Chapter 7, Problem 68E

Interpretation Introduction

Interpretation:

The compounds which are water-soluble are to be predicted.

Concept Introduction:

In a double-replacement reaction, two aqueous solutions react to form a compound that is not soluble; that is, a precipitate. Some solubility rules for the ionic compound are given below.

• Alkali metal ions and ammonium ions are soluble in water.

• Acetate ion, ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}{}^{-}$ is soluble in water.

• Nitrate ion $\left({\text{NO}}_{\text{3}}{}^{-}\right)$ and sulfate ion $\left({\text{SO}}_{\text{4}}{}^{-2}\right)$ (with some exceptions) are soluble in water.

• Carbonate ion $\left({\text{CO}}_{\text{3}}{}^{-2}\right)$ and chromate ion $\left({\text{CrO}}_{\text{4}}{}^{-}\right)$ are insoluble in water.

• Phosphate ion $\left({\text{PO}}_{\text{4}}{}^{3-}\right)$ and sulfide ion $\left({\text{S}}^{2-}\right)$ are insoluble in water.