); Directrix: x = -9 19. Focus: (-5,0); Directrix: x = 5 20. Focus: (-10, 0); Directrix: x = 10 21. Focus: (0, 15); Directrix: y = -15 22. Focus: (0,20); Directrix: y = -20 23. Focus: (0, –25); Directrix: y = 25 24. Focus: (0, -15); Directrix: y = 15 25. Vertex: (2, -3); Focus: (2, -5) 26. Vertex: (5, -2); Focus: (7, -2) 27. Focus: (3, 2); Directrix: x = -1 28. Focus: (2, 4); Directrix: x = -4 29. Focus: (-3, 4); Directrix: y = 2 30. Focus: (7, –1); Directrix: y = -9arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage