EBK BIOLOGY:SCIENCE F/LIFE
6th Edition
ISBN: 9780134819167
Author: BELK
Publisher: PEARSON
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Textbook Question
Chapter 7, Problem 8LTB
If humans have 23 pairs of chromosomes, each carrying hundreds to thousands of genes, roughly how many genes are there in the human genome?
- 23;
- 46;
- 1000;
- 20,000;
- 200,000
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Which one of the following options most accurately describes how the ~3000 megabases (Mb; ~3,000,000,000 nucleotides) of the haploid human genome are distributed on chromosomes?
The haploid human genome is distributed on autosomes 1-22 and X and Y (so, 24 chromosomes).
The haploid human genome is distributed on the homologous pairs of autosomes 1-22 and X and Y (so, 46 chromosomes).
The haploid human genome is distributed on a single chromosome (so, 1 chromosome).
The haploid human genome is distributed on one pair of homologous chromosomes (so, 2 chromosomes).
Most cells in our bodies contain two sets of chromosomes (2x23=46) . Which types of cells each have only one set (23)?
1.
Chapter 7 Solutions
EBK BIOLOGY:SCIENCE F/LIFE
Ch. 7 - List several ways in which meiosis differs from...Ch. 7 - Add labels to the figure that follows, which...Ch. 7 - Prob. 3LTBCh. 7 - A sperm cell follows which path? seminiferous...Ch. 7 - An egg cell that is not fertilized follows which...Ch. 7 - Which of the following is mismatched? urethra:...Ch. 7 - The production of gametes. ___________. begins at...Ch. 7 - If humans have 23 pairs of chromosomes, each...Ch. 7 - Prob. 9LTBCh. 7 - Prob. 10LTB
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
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- How many genes are there in a human cell .arrow_forwardOrangutans are an endangered species in their natural environment (the islands of Borneo and Sumatra), and so a captive-breeding program has been established using orangutans currently held in zoos throughout the world. One component of this program is research into orangutan cytogenetics. This research has shown that all orangutans from Borneo carry one form of chromosome 2, as shown in the accompanying diagram, and all orangutans from Sumatra carry the other form. Before this cytogenetic difference became known, some matings were carried out between animals from different islands, and 14 hybrid progeny are now being raised in captivity.q3.1 q2.2 q2.1 q1.2 q1.1Borneop1.1 p1.2cenq3.1 q2.2 q2.1 p1.1Sumatrap1.2cenq1.1 q1.2a. What term or terms describe the differences between these chromosomes?b. Draw the chromosomes 2, paired in the first meiotic prophase, of such a hybrid orangutan. Be sure to show all the landmarks indicated in the accompanying diagram, and label all parts of your…arrow_forwardOrangutans are an endangered species in their natural environment (the islands of Borneo and Sumatra), and so a captive-breeding program has been established using orangutans currently held in zoos throughout the world. One component of this program is research into orangutan cytogenetics. This research has shown that all orangutans from Borneo carry one form of chromosome 2, as shown in the accompanying diagram, and all orangutans from Sumatra carry the other form. Before this cytogenetic difference became known, some matings were carried out between animals from different islands, and 14 hybrid progeny are now being raised in captivitya. What term or terms describe the differences between these chromosomes? b. Draw the chromosomes 2, paired in the first meiotic prophase, of such a hybrid orangutan. Be sure to show all the landmarks indicated in the accompanying diagram, and label all parts of your drawing. c. In 30 percent of meioses, there will be a crossover somewhere in the region…arrow_forward
- A diploid (ie, contains TWO sets of chromosomes) organisms with a 45,000-kb haploid (counts only one set of its chromosomes) genome contains 21% G residues. Calculate the number of A, C, G< and T residues in the DNA of each cell in this organism. Can you help explain why this is the answer, thank you! Answer: Since the haploid genome contains 21% G, it must contain 21% C (Because G=C) and 58% A + T, or 29% A and 29% T. Each cell is a diploid, containing 90,000 kb or 9x10^7 bases. Therefore, A=T = (0.29)(9x10^7) = 2.61 x 10^7 bases and G=C=(0.21)(9x10^7) = 1.89x10^7 bases.arrow_forwardIn letter B: If the map distance equals the number of recombinant/total of offspring, wouldn't it be 24/806 x 100? Wouldn't we add both recombinants? Can you explain letter C? I don't grasp that concept well. And since I'm using my question already, would you be able to answer D. Thank you!arrow_forwardOn an episode of the science fiction television program Doctor Who, the “Progenation Machine” can take a tissue sample from an individual, duplicate all their chromosomes many times, then assemble a new individual with a complete set of homologous pairs by randomly selecting two of each set of chromosomes. If this actually worked, and wasn’t just a fictional construct, what is the maximum number of genetically distinct individuals that could be produced in this way from a humanarrow_forward
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