COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 7, Problem 68QAP
To determine
What are the coordinates of the center of mass for the combination of the three objects shown in Figure?
The uniform rod has a mass of 10.0 kg, has a length of 30.0 cm and is located at x = 50 cm. The oval football has a mass of 2.00 kg, a semi major axis of 8.00 cm and is centered at x= -50 cm. The spherical volleyball has a mass of 1 kg, has a radius of 10 cm and is centered at y = -30 cm. Assume both balls are of uniform mass density.
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Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.)
a
C
3.00 με
Hh.
6.00 με
20.0 με
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(a) Find the equivalent capacitance between points a and b.
5.92
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(b) Calculate the charge on each capacitor, taking AV ab = 16.0 V.
20.0 uF capacitor 94.7
6.00 uF capacitor 67.6
32.14
3.00 µF capacitor
capacitor C
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The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC
32.14
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You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
In the pivot assignment, we observed waves moving on a string stretched by hanging
weights. We noticed that certain frequencies produced standing waves. One such
situation is shown below:
0 ст
Direct Measurement
©2015 Peter Bohacek I.
20
0 cm 10
20
30
40
50
60
70
80
90
100
Which Harmonic is this?
Do NOT include units!
What is the wavelength of this wave in cm with only no decimal places?
If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with
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Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.)
A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b.
(a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V.
20.0 µF capacitor
µC
6.00 µF capacitor
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capacitor C
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Chapter 7 Solutions
COLLEGE PHYSICS
Ch. 7 - Prob. 1QAPCh. 7 - Prob. 2QAPCh. 7 - Prob. 3QAPCh. 7 - Prob. 4QAPCh. 7 - Prob. 5QAPCh. 7 - Prob. 6QAPCh. 7 - Prob. 7QAPCh. 7 - Prob. 8QAPCh. 7 - Prob. 9QAPCh. 7 - Prob. 10QAP
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