Concept explainers
(a)
Section 1:
To find: The difference between the TBBMC recorded for Operator 1 and the TBBMC for Operator 2.
(a)
Section 1:

Answer to Problem 43E
Solution: The table for difference is as follows:
Operator 1 |
Operator 2 |
Difference |
1.328 |
1.323 |
0.005 |
1.342 |
1.322 |
0.02 |
1.075 |
1.073 |
0.002 |
1.228 |
1.233 |
−0.005 |
0.939 |
0.934 |
0.005 |
1.004 |
1.019 |
−0.015 |
1.178 |
1.184 |
−0.006 |
1.286 |
1.304 |
−0.018 |
Explanation of Solution
Calculation:
To calculate the difference, follow the below mentioned steps in Minitab:
Step 1: Enter the variable name as “Operator 1” in column C1 and enter the data for “Operator 1” and enter the variable name as “Operator 2” in column C2 and enter the data for “Operator 2.”
Step 2: Enter variable name as “Difference” in column C3.
Step 3: Go to
Step 4: In the dialog box that appears, select “Difference” in “Store result in variable.”
Step 5: Enter “Operator 1”-“Operator 2” in “Expression.” Click on “Ok” on the dialog box.
From Minitab result, the table for difference is as follows:
Operator 1 |
Operator 2 |
Difference |
1.328 |
1.323 |
0.005 |
1.342 |
1.322 |
0.02 |
1.075 |
1.073 |
0.002 |
1.228 |
1.233 |
−0.005 |
0.939 |
0.934 |
0.005 |
1.004 |
1.019 |
−0.015 |
1.178 |
1.184 |
−0.006 |
1.286 |
1.304 |
−0.018 |
Interpretation: It is clear from the table that the
Section 2:
To test: Whether t- methods can be used or not.
Section 2:

Answer to Problem 43E
Solution: The t- method can be used.
Explanation of Solution
Calculation:
To determine if the t methods can be used or not, a probability plot is drawn in Minitab by following the below mentioned steps:
Step 1: Follow steps 1 and 2 similar to that in Section 1.
Step 2: Go to “Graph” option and click on “Probability Plot.” In the dialog box that appears, select “Single” and click on OK.
Step 3: Then enter the name of the column containing the data of the differences in the “Graph variables” field and click on OK.
The following probability plot is obtained:
Conclusion: The probability plot shows that the data is approximately normal as all the data points fall within the range and, hence, it is appropriate to use t procedures.
(b)
To test: The significance of the difference between the means of two operators.
(b)

Answer to Problem 43E
Solution: The test statistic value is
Explanation of Solution
Calculation:
To test the null hypothesis, follow the below mentioned steps in Minitab:
Step 1: Follow the Steps 1 to 5 performed in section 1 of part (a).
Step 2: Go to
Step 3: In the dialogue box that appears, select samples in columns.
Step 4: Enter “Operator 1” under the field marked as “First sample” and “Operator 2” under the field marked as “Second sample.”
Step 5: In the dialogue box that appears, Click on “Option.” Enter 95.0 in the field of Confidence interval, 0.0 in “Test mean,” and “not equal” in “Alternative.”
From Minitab results, the value of test statistic is
D.F = n –.
D.F = 8 –.
D.F =.
Conclusion: If the level of significance is 5% then as the p- value is greater than 0.05 the null hypothesis will not be rejected and it is concluded that the two means do not differ significantly at 95% confidence level.
(c)
To find: The confidence interval for difference.
(c)

Answer to Problem 43E
Solution: The required confidence interval is
Explanation of Solution
Calculation: To compute the confidence interval, follow the below mentioned steps in Minitab:
Step 1: Follow the steps 1 to 5 performed in section 1 of part (a).
Step 2: Go to
Step 3: In the dialogue box that appears, select samples in columns.
Step 4: Enter “Operator 1” under the field marked as “First sample” and “Operator 2” under the field marked as “Second sample.”
Step 5: In the dialogue box that appears, Click on “Option.” Enter 95.0 in the field of Confidence interval, 0.0 in “Test mean,” and “not equal” in “Alternative.”
From the Minitab results, the confidence interval is
Interpretation: The confidence interval denotes that the differences recorded will lie in between −0.01172 and 0.00872 with a possible chance of 5% error.
(d)
The validity of the results if the samples are not random.
(d)

Answer to Problem 43E
Solution: The testing results and the confidence interval may not be valid if the samples are non-random.
Explanation of Solution
Want to see more full solutions like this?
Chapter 7 Solutions
EBK INTRODUCTION TO THE PRACTICE OF STA
- Hi, I need to sort out where I went wrong. So, please us the data attached and run four separate regressions, each using the Recruiters rating as the dependent variable and GMAT, Accept Rate, Salary, and Enrollment, respectively, as a single independent variable. Interpret this equation. Round your answers to four decimal places, if necessary. If your answer is negative number, enter "minus" sign. Equation for GMAT: Ŷ = _______ + _______ GMAT Equation for Accept Rate: Ŷ = _______ + _______ Accept Rate Equation for Salary: Ŷ = _______ + _______ Salary Equation for Enrollment: Ŷ = _______ + _______ Enrollmentarrow_forwardQuestion 21 of 28 (1 point) | Question Attempt: 5 of Unlimited Dorothy ✔ ✓ 12 ✓ 13 ✓ 14 ✓ 15 ✓ 16 ✓ 17 ✓ 18 ✓ 19 ✓ 20 = 21 22 > How many apps? According to a website, the mean number of apps on a smartphone in the United States is 82. Assume the number of apps is normally distributed with mean 82 and standard deviation 30. Part 1 of 2 (a) What proportion of phones have more than 47 apps? Round the answer to four decimal places. The proportion of phones that have more than 47 apps is 0.8783 Part: 1/2 Try again kip Part ی E Recheck == == @ W D 80 F3 151 E R C レ Q FA 975 % T B F5 10 の 000 园 Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Y V& U H J N * 8 M I K O V F10 P = F11 F12 . darrow_forwardYou are provided with data that includes all 50 states of the United States. Your task is to draw a sample of: 20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample) 10 States using Systematic Sampling (4 points: 1 for random numbers generation; 1 for generating random sample different from the previous answer; 1 for correct K value calculation table; 1 for correct sample drawn by using systematic sampling) (For systematic sampling, do not use the original data directly. Instead, first randomize the data, and then use the randomized dataset to draw your sample. Furthermore, do not use the random list previously generated, instead, generate a new random sample for this part. For more details, please see the snapshot provided at the end.) You are provided with data that includes all 50 states of the United States. Your task is to draw a sample of: o 20 States using Random Sampling (2 points: 1 for random number generation; 1 for random sample) o…arrow_forward
- Course Home ✓ Do Homework - Practice Ques ✓ My Uploads | bartleby + mylab.pearson.com/Student/PlayerHomework.aspx?homeworkId=688589738&questionId=5&flushed=false&cid=8110079¢erwin=yes Online SP 2025 STA 2023-009 Yin = Homework: Practice Questions Exam 3 Question list * Question 3 * Question 4 ○ Question 5 K Concluir atualização: Ava Pearl 04/02/25 9:28 AM HW Score: 71.11%, 12.09 of 17 points ○ Points: 0 of 1 Save Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S. Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b). Click the icon to view the ANSUR data. a. Use a 0.05 significance level to test the claim that the mean weight of the 1988…arrow_forwardsolving problem 1arrow_forwardselect bmw stock. you can assume the price of the stockarrow_forward
- This problem is based on the fundamental option pricing formula for the continuous-time model developed in class, namely the value at time 0 of an option with maturity T and payoff F is given by: We consider the two options below: Fo= -rT = e Eq[F]. 1 A. An option with which you must buy a share of stock at expiration T = 1 for strike price K = So. B. An option with which you must buy a share of stock at expiration T = 1 for strike price K given by T K = T St dt. (Note that both options can have negative payoffs.) We use the continuous-time Black- Scholes model to price these options. Assume that the interest rate on the money market is r. (a) Using the fundamental option pricing formula, find the price of option A. (Hint: use the martingale properties developed in the lectures for the stock price process in order to calculate the expectations.) (b) Using the fundamental option pricing formula, find the price of option B. (c) Assuming the interest rate is very small (r ~0), use Taylor…arrow_forwardDiscuss and explain in the picturearrow_forwardBob and Teresa each collect their own samples to test the same hypothesis. Bob’s p-value turns out to be 0.05, and Teresa’s turns out to be 0.01. Why don’t Bob and Teresa get the same p-values? Who has stronger evidence against the null hypothesis: Bob or Teresa?arrow_forward
- Review a classmate's Main Post. 1. State if you agree or disagree with the choices made for additional analysis that can be done beyond the frequency table. 2. Choose a measure of central tendency (mean, median, mode) that you would like to compute with the data beyond the frequency table. Complete either a or b below. a. Explain how that analysis can help you understand the data better. b. If you are currently unable to do that analysis, what do you think you could do to make it possible? If you do not think you can do anything, explain why it is not possible.arrow_forward0|0|0|0 - Consider the time series X₁ and Y₁ = (I – B)² (I – B³)Xt. What transformations were performed on Xt to obtain Yt? seasonal difference of order 2 simple difference of order 5 seasonal difference of order 1 seasonal difference of order 5 simple difference of order 2arrow_forwardCalculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





