EBK CHEMISTRY: THE SCIENCE IN CONTEXT,
EBK CHEMISTRY: THE SCIENCE IN CONTEXT,
5th Edition
ISBN: 9780393661385
Author: Davies
Publisher: VST
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Chapter 7, Problem 7.81QP

 (a)

Interpretation Introduction

Interpretation: The set of orbitals corresponds to each of the given sets of quantum numbers are to be stated. Also, the number of electrons occupied by these orbitals is to be stated.

Concept introduction: There are four quantum numbers that indicates the size, energy and shape of an atomic orbital. The quantum number n is the principal quantum number that indicates the energy level and size of the orbital and l is the azimuthal quantum number that determines the shape and angular momentum of an orbital. The magnetic quantum number is an integer that takes the values from (l to +l) .

To determine: The set of orbitals correspond to the given set of quantum numbers and the number of electrons occupied by these orbitals.

 (a)

Expert Solution
Check Mark

Answer to Problem 7.81QP

Solution

The given set of quantum number, n=2 and l=0 represents 2s orbital and the number of electrons in 2s orbital is 2_ .

Explanation of Solution

Explanation

The given principal quantum number (n) is 2 that represents the energy level and angular momentum quantum number (l) is 0 that represents the shape of an orbital. Therefore, n=2 and l=0 represents 2s sub shell.

The number of electrons occupied by s orbital is two as one orbital contains maximum of two electrons. Hence, the given set of quantum number, n=2 and l=0 represents 2s orbital with two electrons.

(b)

Interpretation Introduction

Interpretation: The set of orbitals corresponds to each of the given sets of quantum numbers are to be stated. Also, the number of electrons occupied by these orbitals is to be stated.

Concept introduction: There are four quantum numbers that indicates the size, energy and shape of an atomic orbital. The quantum number n is the principal quantum number that indicates the energy level and size of the orbital and l is the azimuthal quantum number that determines the shape and angular momentum of an orbital. The magnetic quantum number is an integer that takes the values from (l to +l) .

To determine: The set of orbitals correspond to the given set of quantum numbers and the number of electrons occupied by these orbitals.

(b)

Expert Solution
Check Mark

Answer to Problem 7.81QP

Solution

The given set of quantum number, n=3 and l=1 represents 3p orbital and the number of electrons in 3p orbital is 6_ .

Explanation of Solution

Explanation

The given principal quantum number (n) is 3 and angular momentum quantum number (l) is 1 that represents p sub shell. Therefore, n=3 and l=1 represents 3p sub shell.

The sub shell 3p contains three orbitals (3px,3py,3pz) . Each orbital contains two electrons Therefore; the maximum number of electrons accommodated in p sub shell is six. Hence, the given set of quantum number, n=3 and l=1 represents 3p orbital with six electrons.

(c)

Interpretation Introduction

Interpretation: The set of orbitals corresponds to each of the given sets of quantum numbers are to be stated. Also, the number of electrons occupied by these orbitals is to be stated.

Concept introduction: There are four quantum numbers that indicates the size, energy and shape of an atomic orbital. The quantum number n is the principal quantum number that indicates the energy level and size of the orbital and l is the azimuthal quantum number that determines the shape and angular momentum of an orbital. The magnetic quantum number is an integer that takes the values from (l to +l) .

To determine: The set of orbitals correspond to the given set of quantum numbers and the number of electrons occupied by these orbitals.

(c)

Expert Solution
Check Mark

Answer to Problem 7.81QP

Solution

The given set of quantum number, n=4 and l=2 represents 4d orbital and the number of electrons in 4d orbital is 10_ .

Explanation of Solution

Explanation

The given principal quantum number (n) is 4 and angular momentum quantum number (l) is 2 that represents d sub shell. Therefore, n=4 and l=2 represents 4d sub shell.

The sub shell 4d contains five orbitals (4dx,4dy,4dz,4dx2-y2,4dz2) . Each orbital contains two electrons Therefore; the maximum number of electrons accommodated in d sub shell is ten. Hence, the given set of quantum number, n=4 and l=2 represents 4d orbital with ten electrons.

(d)

Interpretation Introduction

Interpretation: The set of orbitals corresponds to each of the given sets of quantum numbers are to be stated. Also, the number of electrons occupied by these orbitals is to be stated.

Concept introduction: There are four quantum numbers that indicates the size, energy and shape of an atomic orbital. The quantum number n is the principal quantum number that indicates the energy level and size of the orbital and l is the azimuthal quantum number that determines the shape and angular momentum of an orbital. The magnetic quantum number is an integer that takes the values from (l to +l) .

To determine: The set of orbitals correspond to the given set of quantum numbers and the number of electrons occupied by these orbitals.

(d)

Expert Solution
Check Mark

Answer to Problem 7.81QP

Solution

The given set of quantum number, n=1 and l=0 represents 1s orbital and the number of electrons in 1s orbital is 2_ .

Explanation of Solution

Explanation

The given principal quantum number (n) is 1 and angular momentum quantum number (l) is 0 that represents s orbital. Therefore, n=1 and l=0 represents 1s sub shell.

The number of electrons occupied by s orbital is two as one orbital contains maximum of two electrons. Hence, the given set of quantum number, n=2 and l=0 represents 2s orbital with two electrons. Hence, the given set of quantum number, n=1 and l=0 represents 1s orbital with two electrons.

Conclusion

  1. a. The set of quantum number, n=2 and l=0 represents 2s orbital and the number of electrons in 2s orbital is 2_ .
  2. b. The set of quantum number, n=3 and l=1 represents 3p orbital and the number of electrons in 3p orbital is 6_ .
  3. c. The set of quantum number, n=4 and l=2 represents 4d orbital and the number of electrons in 4d orbital is 10_ .
  4. d. The set of quantum number, n=1 and l=0 represents 1s orbital and the number of electrons in 1s orbital is 2_ .

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Chapter 7 Solutions

EBK CHEMISTRY: THE SCIENCE IN CONTEXT,

Ch. 7.9 - Prob. 11PECh. 7.10 - Prob. 12PECh. 7.10 - Prob. 13PECh. 7.11 - Prob. 14PECh. 7.12 - Prob. 15PECh. 7 - Prob. 7.1VPCh. 7 - Prob. 7.2VPCh. 7 - Prob. 7.3VPCh. 7 - Prob. 7.4VPCh. 7 - Prob. 7.5VPCh. 7 - Prob. 7.6VPCh. 7 - Prob. 7.7VPCh. 7 - Prob. 7.8VPCh. 7 - Prob. 7.9VPCh. 7 - Prob. 7.10VPCh. 7 - Prob. 7.11QPCh. 7 - Prob. 7.12QPCh. 7 - Prob. 7.13QPCh. 7 - Prob. 7.14QPCh. 7 - Prob. 7.15QPCh. 7 - Prob. 7.16QPCh. 7 - Prob. 7.17QPCh. 7 - Prob. 7.18QPCh. 7 - Prob. 7.19QPCh. 7 - Prob. 7.20QPCh. 7 - Prob. 7.21QPCh. 7 - Prob. 7.22QPCh. 7 - Prob. 7.23QPCh. 7 - Prob. 7.24QPCh. 7 - Prob. 7.25QPCh. 7 - Prob. 7.26QPCh. 7 - Prob. 7.27QPCh. 7 - Prob. 7.28QPCh. 7 - Prob. 7.29QPCh. 7 - Prob. 7.30QPCh. 7 - Prob. 7.31QPCh. 7 - Prob. 7.32QPCh. 7 - Prob. 7.33QPCh. 7 - Prob. 7.34QPCh. 7 - Prob. 7.35QPCh. 7 - Prob. 7.36QPCh. 7 - Prob. 7.37QPCh. 7 - Prob. 7.38QPCh. 7 - Prob. 7.39QPCh. 7 - Prob. 7.40QPCh. 7 - Prob. 7.41QPCh. 7 - Prob. 7.42QPCh. 7 - Prob. 7.43QPCh. 7 - Prob. 7.44QPCh. 7 - Prob. 7.45QPCh. 7 - Prob. 7.46QPCh. 7 - Prob. 7.47QPCh. 7 - Prob. 7.48QPCh. 7 - Prob. 7.49QPCh. 7 - Prob. 7.50QPCh. 7 - Prob. 7.51QPCh. 7 - Prob. 7.52QPCh. 7 - Prob. 7.53QPCh. 7 - Prob. 7.54QPCh. 7 - Prob. 7.55QPCh. 7 - Prob. 7.56QPCh. 7 - Prob. 7.57QPCh. 7 - Prob. 7.58QPCh. 7 - Prob. 7.59QPCh. 7 - Prob. 7.60QPCh. 7 - Prob. 7.61QPCh. 7 - Prob. 7.62QPCh. 7 - Prob. 7.63QPCh. 7 - Prob. 7.64QPCh. 7 - Prob. 7.65QPCh. 7 - Prob. 7.66QPCh. 7 - Prob. 7.67QPCh. 7 - Prob. 7.68QPCh. 7 - Prob. 7.69QPCh. 7 - Prob. 7.70QPCh. 7 - Prob. 7.71QPCh. 7 - Prob. 7.72QPCh. 7 - Prob. 7.73QPCh. 7 - Prob. 7.74QPCh. 7 - Prob. 7.75QPCh. 7 - Prob. 7.77QPCh. 7 - Prob. 7.78QPCh. 7 - Prob. 7.76QPCh. 7 - Prob. 7.79QPCh. 7 - Prob. 7.80QPCh. 7 - Prob. 7.81QPCh. 7 - Prob. 7.82QPCh. 7 - Prob. 7.83QPCh. 7 - Prob. 7.84QPCh. 7 - Prob. 7.85QPCh. 7 - Prob. 7.86QPCh. 7 - Prob. 7.87QPCh. 7 - Prob. 7.88QPCh. 7 - Prob. 7.89QPCh. 7 - Prob. 7.90QPCh. 7 - Prob. 7.91QPCh. 7 - Prob. 7.92QPCh. 7 - Prob. 7.93QPCh. 7 - Prob. 7.94QPCh. 7 - Prob. 7.95QPCh. 7 - Prob. 7.96QPCh. 7 - Prob. 7.97QPCh. 7 - Prob. 7.98QPCh. 7 - Prob. 7.99QPCh. 7 - Prob. 7.100QPCh. 7 - Prob. 7.101QPCh. 7 - Prob. 7.102QPCh. 7 - Prob. 7.103QPCh. 7 - Prob. 7.104QPCh. 7 - Prob. 7.105QPCh. 7 - Prob. 7.106QPCh. 7 - Prob. 7.107QPCh. 7 - Prob. 7.108QPCh. 7 - Prob. 7.109QPCh. 7 - Prob. 7.110QPCh. 7 - Prob. 7.111QPCh. 7 - Prob. 7.112QPCh. 7 - Prob. 7.113QPCh. 7 - Prob. 7.114QPCh. 7 - Prob. 7.115QPCh. 7 - Prob. 7.116QPCh. 7 - Prob. 7.117QPCh. 7 - Prob. 7.118QPCh. 7 - Prob. 7.119QPCh. 7 - Prob. 7.120QPCh. 7 - Prob. 7.121QPCh. 7 - Prob. 7.122QPCh. 7 - Prob. 7.123QPCh. 7 - Prob. 7.124QPCh. 7 - Prob. 7.125QPCh. 7 - Prob. 7.126QPCh. 7 - Prob. 7.127APCh. 7 - Prob. 7.128APCh. 7 - Prob. 7.129APCh. 7 - Prob. 7.130APCh. 7 - Prob. 7.131APCh. 7 - Prob. 7.132APCh. 7 - Prob. 7.133APCh. 7 - Prob. 7.134APCh. 7 - Prob. 7.135APCh. 7 - Prob. 7.136APCh. 7 - Prob. 7.137APCh. 7 - Prob. 7.138APCh. 7 - Prob. 7.139APCh. 7 - Prob. 7.140APCh. 7 - Prob. 7.141APCh. 7 - Prob. 7.142AP
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