11th Edition

ISBN: 9781337620338

Author: SERWAY/VUILLE

Publisher: CENGAGE Learning Custom Publishing

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Textbook Question

Chapter 7, Problem 8P

A bicycle is turned upside down while its owner repairs a flat tire. A friend spins the other wheel and observes that drops of water fly off tangentially. She measures the heights reached by drops moving vertically (Fig. P7.8). A drop that breaks loose from the tire on one turn rises vertically 54.0 cm above the tangent point. A drop that breaks loose on the next turn rises 51.0 cm above the tangent point. The radius of the wheel is 0.381 m. (a) Why does the first drop rise higher than the second drop? (b) Neglecting air friction and using only the observed heights and the radius of the wheel, find the wheel’s angular acceleration (assuming it to be constant).

Chapter 7, Problem 8P, A bicycle is turned upside down while its owner repairs a flat tire. A friend spins the other wheel

Figure P7.8

Problems 8 and 69.

Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .

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Chapter 7, Problem 7P

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Chapter 7 Solutions

College Physics 11E Global Edition

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Solution Summary: The author explains that the first drop rises higher than the second drop as the tangential velocity of the tire decreases in each subsequent turn.

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