Principles of Instrumental Analysis, 6th Edition
6th Edition
ISBN: 9788131525579
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cenage Learning
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Question
Chapter 7, Problem 7.1QAP
Interpretation Introduction
Interpretation:
The reason for the variation in the slit width of prism monochromator to obtain the constant effective bandwidth needs to be explained.
Concept introduction:
Monochromators are optical devices which transmit a wide range of available wavelengths, a mechanically selectable narrow wavelength band. These could be
Expert Solution & Answer
Answer to Problem 7.1QAP
Over a certain spectral range, the output wavelength is continuously variable in case of prism monochromator and so, the slit width also must be varied.
Explanation of Solution
The wavelength, that is the output keeps changing continuously for a considerable spectral range in case of a prism monochromator while in case of a grating monochromator, the output wavelength remains same, as the radiation is dispersed in the component wavelength.
As the output wavelength keeps varying, the slit width is also required to be varied in case of a prism monochromator in order to keep the effective wavelength constant which is not needed in case of a grating monochromator.
Conclusion
Slit width must be varied to get constant effective wavelength in case of prism monochromator while it is almost same in case of grating monochromator.
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Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below.
Find the following:
(a) The no. of protons corresponding to each signal in the spectra
(6) Give the structure of the compound and assign the signals to each
proton in the compound.
a
70.2
Integration Values
C5H10O2
b
47.7
C
46.5
d
69.5
3.6 3.5
3.4 3.3 3.2 3.1 3.0
2.9 2.8
2.7
2.6 2.5
2.4 2.3 2.2 2.1 2.0
Chemical Shift (ppm)
1.9
1.8
1.7 1.6
1.5
1.4 1.3 1.2
1.1 1.0
0.9 0.8
Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below.
Answer the following:
(a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure
of the molecule below.
(b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible.
complex splitting patterns assuming J values are not similar.
там
Br
22
2
3
6
4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0
Chemical Shift (ppm)
ra.
Br
2
3
6
6
2.5
2.4
2.3
2.2
2.1
2.0
1.9
1.8
1.7
1.6
1.5
1.4
1.3
1.2
1.1
1.0
0.9
0.8
Chemical Shift (ppm)
2
2
Br
7.3
7.2
7.1
7.0 6.9
6.7 6.6 6.5
6.4
6.3
6.2
6.1
6.0
Chemical Shift (ppm)
5.9
5.8 5.7
5.5 5.4 5.3 5.2
5.0 4.9
1600°
1538°C
1493°C
In the diagram, the letter L indicates
that it is a liquid. Indicate its
components in the upper region
where only L is indicated.
The
iron-iron carbide phase
diagram.
Temperature (°C)
1400
8
1394°C
y+L
1200
2.14
y, Austenite
10000
912°C
800a
0.76
0.022
600
400
(Fe)
a, Ferrite
Composition (at% C)
15
1147°C
a + Fe3C
2
3
Composition (wt% C)
L
2500
4.30
2000
y + Fe3C
727°C
1500
Cementite (Fe3C)
1000
4
5
6
6.70
Temperature (°F)
Chapter 7 Solutions
Principles of Instrumental Analysis, 6th Edition
Ch. 7 - Prob. 7.1QAPCh. 7 - Prob. 7.2QAPCh. 7 - The Wien displacement law states that the...Ch. 7 - Prob. 7.4QAPCh. 7 - Prob. 7.5QAPCh. 7 - Describe the differences and similarities between...Ch. 7 - Prob. 7.7QAPCh. 7 - Prob. 7.8QAPCh. 7 - Prob. 7.9QAPCh. 7 - Prob. 7.10QAP
Ch. 7 - Why is glass better than fused silica as a prism...Ch. 7 - Prob. 7.12QAPCh. 7 - Prob. 7.13QAPCh. 7 - Prob. 7.14QAPCh. 7 - Prob. 7.15QAPCh. 7 - Prob. 7.16QAPCh. 7 - Prob. 7.17QAPCh. 7 - Prob. 7.18QAPCh. 7 - Prob. 7.19QAPCh. 7 - Prob. 7.20QAPCh. 7 - Prob. 7.21QAPCh. 7 - Prob. 7.22QAPCh. 7 - Prob. 7.23QAPCh. 7 - Prob. 7.24QAP
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