EBK COMPUTER NETWORKING
7th Edition
ISBN: 8220102955479
Author: Ross
Publisher: PEARSON
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Question
Chapter 7, Problem P16P
Program Plan Intro
MSC:
- MSC stands for Mobile Switching Center that will connects calls by switching the digital voice data packets from one network to another network.
- It will also give the data that is required to support mobile service benefactors.
HLR in GSM network:
- The HLR stands for Home Location Register; it is the reference
database for benefactor parameters. - The Home Location Register is an integral component of Time Division Multiple Access (TDMA), Code Division Multiple Access (CDMA) and Global System for Mobile Communications (GSM) network.
- It maintain the benefactor information like user name, address, account status, phone number etc.
- If the mobile user is currently roaming in another network, the HLR contains enough data to obtain an address in the visited network to which a call to the mobile user should be routed.
VLR in GSM network:
- The VLR stands for Visitor Location Register; it has a copy of the data which is stored at the HLR.
- The database of VLR contains some duplicate data and also more precise data related to the benefactor remaining contained by the VLR coverage.
- The VLR entries come and go as mobile users enter and leave the network.
- It is normally co-located with the MSC that coordinates the setup of a call from and to the visited network.
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Students have asked these similar questions
Problem 3: Consider the two-link planar elbow manipulator shown below with link information: a₁ = 3,
a₂ = 3.
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(a) Find the location of the end-effector P° if the joint angles are:
0₁ = 140°, 0₂ = 30°
(b) Find the values of joint variables 01, 02 if the robotic manipulator is commanded to reach the desired
location of Pº = [4.5, 3,0]. Notice there are possibly two sets of solutions.
(c) Also sketch the two poses of the robot for the computed joint variables.
Page 5 of 7
Problem 5: The following shows the schematic of a SCARA robot and its DH parameters. Complete the
following questions based on this information.
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The Jacobian matrix of this robot is given below:
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(a) For a₁ = 1, a2 = 2, is q = 180° a singularity configuration of this robot?
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(b) For a₁ = 1, a2 = 2, is q = | 0° a singularity configuration of this robot?
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(c) Consider the following sequence of rotations:
1) Rotate by 130° about the world z-axis
2) Rotate by 45° about the current x-axis
3) Rotate by -30° about the world/fixed y-axis
Compute the resulting overall rotation matrix R. Notice that you need to provide the numerical
solution to the matrix R.
(d) Find R giving the following rotation matrices.
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Chapter 7 Solutions
EBK COMPUTER NETWORKING
Ch. 7 - Prob. R1RQCh. 7 - Prob. R2RQCh. 7 - Prob. R3RQCh. 7 - Prob. R4RQCh. 7 - Prob. R5RQCh. 7 - Prob. R6RQCh. 7 - Prob. R7RQCh. 7 - Prob. R8RQCh. 7 - Prob. R9RQCh. 7 - Prob. R10RQ
Ch. 7 - Prob. R11RQCh. 7 - Prob. R12RQCh. 7 - Prob. R13RQCh. 7 - Prob. R14RQCh. 7 - Prob. R15RQCh. 7 - Prob. R16RQCh. 7 - Prob. R17RQCh. 7 - Prob. R18RQCh. 7 - Prob. R19RQCh. 7 - Prob. R20RQCh. 7 - Prob. R21RQCh. 7 - Prob. R22RQCh. 7 - Prob. R23RQCh. 7 - Prob. P1PCh. 7 - Prob. P2PCh. 7 - Prob. P3PCh. 7 - Prob. P5PCh. 7 - Prob. P6PCh. 7 - Prob. P7PCh. 7 - Prob. P8PCh. 7 - Prob. P10PCh. 7 - Prob. P11PCh. 7 - Prob. P12PCh. 7 - Prob. P13PCh. 7 - Prob. P14PCh. 7 - Prob. P15PCh. 7 - Prob. P16P
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