Chapter 7, Problem 64P

Interpretation Introduction

Interpretation:

The equilibrium constant for a reaction is equal to the ratio of rate constants for the forward and reverse reactions should be verified.

$\text{K}=\frac{k}{k^{\text{'}}}$

Concept Introduction:

The given chemical equilibrium is,

$\text{A + B}\stackrel{k}{\underset{k^{\text{'}}}{◰\hspace{1em}}}\text{C + D}$

Here,

$\text{Rate}\text{constant}k\text{refers}\text{to}\text{the}\text{rate}\text{of}\text{forward}\text{reaction}$

$\text{Rate}\text{constant}{k}^{\text{'}}\text{refers}\text{to}\text{the}\text{rate}\text{of}\text{backward}\text{reaction}$

The equilibrium constant for the above equilibrium will be,

$\text{K=}\frac{\text{[C][D]}}{\text{[A][B]}}$.