The product of the given reaction should be determined. Concept Introduction: Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation. Different reagents are used for the deprotonation and one of the common reagent is sodium amide. NaNH 2 will deprotonate alkynes , alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion. Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product. Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes. P d / C : Hydrogenation can done using this catalyst and converts alkenes to alkanes . The addition will be a syn addition.

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Answer 1

Question

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

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Answer 2

Question

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

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Answer 3

Question

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

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Answer 4

Question

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

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Answer 5

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

Answer 6

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 7

Chapter 7, Problem 57P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Acid Catalysed addition of water: When water is added to alkyne in the presence of an acid, the product formed will be an enol. Enol contains a double bond and an $OH$ group. The $OH$ group is bonded to one of the $sp2$ carbons.

If a carbonyl group is bonded to two alkyl groups, it is called as a ketone. The enol formed in the acid catalysed addition of water will be easily converted into a ketone.

Conversion of terminal alkynes into enol: If we want to convert terminal alkyne into an enol, the presence of mercuric ion as a catalyst should be needed and the catalyst will increase the rate of the reaction.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

Answer 13

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

Answer 14

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 15

(e)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 16

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 17

(f)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 18

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 19

(g)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.

Different reagents are used for the deprotonation and one of the common reagent is sodium amide.

$NaNH2$ will deprotonate alkynes, alcohols and as a strong base it will deprotonate alkynes and produces acetylide ion.

Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.

Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

$Pd/C$ : Hydrogenation can done using this catalyst and converts alkenes to alkanes. The addition will be a syn addition.

Answer 20

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

Answer 21

(h)

Interpretation Introduction

Interpretation:

The product of the given reaction should be determined.

Concept Introduction:

Hydroboration-oxidation reaction:

Internal alkynes oxidize to form ketones.

Terminal alkyne oxidize to form aldehyde.

Reagents used are $BH3 and R2BH$ for internal alkyne.

$R2BH$ is the reagent used for terminal alkynes.

General mechanism for hydroboration oxidation:

Answer 22

Expert Solution & Answer

Answer 23

Expert Solution & Answer

Answer 24

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Answer 25

Ch. 7.1 - What is the molecular formula for a monocyclic...Ch. 7.1 - Prob. 2P Ch. 7.1 - Draw the structure and give the common and...Ch. 7.1 - Prob. 4P Ch. 7.1 - Name the following:Ch. 7.2 - Prob. 6P Ch. 7.2 - Name the following:Ch. 7.3 - Prob. 8P Ch. 7.3 - Why does cis-2-butene have a higher boiling point...Ch. 7.4 - What orbitals are used to form the carbon-carbon ...

Concept explainers

Interpretation:

The product of the given reaction should be determined.

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Chapter 7 Solutions

Concept explainers

Interpretation: The product of the given reaction should be determined.

Want to see the full answer?

Chapter 7 Solutions

Interpretation:

The product of the given reaction should be determined.