ELEMENTARY SURVERYING W/ACCESS PACKAGE
15th Edition
ISBN: 9780134771786
Author: GHILANI
Publisher: PEARSON
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Chapter 7, Problem 7.8P
To determine
By converting the bearings to azimuth from the north and compute the angles smaller than
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The cantilever beam shown below supports a uniform service (unfactored) dead load of 1.5 kip/ft plus its own self weight, plus two unknown concentrated service (unfactored) live loads, as shown. The concrete has f’c = 6,000 psi and the steel yield strength is 60 ksi.
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Chapter 7 Solutions
ELEMENTARY SURVERYING W/ACCESS PACKAGE
Ch. 7 - Define the different reference meridians that can...Ch. 7 - Prob. 7.2PCh. 7 - Why is it important to adopt a standard angle...Ch. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - In Problems 7.6 through 7.? I9, convert the...Ch. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - For a bearing DE = NUS 5 53’56 ”WT and angles to...Ch. 7 - ?.14 Similar to Problem ?.13 El, except the...Ch. 7 - Prob. 7.15PCh. 7 - Course AB of a ?ve-sided traverse runs due north....Ch. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Prob. 7.22PCh. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - Prob. 7.26PCh. 7 - Prob. 7.27PCh. 7 - Prob. 7.28PCh. 7 - Prob. 7.29PCh. 7 - For Problems 7.30 through 7.32 the observed...Ch. 7 - Prob. 7.31PCh. 7 - Prob. 7.32PCh. 7 - Prob. 7.33PCh. 7 - Prob. 7.34PCh. 7 - Prob. 7.35PCh. 7 - Prob. 7.36PCh. 7 - Prob. 7.37PCh. 7 - Prob. 7.38P
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- The circular slab of radius r supported by four columns, as shown in figure, is to be isotropically reinforced. Find the ultimate resisting moment (m) per linear meter required just to sustain a concentrated factored load of P kN applied at the center of the slab. Solve by using equilibrium m m Columnarrow_forwardBy using the yield line theory, determine the ultimate resisting moment per linear meter (m) for an isotropic reinforced concrete two-way simply supported polygon slab shown in figure under a uniform load (q). Solve by using equilibrium method m marrow_forwardBy using the yield line theory, determine the ultimate resisting moment per linear meter (m) for an isotropic reinforced concrete two-way simply supported polygon slab shown in figure under a concentrated factored load of P. Solve by Using equilibrium method m m 8/arrow_forward
- H.W: Evaluate the integral 1. 30 √ · √(x²y – 2xy)dydx 0-2 3 1 3. (2x-4y)dydx 1-1 2π π 5. (sinx + cosy)dxdy π 0 0 1 ƒ ƒ (x + 2. +y+1)dxdy 4. -1-1 41 ][ 20 x²ydxdyarrow_forwardExample 5 By using the yield line theory, determine the moment (m) for an isotropic reinforced concrete two-way slab (supports on two S.S sides shown in figure under the load (P) (all dimensions are in mm). Solve by using equilibrium method Please solve by using equilibrium method m m 3000 2000 2000arrow_forward2. During construction, gate AB is temporarily held in place by the horizontal strut CD. Determine the force in the strut CD, if the gate is 3.0-m wide. A 0 B D Density of water = 103 kg/m³ 2 m 3 marrow_forward
- 5. A gate is used to hold water as shown. The gate is rectangular and is 8-ft wide. Neglect the weight of the gate. Determine at what depth the gate is just about to open. 5000 Ib 15 ft Hinge 60°arrow_forwardH.W2. Design Twin Opening of an Inverted Siphon (8 + 27 +6) m required to pass Canal Discharge of 3m³/ sec under road with 0.18m Head Loss. The Velocity in the Canal is 0.78m/sec and the depth of water in the canal is 1.4m, Safety Screen is provided from entry and exit. The Inverted Siphon 22.5 ° ELBOWS of each end. IF n = 0.013, Ke= 0.2, Ko = 0.3, Kscreen Kelbows 0.05. = 0.2 andarrow_forwardH.W.1: A concrete pipe culvert is to be constructed under road to carry a maximum discharge 9 m3/sec. If the length of pipe culvert 10 m on slope 1/100, Ke= 0.5, Ko = 1, n = 0.018, HL = 0.18. Find the diameter of the pipe. birea vaznds or bout one anorgia batio/larrow_forward
- Find the magnitude and depth of the point of application of the force on circular gate shown in figure if h=5 ft and D=4 ft dia. (Answer: 5280 lbf, ycp = 7.9 ft i.e. vertical depth of cp is 6.84 ft)arrow_forward*3-4. A tension test was performed on a steel specimen having an original diameter of 0.503 in. and a gauge length of 2.00 in. The data is listed in the table. Plot the stress-strain diagram and determine approximately the modulus of elasticity, the ultimate stress, and the rupture stress. Use a scale of 1 in. = 15 ksi and 1 in. = 0.05 in./in. Redraw the linear-elastic region, using the same stress scale but a strain scale of 1 in. = 0.001 in. Load (kip) Elongation (in.) 0 0 2.50 0.0009 6.50 0.0025 8.50 0.0040 9.20 0.0065 9.80 0.0098 12.0 0.0400 14.0 0.1200 14.5 0.2500 14.0 0.3500 13.2 0.4700arrow_forwardPROBLEM 4 Draw a free body diagram of the loading and forces. Solve for the reaction A at the wall support. Check your answer using the summation of forces. 15 K/ft 15 ft 25 K/ftarrow_forward
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