EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
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Question
Chapter 7, Problem P7P
Program Plan Intro
IEEE 802.11:
- IEEE 802.11 stands for wireless LAN that was ratified by the Institute of Electrical and Electronics Engineering.
- There are many 802.11 standards for wireless LAN technology in the IEEE 802.11. The different 802.11 standards all share some common characteristics.
- Basic service set (BSS) is a fundamental building block of 802.11 architecture. The BSS also known as Access Point (AP).
- Every wireless station in 802.11 wants to associate with an access point before it can send or receive network layer data.
DIFS:
DIFS stands for DCF Interframe Spacing. It is a time delay for which sender wait after finishing its back off, previously sending RTS package.
SIFS:
SIFS stands for Shortest Interframe Spacing and it is consider as shortest among above mention networking technology.
Request to send (RTS)/ clear to send (CTS):
- The optimal
mechanism used by the IEEE 802.11 is RTS. This is used to decreasing the frame collisions which was introduced by the hidden node problem. - In order to avoid the collisions problem, the IEEE 802.11 protocol allows a station to use Request to Send (RTS) and Clear to Send (CTS) control frames to reserve access to the channel.
- When a sender want to send a data frame, it can initial send an RTS frame to the AP. After AP receives the RTS frame, it will responds by broadcasting a CTS frame.
Expert Solution & Answer
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Suppose that a SW ARQ system with 1-bit sequence numbering has a time-out value
that is less than the time required to receive an ACK. Station A sends 5 frames to station
B. No errors occur during transmission of all 5 frames. One ACK is lost when it is
transmitted the first time (see the following table), and no
transmission of that ACK. No errors occur during transmission of the other 4 ACKS.
Sketch the sequence of frame exchanges that transpire between stations A and B.
(а)
error occurs in re-
Last digit of your student ID number
0, 1
2, 3
Lost ACK
1
4, 5
6, 7
8, 9
2
3
4
Compute the fraction of the bandwidth
that is wasted on overhead (headers
and retransmissions) for sliding
window protocol using selective
repeat on a heavily loaded 50 kbps
satellite channel with data frames
consisting of 40 header and 3960 data
bits. ACK frames never occur. NAK
frames are 40-bits. The error rate for
data frames is 1 percent and the error
rate for NAK frames is negligible. The
sequence numbers are 8-bits.
Frames of 1000 bits are sent over a 106 bps duplex link between two hosts. The propagation time is 25 ms. Frames are to be transmitted into this link to maximally pack them in transit (within the link).
1.1 What is the minimum number of bits (1) that will be required to represent the sequence numbers distinctly? Assume that no time gap needs to be given between transmission of two frames.
Chapter 7 Solutions
EBK COMPUTER NETWORKING
Ch. 7 - Prob. R1RQCh. 7 - Prob. R2RQCh. 7 - Prob. R3RQCh. 7 - Prob. R4RQCh. 7 - Prob. R5RQCh. 7 - Prob. R6RQCh. 7 - Prob. R7RQCh. 7 - Prob. R8RQCh. 7 - Prob. R9RQCh. 7 - Prob. R10RQ
Ch. 7 - Prob. R11RQCh. 7 - Prob. R12RQCh. 7 - Prob. R13RQCh. 7 - Prob. R14RQCh. 7 - Prob. R15RQCh. 7 - Prob. R16RQCh. 7 - Prob. R17RQCh. 7 - Prob. R18RQCh. 7 - Prob. R19RQCh. 7 - Prob. R20RQCh. 7 - Prob. R21RQCh. 7 - Prob. R22RQCh. 7 - Prob. R23RQCh. 7 - Prob. P1PCh. 7 - Prob. P2PCh. 7 - Prob. P3PCh. 7 - Prob. P5PCh. 7 - Prob. P6PCh. 7 - Prob. P7PCh. 7 - Prob. P8PCh. 7 - Prob. P10PCh. 7 - Prob. P11PCh. 7 - Prob. P12PCh. 7 - Prob. P13PCh. 7 - Prob. P14PCh. 7 - Prob. P15PCh. 7 - Prob. P16P
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