(a)
Interpretation:
The mechanism for the addition of a proton from trifluoromethanesulfonic acid to the
Concept introduction:
Carbon-carbon double and triple bonds are electron-rich. They can undergo heterolytic bond breaking. The pi bond can break, and the electron pair can be used to form a bond with an electrophile such as a proton. The electrophile bonds to one of the carbon atoms. The other carbon atom gets a 1+ charge and is called a carbocation. The reaction mechanism is drawn by showing the movement of electron pairs with curved arrows. The curved arrow starts from an electron-rich atom or center of an electron-rich region (a pi bond) and ends on an electron-poor atom, an electrophile, to show the formation of a new sigma bond. If a pi bond is formed, the arrow must end in the region between the corresponding atoms.
(b)
Interpretation:
It is to be determined which of the two carbocations formed on the addition of a proton to the given alkyne is more stable.
Concept introduction:
Carbocations are positively charged carbon atoms that are electron poor. The carbon is two electrons short of an octet. The charge and the incomplete octet make the carbocation an unstable species. The stability of a carbocation depends on the number of alkyl groups bonded to it and increases in the order
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- Using what we have learned in CHEM 2310 and up through class on 1/31, propose a series of reaction steps to achieve the transformation below. Be sure to show all reagents and intermediates for full credit. You do not need to draw mechanism arrows, but you do need to include charges where appropriate. If you do not put your group name, you will get half credit at most. ? Brarrow_forwardDraw a mechanism for the formation of 2-bromovanillin using bromonium ion as the reactive electrophile.arrow_forwardNonearrow_forward