EBK INTRODUCTORY CHEMISTRY
EBK INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 9780134553153
Author: CORWIN
Publisher: PEARSON CO
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Chapter 7, Problem 19E
Interpretation Introduction

(a)

Interpretation:

The balanced chemical equation for the reaction between lead and oxygen gas is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 19E

The balanced chemical equation for the reaction between lead and oxygen gas is shown below.

2Pb(s)+O2(g)2PbO(s)

Explanation of Solution

The unbalanced chemical equation for the reaction between lead and oxygen gas is shown below.

Pb(s)+O2(g)PbO(s)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2 is placed in front of Pb and PbO to balance the chemical equation.

Therefore, the balanced chemical equation for the reaction between lead and oxygen gas is shown below.

2Pb(s)+O2(g)2PbO(s)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between lead and oxygen gas is given below.

2Pb(s)+O2(g)2PbO(s)

Interpretation Introduction

(b)

Interpretation:

The balanced chemical equation of the decomposition reaction of lithium nitrate is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 19E

The balanced chemical equation of the decomposition reaction of lithium nitrate is shown below.

2LiNO3(s)2LiNO2(s)+O2(g)

Explanation of Solution

The unbalanced chemical equation of the decomposition reaction of lithium nitrate is shown below.

LiNO3(s)LiNO2(s)+O2(g)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2is placed in front of LiNO3 and LiNO2 to balance the chemical equation.

Therefore, the balanced chemical equation of the decomposition reaction of lithium nitrate is shown below.

2LiNO3(s)2LiNO2(s)+O2(g)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation of the decomposition reaction of lithium nitrate is given below.

2LiNO3(s)2LiNO2(s)+O2(g)

Interpretation Introduction

(c)

Interpretation:

The balanced chemical equation for the reaction between magnesium metal and acetic acid is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 19E

The balanced chemical equation for the reaction between magnesium metal and acetic acid is shown below.

Mg(s)+2HC2H3O2(aq)Mg(C2H3O2)2(aq)+H2(g)

Explanation of Solution

The unbalanced chemical equation for the reaction between magnesium metal and acetic acid is shown below.

Mg(s)+HC2H3O2(aq)Mg(C2H3O2)2(aq)+H2(g)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2 is placed in front of HC2H3O2 to balance the chemical equation.

Therefore, the balanced chemical equation for the reaction between magnesium metal and acetic acid is shown below.

Mg(s)+2HC2H3O2(aq)Mg(C2H3O2)2(aq)+H2(g)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between magnesium metal and acetic acid is given below.

Mg(s)+2HC2H3O2(aq)Mg(C2H3O2)2(aq)+H2(g)

Interpretation Introduction

(d)

Interpretation:

The balanced chemical equation for the reaction between mercury nitrate and sodium bromide is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 19E

The balanced chemical equation for the reaction between mercury nitrate and sodium bromide is shown below.

Hg2(NO3)2(aq)+2NaBr(aq)Hg2Br2(s)+2NaNO3(aq)

Explanation of Solution

The unbalanced chemical equation for the reaction between mercury nitrate and sodium bromide is shown below.

Hg2(NO3)2(aq)+NaBr(aq)Hg2Br2(s)+NaNO3(aq)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2 is placed in front of NaBr and NaNO3 to balance the chemical equation.

Therefore, the balanced chemical equation for the reaction between mercury nitrate and sodium bromide is shown below.

Hg2(NO3)2(aq)+2NaBr(aq)Hg2Br2(s)+2NaNO3(aq)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between mercury nitrate and sodium bromide is given below.

Hg2(NO3)2(aq)+2NaBr(aq)Hg2Br2(s)+2NaNO3(aq)

Interpretation Introduction

(e)

Interpretation:

The balanced chemical equation for the reaction between carbonic acid and ammonium hydroxide is to be stated.

Concept introduction:

A chemical reaction is a process in which rearrangement of atom or ions takes place between two reacting species. A balanced chemical equation represents an equation in which all the reactants and products are written with their stoichiometric coefficient and physical states. The number of atoms of an element on both sides of the equation is equal.

Expert Solution
Check Mark

Answer to Problem 19E

The balanced chemical equation for the reaction between carbonic acid and ammonium hydroxide is shown below.

H2CO3(aq)+2NH4OH(aq)(NH4)2CO3(aq)+2H2O(l)

Explanation of Solution

The unbalanced chemical equation for the reaction between carbonic acid and ammonium hydroxide is shown below.

H2CO3(aq)+NH4OH(aq)(NH4)2CO3(aq)+H2O(l)

The numbers of atoms of elements on the left side of the reaction are not equal to the right side of the reaction. Therefore, the reaction is unbalanced.

A coefficient of 2 is placed in front of NH4OH and H2O to balance the reaction.

Therefore, the balanced chemical equation for the reaction between carbonic acid and ammonium hydroxide is shown below.

H2CO3(aq)+2NH4OH(aq)(NH4)2CO3(aq)+2H2O(l)

The numbers of atoms of each element on the left side of the reaction are equal to the right side of the reaction. Therefore, the reaction is balanced.

Conclusion

The balanced chemical equation for the reaction between carbonic acid and ammonium hydroxide is given below.

H2CO3(aq)+2NH4OH(aq)(NH4)2CO3(aq)+2H2O(l)

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Chapter 7 Solutions

EBK INTRODUCTORY CHEMISTRY

Ch. 7 - Prob. 11CECh. 7 - Prob. 12CECh. 7 - Prob. 13CECh. 7 - Prob. 14CECh. 7 - Prob. 15CECh. 7 - Prob. 16CECh. 7 - Prob. 1KTCh. 7 - Prob. 2KTCh. 7 - Prob. 3KTCh. 7 - Prob. 4KTCh. 7 - Prob. 5KTCh. 7 - Prob. 6KTCh. 7 - Prob. 7KTCh. 7 - Prob. 8KTCh. 7 - Prob. 9KTCh. 7 - Prob. 10KTCh. 7 - Prob. 11KTCh. 7 - Prob. 12KTCh. 7 - Prob. 13KTCh. 7 - Prob. 14KTCh. 7 - Prob. 15KTCh. 7 - Prob. 16KTCh. 7 - Prob. 17KTCh. 7 - Prob. 18KTCh. 7 - Prob. 19KTCh. 7 - Prob. 20KTCh. 7 - Prob. 21KTCh. 7 - Prob. 22KTCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - Prob. 59ECh. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Prob. 66ECh. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Prob. 81ECh. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Prob. 86ECh. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 1STCh. 7 - Prob. 2STCh. 7 - Prob. 3STCh. 7 - Prob. 4STCh. 7 - Prob. 5STCh. 7 - Prob. 6STCh. 7 - Prob. 7STCh. 7 - Prob. 8STCh. 7 - Prob. 9STCh. 7 - Prob. 10STCh. 7 - Prob. 11STCh. 7 - Prob. 12STCh. 7 - Prob. 13STCh. 7 - Prob. 14STCh. 7 - Prob. 15STCh. 7 - Prob. 16STCh. 7 - Prob. 17STCh. 7 - Prob. 18ST
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