Bundle: Enhanced Discovering Computers ©2017, Loose-leaf Version + LMS Integrated MindTap Computing, 1 term (6 months) Printed Access Card
Bundle: Enhanced Discovering Computers ©2017, Loose-leaf Version + LMS Integrated MindTap Computing, 1 term (6 months) Printed Access Card
1st Edition
ISBN: 9781337351911
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher: Cengage Learning
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Chapter 7, Problem 9SG
Program Plan Intro

Input:

  • Any data and instructions entered into the memory of a computer are input.
  • Some input devices are mouse, keyboard, touch screen, data collective device, MICR characters, stylus, graphics tablet, touch-sensitive pad, magnetic stripe card reader, game controller, microphone, and webcam.

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Please run and debug the following program and answer the questions.
(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.

Chapter 7 Solutions

Bundle: Enhanced Discovering Computers ©2017, Loose-leaf Version + LMS Integrated MindTap Computing, 1 term (6 months) Printed Access Card

Ch. 7 - Prob. 12SGCh. 7 - Prob. 13SGCh. 7 - Prob. 14SGCh. 7 - Prob. 15SGCh. 7 - Prob. 16SGCh. 7 - Prob. 17SGCh. 7 - Prob. 18SGCh. 7 - Prob. 19SGCh. 7 - Prob. 20SGCh. 7 - Prob. 21SGCh. 7 - Prob. 22SGCh. 7 - Prob. 23SGCh. 7 - Prob. 24SGCh. 7 - Prob. 25SGCh. 7 - Prob. 26SGCh. 7 - Prob. 27SGCh. 7 - Prob. 28SGCh. 7 - Prob. 29SGCh. 7 - Prob. 30SGCh. 7 - Prob. 31SGCh. 7 - Prob. 32SGCh. 7 - Prob. 33SGCh. 7 - Prob. 34SGCh. 7 - Prob. 35SGCh. 7 - Prob. 36SGCh. 7 - Prob. 37SGCh. 7 - Prob. 38SGCh. 7 - Prob. 39SGCh. 7 - Prob. 40SGCh. 7 - Prob. 41SGCh. 7 - Prob. 42SGCh. 7 - Prob. 43SGCh. 7 - Prob. 44SGCh. 7 - Prob. 45SGCh. 7 - Prob. 46SGCh. 7 - Prob. 47SGCh. 7 - Prob. 48SGCh. 7 - Prob. 49SGCh. 7 - Prob. 1TFCh. 7 - Prob. 2TFCh. 7 - Prob. 3TFCh. 7 - Prob. 4TFCh. 7 - Prob. 5TFCh. 7 - Prob. 6TFCh. 7 - Prob. 7TFCh. 7 - Prob. 8TFCh. 7 - Prob. 9TFCh. 7 - Prob. 10TFCh. 7 - Prob. 11TFCh. 7 - Prob. 12TFCh. 7 - Prob. 2MCCh. 7 - Prob. 3MCCh. 7 - Prob. 4MCCh. 7 - Prob. 5MCCh. 7 - Prob. 6MCCh. 7 - Prob. 7MCCh. 7 - Prob. 8MCCh. 7 - Prob. 1MCh. 7 - Prob. 2MCh. 7 - Prob. 3MCh. 7 - Prob. 4MCh. 7 - Prob. 5MCh. 7 - Prob. 6MCh. 7 - Prob. 7MCh. 7 - Prob. 8MCh. 7 - Prob. 9MCh. 7 - Prob. 10MCh. 7 - Prob. 2CTCh. 7 - Prob. 3CTCh. 7 - Prob. 4CTCh. 7 - Prob. 5CTCh. 7 - Prob. 6CTCh. 7 - Prob. 7CTCh. 7 - Prob. 8CTCh. 7 - Prob. 9CTCh. 7 - Prob. 10CTCh. 7 - Prob. 11CTCh. 7 - Prob. 12CTCh. 7 - Prob. 13CTCh. 7 - Prob. 14CTCh. 7 - Prob. 15CTCh. 7 - Prob. 16CTCh. 7 - Prob. 17CTCh. 7 - Prob. 18CTCh. 7 - Prob. 20CTCh. 7 - Prob. 21CTCh. 7 - Prob. 22CTCh. 7 - Prob. 23CTCh. 7 - Prob. 24CTCh. 7 - Prob. 25CTCh. 7 - Prob. 26CTCh. 7 - Prob. 27CTCh. 7 - Prob. 28CTCh. 7 - Prob. 1PSCh. 7 - Prob. 2PSCh. 7 - Prob. 3PSCh. 7 - Prob. 4PSCh. 7 - Prob. 5PSCh. 7 - Prob. 6PSCh. 7 - Prob. 7PSCh. 7 - Prob. 8PSCh. 7 - Prob. 9PSCh. 7 - Prob. 10PSCh. 7 - Prob. 11PSCh. 7 - Prob. 1.1ECh. 7 - Prob. 1.2ECh. 7 - Prob. 1.3ECh. 7 - Prob. 2.1ECh. 7 - Prob. 2.2ECh. 7 - Prob. 2.3ECh. 7 - Prob. 3.1ECh. 7 - Prob. 3.2ECh. 7 - Prob. 4.1ECh. 7 - Prob. 4.2ECh. 7 - Prob. 4.3ECh. 7 - Prob. 5.1ECh. 7 - Prob. 5.2ECh. 7 - Prob. 5.3ECh. 7 - Prob. 1IRCh. 7 - Prob. 2IRCh. 7 - Prob. 4IRCh. 7 - Prob. 5IRCh. 7 - Prob. 1CTQCh. 7 - Prob. 2CTQCh. 7 - Prob. 3CTQ
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