Concept explainers
(a)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans
(b)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
(c)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
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Chapter 7 Solutions
Organic Chemistry
- Predict the major products of this reaction: ་ ་ + H NaOH ? Δ excess Note that the second reactant is used in excess, that is, there is much more of the second reactant than the first. If there won't be any products, just check the box under the drawing area instead.arrow_forwardP A student claims the right-hand side of the reaction in the drawing area below shows the product of a Claisen condensation. • If the student is correct, complete the reaction by adding the necessary organic reactants to the left-hand side, and by adding any necessary reagents and reaction conditions above and below the arrow. • If the student is incorrect, because it's not possible to obtain this product from a Claisen condensation, check the box under the drawing area instead. those that will minimize any byproducts or competing • Note for advanced students: If you have a choice, use the most efficient reactants and reagents reactions. - ☐ ☐ : ☐ + I Х Click and drag to start drawing a structure.arrow_forwardidentify the relationship between the structures and H- OH HO H H- OH and HO H H -ОН HO H Br and Brarrow_forward
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Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning