Chapter 7, Problem 7A.6AE

(i)

Interpretation Introduction

Interpretation:

The speed to which a stationary $\text{H}$ atom would be accelerated if it absorbed the photons of $\text{600}\text{nm}$ has to be calculated.

Concept introduction:

De Broglie wavelength shows dual nature of light, that is, particle like nature and wave like nature.  The de Broglie wavelength relates the wavelength of an object with its momentum.  The de Broglie wavelength is given bythe expression,

    $\lambda =\frac{h}{mv}$

Where,

• $\lambda$ is the de Broglie wavelength.
• $h$ is the Planck’s constant.
• $m$ is the mass of the given body.
• $v$ is the velocity.

(ii)

Interpretation Introduction

Interpretation:

The speed to which a stationary $\text{H}$ atom would be accelerated if it absorbed the photons of $\text{550}\text{nm}$ has to be calculated.

Concept introduction:

De Broglie wavelength shows dual nature of light, that is, particle like nature and wave like nature.  The de Broglie wavelength relates the wavelength of an object with its momentum.  The de Broglie wavelength is given by the expression,

    $\lambda =\frac{h}{mv}$

Where,

• $\lambda$ is the de Broglie wavelength.
• $h$ is the Planck’s constant.
• $m$ is the mass of the given body.
• $v$ is the velocity.

(iii)

Interpretation Introduction

Interpretation:

The speed to which a stationary $\text{H}$ atom would be accelerated if it absorbed the photons of $\text{400}\text{nm}$ has to be calculated.

Concept introduction:

De Broglie wavelength shows dual nature of light, that is, particle like nature and wave like nature.  The de Broglie wavelength relates the wavelength of an object with its momentum.  The de Broglie wavelength is given by,

    $\lambda =\frac{h}{mv}$

Where,

• $\lambda$ is the de Broglie wavelength.
• $h$ is the Planck’s constant.
• $m$ is the mass of the given body.
• $v$ is the velocity.