The alkyl chloride formed by the reaction of HCl with (CH 3 ) 2 C=CH 2 is to be identified. Concept Introduction: > Alkenes , which have non-identicalsubstituents attached to the double bonded carbon atoms, can form more than one type of carbocations upon protonation. > The more stable carbocation is the one having the more substituents attached to the carbon atom bearing the positive charge. > In general, tertiary carbocations are more stable as compared to secondary and primary carbocations. > Once the carbocation is formed, the halide ion gets attached to the carbon bearing the positive charge, forming the alkyl halide as the product.

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Chapter 7, Problem 64DSP

Interpretation Introduction

Interpretation:

The alkyl chloride formed by the reaction of HCl with (CH3)2C=CH2 is to be identified.

Concept Introduction:
>
Alkenes, which have non-identicalsubstituents attached to the double bonded carbon atoms, can form more than one type of carbocations upon protonation.
>
The more stable carbocation is the one having the more substituents attached to the carbon atom bearing the positive charge.
>
In general, tertiary carbocations are more stable as compared to secondary and primary carbocations.
>
Once the carbocation is formed, the halide ion gets attached to the carbon bearing the positive charge, forming the alkyl halide as the product.

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